# i nclude<stdio.h> q5DEw&UZJ
# i nclude<stdio.h> sD;M!K_
# i nclude<math.h> zp}eLm:=d
#define PI 3.1415926 8'
DW#%
void ydgl(); !69&Ld
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; I:98 $ r$
int f; $g0+,ll[6
main() o 5U(i
{ printf("Determaination the prime circle of cam\n"); KqY["5p
printf("----------------------------\n"); Fh$slow4!
printf( "input ro=");scanf("%f",&ro); KngTc(^_D
printf("input h=");scanf("%f",&h); 3?I;ovsM
printf("input e=");scanf("%f",&e); ]}|byo
printf("input dt0=");scanf("%f",&dt0); dt@P>rel
am=0;p=PI/180; ,f3pqi9|
printf("The initial data:ro=%f\n",ro); "Jq8?FoT
printf("h=%f e=%f dt0=%f\n",h,e,dt0); O^Q7b7}y
do hj%ye~|~
{ro=ro+5; !9Z r;K~\
for(f=0;f<=dt0;f=f+2) 1\*\?\T>_
{d=PI*f/dt0; F,BOgWwP
ydgl(); <EO$]>;0
} FY{e2~gi
} GzXUU@p
while(am>30*p); CAq/K?:8
printf("The intermediate results: am=%f\n",am/p); 8Me:Yp_Xt
printf("ro=%f\n",ro); YHkcWz
do {%lXY Myu
{ro=ro-1; K.<.cJE
if(ro<e) i<kD
break; L!0OC''C
&s Pq<l o
for(f=0;f<=dt0;f=f+2) x+ncc_2n&D
{d=PI*f/dt0; )c n+1R
ydgl(); KqBk~-G
} xsd_Uu*
} y&}E~5O
while((am>30*p)||(am<=29.5*p)); ('wY9kvL&
printf("The final results:max alfa=%f\n",am/p); <h%O?mkC
printf(" min ro=%f\n",ro); poGc a1
getch(); Nkxmm/Z
} ;<yd^Xs
void ydgl() m8'C_U^89
{ d0=dt0*p; :I -V_4b
s=0.5*h*(1-cos(d)); `>0MNmu
ds=0.5*h*PI*sin(d)/d0; fkf1m:Ckh
r=sqrt(ro*ro-e*e); +zXEYc
if((s+r)==0) f Vb-$
return; x~xa6
al=atan((ds-e)/(s+r)); 'WaPrCw@Mf
if(al>am) +fvaUV_-
am=al; l^ZI* z7N
}