# i nclude<stdio.h> a$}mWPp+f
# i nclude<stdio.h> 2u:4$x8
# i nclude<math.h> qm(1:iK,0
#define PI 3.1415926 JBcY!dy-d
void ydgl(); ?~F. /
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; JJf<*j^G
int f; p|VcMxT9-
main() UR3 $B%i
{ printf("Determaination the prime circle of cam\n"); LprM ;Q_
printf("----------------------------\n"); =!<G!^
printf( "input ro=");scanf("%f",&ro); >oqZ !V5[
printf("input h=");scanf("%f",&h); 9]$`)wZ
printf("input e=");scanf("%f",&e); v>-YuS
printf("input dt0=");scanf("%f",&dt0); p&3>
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am=0;p=PI/180; ybvI?#
printf("The initial data:ro=%f\n",ro); I@./${o
printf("h=%f e=%f dt0=%f\n",h,e,dt0); Y60"M4j
do +1@AGJU3
{ro=ro+5; aRwnRii
for(f=0;f<=dt0;f=f+2) Ew4g'A:H
{d=PI*f/dt0; C\Ayv)S#2
ydgl(); Hj~O49%j&
} Lq04T0
} Q}P-$X+/ n
while(am>30*p); E`AYee%l
printf("The intermediate results: am=%f\n",am/p); e@jfIF0=}
printf("ro=%f\n",ro); ;~/4d-
do 4lz{G*u
{ro=ro-1; L[C*@
uK
if(ro<e) Y'N'hRD
break; Y4To@TrN#\
+,_c/(P
for(f=0;f<=dt0;f=f+2) >saI+u'o
{d=PI*f/dt0; 3j*'HST
ydgl(); u~'OcO
} %#k,6;m
} zM59UQU;
while((am>30*p)||(am<=29.5*p)); J}@GKNm
printf("The final results:max alfa=%f\n",am/p); }ND'0*#
printf(" min ro=%f\n",ro); `-O=>U5nH
getch(); IJPgFZ7
} {L9yhYw
void ydgl() (=JueF@J
{ d0=dt0*p; /DU*M,
s=0.5*h*(1-cos(d)); `P.CNYR<J
ds=0.5*h*PI*sin(d)/d0; IVteF*8hU
r=sqrt(ro*ro-e*e); iz`jDa Q|1
if((s+r)==0) p>p'.#M
return; -,GEv%6c
al=atan((ds-e)/(s+r)); E5{n?e
if(al>am) SDc"
4g`
am=al; \_ -DyD#3
}