# i nclude<stdio.h> NfqJ=9
# i nclude<stdio.h> oN ;-M-(
# i nclude<math.h> m{O
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#define PI 3.1415926 )r#,ML
void ydgl(); 6kR
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float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; SctJxY(}!
int f; $E @ouX?
main() RUqO!s~#rY
{ printf("Determaination the prime circle of cam\n"); n{$}#NdV
printf("----------------------------\n"); lJlhl7
printf( "input ro=");scanf("%f",&ro); wBE7Bv45
printf("input h=");scanf("%f",&h); OOfyGvs
printf("input e=");scanf("%f",&e); }pKv.
printf("input dt0=");scanf("%f",&dt0); ~W3:xnBEk
am=0;p=PI/180; l-cW;b~
printf("The initial data:ro=%f\n",ro); 8XlU%a6x
printf("h=%f e=%f dt0=%f\n",h,e,dt0); X*)?LxTj
do uct=i1+ fE
{ro=ro+5; ?0uOR*y'
for(f=0;f<=dt0;f=f+2) wePI*."]
{d=PI*f/dt0; /Bh>
ydgl(); 3jXR"@Z-
} Enu!u~1]F
} \Vz,wy%-
while(am>30*p); pbPz$Y
printf("The intermediate results: am=%f\n",am/p); FN>L7
*,0
printf("ro=%f\n",ro); 7oD
y7nV4
do ^K"ZJ6?+1
{ro=ro-1; rykj2/O
if(ro<e) f&f`J/(
break; JBvk)ogM
\FVNXUMU
for(f=0;f<=dt0;f=f+2) *^uGvJXF
{d=PI*f/dt0; CX]RtV!
ydgl(); ma1(EJ/
} %n4@[fG%K
} p%tE v
while((am>30*p)||(am<=29.5*p)); K[*h+YO
printf("The final results:max alfa=%f\n",am/p); [;*\P\Xih
printf(" min ro=%f\n",ro); +)?, {eE|
getch(); 'frWu6]<
4
} 7&h\l6}Yh
void ydgl() xm^N8
{ d0=dt0*p; ::v;)VdX+*
s=0.5*h*(1-cos(d)); l},dQ4R
ds=0.5*h*PI*sin(d)/d0; Wux 0RF&
r=sqrt(ro*ro-e*e); )4@M`8
if((s+r)==0) Y$>+U
return; *3!(*F@M,
al=atan((ds-e)/(s+r)); hK
Fk$A
if(al>am) NWw<B3aL
am=al; Ih(:HFRMq6
}