# i nclude<stdio.h> 5I(gP
# i nclude<stdio.h> E?/Bf@a28=
# i nclude<math.h> B[R1XpB7
#define PI 3.1415926 ,:!dqonn
void ydgl(); N>$Nw<wV
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; +R_w- NI
int f; u\-f\Z7
main() Kpo{:a
{ printf("Determaination the prime circle of cam\n"); Y:0SrB!\
printf("----------------------------\n"); XNU[\I
printf( "input ro=");scanf("%f",&ro); Yy"05V.
printf("input h=");scanf("%f",&h); 9rn[46s`
printf("input e=");scanf("%f",&e); ?`oCc[hY
printf("input dt0=");scanf("%f",&dt0); u}7#3JfLn
am=0;p=PI/180; B0^0d*8t|@
printf("The initial data:ro=%f\n",ro); 'b*
yYX<
printf("h=%f e=%f dt0=%f\n",h,e,dt0); [ Yzh(a8
do '14
G0<;yL
{ro=ro+5; _"PTO&E
for(f=0;f<=dt0;f=f+2) lF\oEMd*
{d=PI*f/dt0; poqx
O
ydgl(); Xh,{/5m
} ~8-Z=-
} }lk_Oe1
while(am>30*p); ^/3R/;?
printf("The intermediate results: am=%f\n",am/p); ^]$x/1I;
printf("ro=%f\n",ro); )k.[Ve
do rmW,#
{ro=ro-1; \wxS~T<&L
if(ro<e) T>&d/$;]
break; -
T,;Fr'
K>h=
for(f=0;f<=dt0;f=f+2) D! 1oYr
{d=PI*f/dt0; O6^>L0'
ydgl(); T
#&9|
} t&SC>8M<
} pr8eRV!x
while((am>30*p)||(am<=29.5*p)); ?Mg&e/^
printf("The final results:max alfa=%f\n",am/p); >5&'_
printf(" min ro=%f\n",ro); );wSay>%(
getch(); $T\z
} 3%]%c6
void ydgl() gp:,DC?(
{ d0=dt0*p; Zu\(XN?62
s=0.5*h*(1-cos(d)); W27EU/+3
ds=0.5*h*PI*sin(d)/d0; *v[WJ"8@
r=sqrt(ro*ro-e*e); *7Ct#GC
if((s+r)==0) 8'Z#sM^E
return; c|lo%[]R!
al=atan((ds-e)/(s+r)); ngprTMO$&
if(al>am) dyRKmLb
am=al; [a;U'v*
}