本文系全自动[GAD]齿轮设计软件之内容,限于篇幅,未包含功率部份, 符合ISO.9085 渐开线园柱齿轮标准。 }S')!3[G
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河海大学常州校区 胡瑞生 2009. 10 . 18 eNi#% ?=WB
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本程序适用于: 速比 u < 4, 求取最大功率, 而且 "SQyy
一般不发生切削干涉与啮合干涉。 et/l7+/'
当速比 2 > u > 4 尚需作局部修正 ;w]1H&mc*A
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己知: 产品的工作条件: 中心距 [A`] , 速比 [u] v^Fu/Y
步骤00 1 起步假设 [Z1齿 经验值] }QQl.'
if ( u <=1.25 )Z1 =41.0 *sB'D+-/
if ( u >1.25 .and. u <=1.50 ) Z1 = 37.0 dxZn| Y
if ( u >1.50 .and. u <=1.75 ) Z1 = 33.0 Gl3g.`X{$@
if ( u >1.75.and. u <=2.00 ) Z1 = 28.0 WL'!M&h
if ( u >2.00 .and. u <=2.50 ) Z1 = 25.0 {&D$U'ye
if ( u >2.50 .and. u <=3.00 ) Z1 = 23.0 lB/^
if ( u >3.00 .and. u <=3.50 ) Z1 = 21.0 :@E^oNKa0
if ( u >3.50 .and. u <=4.00)Z1 = 19.0 HfP<hQmN'
if ( u >4.00 .and. u <=4.50 ) Z1 = 18.0 Yc~l Yz+b
if ( u >4.50 .and. u <=5.00) Z1 = 17.0 + `'wY?
if ( u >5.00 .and. u <5.50 )Z1 = 16.0 | a
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if ( u >5.50 .and. u <6.00 )Z1 = 15.0 }uaFmXy3
if ( u >6.00 ) Z1 = 14.0 =s'H o
Z1 = Z1 Zm++5b`W/[
Z2 = int ( Z1 * u +0.50 ) 取整数 l& sEdEA
u = Z2/ Z1 &"T7KXx
齿 数 比[ u] ≡ u GyxLzrp
步骤002起步假设螺旋角 [ β 经验值 ] OtQ]\:p7
if ( u <=1.25 )β= 24.0 o>d0R
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if ( u >1.25 .and. u <=1.50 ) β= 22.0 +"WNG
if ( u >1.50 .and. u <=1.75 ) β= 20.0 "W4|}plnu
if ( u >1.75. and. u <=2.00 ) β= 18.0 S{]3e-?
if ( u >2.00 .and. u <=2.50 ) .β= 16.0 Lr\(7r
if ( u >2.50 .and. u <=3.00 ) β= 14.0 pBBKfv
if ( u >3.00 .and. u <=3.50 ) β= 12.0 n4XkhY|
if ( u >3.50 .and. u <=4.00) β= 11.0 '
Gx\
if ( u >4.00 .and. u <=4.50 ) .β= 10.0 |t3}>+"?z
if ( u >4.50 .and. u <=5.00) β= 10.0 67}8EV!/k
if ( u >5.00 .and. u <5.50 )β= 9.0 S7cD}yx*[
if ( u >5.50 .and. u <6.00 )β= 7.0 A>S7Ap4z>
if ( u >6.00 ) β= 6.0 eW3?3l`fvt
β= bff F8tMZ,:
jtt = Atan ( tand (20) /Cos( bff) ) aWLA6A+C&
压力角 [初值][αt] = jtt 9<P%?Q
步骤003 导出 [Axi] 几何性能综合参数概念 /Hm/%os
令 [Axi] ≡ Cos(αt) / [ 2*Cos(β)*Cos(α`) ] P$AHw;n[R
此系数综合包含螺旋角. 压力角. 啮合角因子, 意义很重要 +@8, uL
中心距 [A`] ≡ Mn *Z1 *(1+u) *Axi (o{x*';i4
常规采用 [V+] 变位体制齿轮 [V-变位制不利于强度] K~^o06 Y
Axi* Cos(β)≥ 0.5; Axi ≥ 0.5 / Cos(β) AOL=;z9c#
β= 5, Axi≥ 0.5019 β=10, Axi≥ 0.5077 7hMh%d0d(_
β=15, Axi≥ 0.5176 β=20, Axi≥ 0.5320 lY,9bSF$
β=22, Axi≥ 0.5392 β=24, Axi≥ 0.5473 ,1<6=vL
故 [Axi]max = 0 .5473, [Axi]min = 0.5019 4-'0# a
步骤004 计算 模 数 sMJa4P>O@
[Mn]min ≌ A`/ ( Z1*(1+u)*0 .5473 ) "av/a
[Mn]max ≌ A`/ ( Z1*(1+u)*0 .5019 ) ,5t_}d|3C=
将模 数化为标 准 值 [Mn]≡,Mn *?Wr^T
[Mn]≡Mn, call Xg (ch,Mn ) 询问满意否 ? -H_#et3&i