# i nclude<stdio.h> ?5F;4oR2g
# i nclude<stdio.h> V."cmtf
# i nclude<math.h> di7cCn
#define PI 3.1415926 \+&)9 !K
void ydgl(); 5mZwg(si
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; 'j!n
int f; j%}9tM6[
main() ])q,mH
{ printf("Determaination the prime circle of cam\n"); >_$_fB
printf("----------------------------\n"); 3J8M0W
printf( "input ro=");scanf("%f",&ro); O\6gw$
printf("input h=");scanf("%f",&h); 7Hj7b:3K&!
printf("input e=");scanf("%f",&e); 5W=Jn?y2
printf("input dt0=");scanf("%f",&dt0); iiWpmE<,
am=0;p=PI/180; UID`3X
printf("The initial data:ro=%f\n",ro); w O6>jW
7
printf("h=%f e=%f dt0=%f\n",h,e,dt0); S,Q(,e^&
do 7Sh1QDYZ
{ro=ro+5; X~/-,oV=A
for(f=0;f<=dt0;f=f+2) $GHi9aj_P
{d=PI*f/dt0; 8"p rWAN
ydgl(); \f=kQbM
} / %iS\R%ca
} '8FHn~F
while(am>30*p); Spn)M79
printf("The intermediate results: am=%f\n",am/p); b|iIdDK
printf("ro=%f\n",ro); +|x%a2?x:
do LBmXy8'T`
{ro=ro-1; L[<CEk
if(ro<e) TI\EkKu"
break; ?{xD{f$
DyA1zwp}
for(f=0;f<=dt0;f=f+2) irP*:QM
{d=PI*f/dt0; [
$"
ydgl(); b
`bg`}x
} nB]mj_)R^
}
m3^D~4
while((am>30*p)||(am<=29.5*p)); FlY"OU*
printf("The final results:max alfa=%f\n",am/p); 1QnaZhu'
printf(" min ro=%f\n",ro); Z v*uUe
getch(); [Dmf.PUe
} N vTp1kI]
void ydgl() T0.sL9
{ d0=dt0*p; ooP{Q r
s=0.5*h*(1-cos(d)); J25/Iy*byG
ds=0.5*h*PI*sin(d)/d0; if3z Fh
r=sqrt(ro*ro-e*e); Om_ "X6
if((s+r)==0) -Owb@Nw
return; 5=}CZYWB
al=atan((ds-e)/(s+r)); `:jF%3ks+0
if(al>am) Lr(JnS
am=al; }5}>B *
}