# i nclude<stdio.h> [t*-s1cq
# i nclude<stdio.h>
BDX>J3h
# i nclude<math.h> dO9bxHMnM
#define PI 3.1415926 _+Uf5,.5yU
void ydgl(); #?Ob->v
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; #9A*B bY
int f; mAe)Hy %
main()
:Z6l)R+V
{ printf("Determaination the prime circle of cam\n"); ~!e(e2
printf("----------------------------\n"); =7S\-{
printf( "input ro=");scanf("%f",&ro); yoTx3U@
printf("input h=");scanf("%f",&h); GwG(?_I"
printf("input e=");scanf("%f",&e); >^v,,R8j
printf("input dt0=");scanf("%f",&dt0); R78P](1\>
am=0;p=PI/180; _1jeaV9@
printf("The initial data:ro=%f\n",ro); 1NAtg*`
printf("h=%f e=%f dt0=%f\n",h,e,dt0); uK[gI6M
do 461p 4)
{ro=ro+5; }9Q<<a
for(f=0;f<=dt0;f=f+2) +1eb@bX
{d=PI*f/dt0; Xx^v%[!`+
ydgl(); +@do<2l]
} 4EhWK;ra
} SPINV.
while(am>30*p); )<T2J0*
printf("The intermediate results: am=%f\n",am/p); Qqp=
printf("ro=%f\n",ro); OV-#8RXJ
do |e2s{J2
{ro=ro-1; tU-jtJ
if(ro<e) >6'brb
break; u}jC$T>2%6
q=k[]vD
for(f=0;f<=dt0;f=f+2) ZRUI';5x
{d=PI*f/dt0; Eq5X/Hx
ydgl(); 9hhYyqGsO
} T6=~vOzTJ
} = Fwzm^}6
while((am>30*p)||(am<=29.5*p)); "gXvnl
printf("The final results:max alfa=%f\n",am/p); >NA{* *$0
printf(" min ro=%f\n",ro); tSiQrI
getch(); D ~NWP%H
} ro^T L
void ydgl() ?T>N vKF
{ d0=dt0*p; :]`JcJ
s=0.5*h*(1-cos(d)); {<2q
ds=0.5*h*PI*sin(d)/d0; (y2P."
r=sqrt(ro*ro-e*e); ZC&4uNUr
if((s+r)==0) (=tu~ ^
return; 9YwS"~Q =w
al=atan((ds-e)/(s+r)); 6/|"y
if(al>am) 21~~ =+)X
am=al; i]0$7s9!
}