# i nclude<stdio.h> ,b&hLht
# i nclude<stdio.h> o+}k$i!6
# i nclude<math.h> +B1&bOb
#define PI 3.1415926 V4NQcy?
H
void ydgl(); O=V_7I5
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; +a^gC
int f; hHmm(~5gR
main() gN/>y1{a
{ printf("Determaination the prime circle of cam\n"); >h\u[I$7
printf("----------------------------\n"); ~WTk X(\
printf( "input ro=");scanf("%f",&ro); GJZjQH-#P
printf("input h=");scanf("%f",&h); 3: WEODV2
printf("input e=");scanf("%f",&e); ("t'XKP&N
printf("input dt0=");scanf("%f",&dt0); #:0-t!<0C
am=0;p=PI/180; aIFlNS,y
printf("The initial data:ro=%f\n",ro); `j@1]%&z
printf("h=%f e=%f dt0=%f\n",h,e,dt0); w-e{_R
do |@'O3KA
{ro=ro+5; r!dWI
for(f=0;f<=dt0;f=f+2) z,ERq,g+L
{d=PI*f/dt0; <fG\J
ydgl(); H}5WglV.
} tF}^
} :K]7(y7>
while(am>30*p); '7el`Ff
printf("The intermediate results: am=%f\n",am/p); p>+9pxx~U
printf("ro=%f\n",ro); K2yNIq_
do aH{)|?
{ro=ro-1; g assOd
if(ro<e) ^_|kEvk0
break; eNK
+)<PK(
X2Z)>
10
for(f=0;f<=dt0;f=f+2) }q@#M8 b
{d=PI*f/dt0; 30uPDDvar
ydgl(); K us=.(
} <A)M^,#o
} o=($'(1
while((am>30*p)||(am<=29.5*p)); uB.kkkGZ M
printf("The final results:max alfa=%f\n",am/p); }Cu[x'J
printf(" min ro=%f\n",ro); Xj/z),
getch(); Lcpe*C x-
} {owuYVm
void ydgl() vHpw?(]
{ d0=dt0*p; N5=BjXSAg
s=0.5*h*(1-cos(d)); `R8&(kQ
ds=0.5*h*PI*sin(d)/d0; K#wA ;
r=sqrt(ro*ro-e*e); R*D<M3
if((s+r)==0) )Q
=>7%ZA
return; (8h4\utA
al=atan((ds-e)/(s+r)); @!f4>iUy
if(al>am) l(sVnhL6h
am=al; _=s9o/Cn]
}