# i nclude<stdio.h> ? HNuffk
# i nclude<stdio.h> SSbx[<E3
# i nclude<math.h> ,j9? 9Z7R
#define PI 3.1415926 uL@%M8n
void ydgl(); ,L.V>Ae
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; `KE]RTq
int f; ]5K(}95&'
main() dz>Jl},`k
{ printf("Determaination the prime circle of cam\n"); ZR-64G=L,
printf("----------------------------\n"); ^ fyue~9u
printf( "input ro=");scanf("%f",&ro); 34[TM 3L].
printf("input h=");scanf("%f",&h); T$AVMVq
printf("input e=");scanf("%f",&e); ]T&d_~l
printf("input dt0=");scanf("%f",&dt0); kwqY~@W
am=0;p=PI/180; hg:$H9\%
printf("The initial data:ro=%f\n",ro); (2QfH$HEk
printf("h=%f e=%f dt0=%f\n",h,e,dt0); VXlAK(
do GKOl{och
{ro=ro+5; BX6kn/i
for(f=0;f<=dt0;f=f+2) Hq,@j{($
{d=PI*f/dt0; Sv0?_3C
ydgl(); hF5T9^8
}
>@ xe-0z
} !*HJBZ]q
while(am>30*p); Yh;(puhyA
printf("The intermediate results: am=%f\n",am/p); NQ;$V:s)
printf("ro=%f\n",ro); <2]D3,.g.
do C^5 V
{ro=ro-1; (;^>G[
if(ro<e) 6$f\#TR
break; 1
?Zw
Ziub%C[oV
for(f=0;f<=dt0;f=f+2) zUNUH^Il
{d=PI*f/dt0; ,nCvA%B!
ydgl(); u??ti
OK{
} ~(yW#'G
} 6O.kKhk
while((am>30*p)||(am<=29.5*p)); Ctn?O~u
printf("The final results:max alfa=%f\n",am/p); e=s85!
printf(" min ro=%f\n",ro); XJKns
getch(); r\FZ-gk}Q
} _Y/*e<bU
void ydgl() 2K
o]Q_,~
{ d0=dt0*p; 3&5b!Y
s=0.5*h*(1-cos(d)); ZZHzC+O#^
ds=0.5*h*PI*sin(d)/d0; 12hD*,A5j
r=sqrt(ro*ro-e*e); q8-hbWNm4
if((s+r)==0) -Ah&|!/
return; 8O(L;&h
al=atan((ds-e)/(s+r)); @D=%J!!*
if(al>am) 6>;OVX
am=al; zK1]o-wSAT
}