# i nclude<stdio.h> )v;>6(
# i nclude<stdio.h> k:s}`h_n
# i nclude<math.h> YQ X+lE
#define PI 3.1415926 {"!V&}
void ydgl(); ~1wAk0G`n
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; ,0NVb7F;k
int f; 2H;&E1:
main() }$#e&&)n
{ printf("Determaination the prime circle of cam\n"); KCJ zE>
printf("----------------------------\n"); @!fy24R]D
printf( "input ro=");scanf("%f",&ro); ,)'!E^n
printf("input h=");scanf("%f",&h); LgRx\*[C*
printf("input e=");scanf("%f",&e); 85$MHod}[,
printf("input dt0=");scanf("%f",&dt0); LP_d}ve
am=0;p=PI/180; 4ao
oBY$
printf("The initial data:ro=%f\n",ro); xr?=gY3E;
printf("h=%f e=%f dt0=%f\n",h,e,dt0); m'Z233Nt"
do ~6.AE/ow
{ro=ro+5; h'^7xDw
for(f=0;f<=dt0;f=f+2) pA3j@w
{d=PI*f/dt0; f}^}d"&F
ydgl(); N~l(ng9'U
} uzG<(Q pu
} ]0by6hQ
while(am>30*p); iI+kZI-
printf("The intermediate results: am=%f\n",am/p); }cgEC-
printf("ro=%f\n",ro); WqqrfzlM
do MHVqRYz
{ro=ro-1; cKh { s
if(ro<e) j/3827jw=
break; \:4WbM:B
v3Tr6[9
for(f=0;f<=dt0;f=f+2) gSEj/?
{d=PI*f/dt0; +`kfcA#pi
ydgl(); ?'CIt5n+\{
} YKf,vHau
} ye KzI~
while((am>30*p)||(am<=29.5*p)); * gr{{c
printf("The final results:max alfa=%f\n",am/p); vrm[sP
printf(" min ro=%f\n",ro); )+wBS3BC
getch(); \E9Z
H3;
} eHF#ME
void ydgl() QUb#;L@okn
{ d0=dt0*p; \v9IbU*js
s=0.5*h*(1-cos(d)); PP/M-Jql)
ds=0.5*h*PI*sin(d)/d0; WG NuB9R
r=sqrt(ro*ro-e*e); V;L^q?v
!
if((s+r)==0) =DvFY]9{
return; QOlm#S
al=atan((ds-e)/(s+r)); zHG
KPuk'
if(al>am) 2al%J%
am=al; Bt[`p\p@
}