# i nclude<stdio.h> /ygUd8@
# i nclude<stdio.h> zJy 89ib'
# i nclude<math.h> w]o:c(x@
#define PI 3.1415926 T>%uRK$
void ydgl(); Ru
vG1"
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; _Cv[`e.
int f; dCoi>PO
main() NE;(..
{ printf("Determaination the prime circle of cam\n"); a.Rp#}f
printf("----------------------------\n"); ZZ]OR;8
printf( "input ro=");scanf("%f",&ro); ={mPg+Ei'
printf("input h=");scanf("%f",&h); t]u(jX)
printf("input e=");scanf("%f",&e); Pt PGi^
printf("input dt0=");scanf("%f",&dt0); Ul$X%
am=0;p=PI/180; lt2Nwt0bv
printf("The initial data:ro=%f\n",ro); G+ $)W
u
printf("h=%f e=%f dt0=%f\n",h,e,dt0); !"Oj$c
-
do 5ykk11!p$
{ro=ro+5; %/6e"o
for(f=0;f<=dt0;f=f+2) Gw\G+T?M-
{d=PI*f/dt0; SSL%$:l@
ydgl(); HYI1 o/}
} Zs3]|bUR
} MoKXl?B<
while(am>30*p); S}v{^vR
printf("The intermediate results: am=%f\n",am/p); L?D~~Jb
printf("ro=%f\n",ro); |`94W j<
do <mo^Y k3
{ro=ro-1; p~d)2TC4#
if(ro<e) {>UMw>T[
break; Jc"$p\ $-
E-tNB{r@
for(f=0;f<=dt0;f=f+2) ?ck^? p7
{d=PI*f/dt0; qy42Y/8'
ydgl(); +SuUI-.
} rmg";(I
} ax{-Qi7z-+
while((am>30*p)||(am<=29.5*p)); ,Zcx3C:#
printf("The final results:max alfa=%f\n",am/p); \@PUljU]
printf(" min ro=%f\n",ro); H s4zJk
getch(); \HP,LH[P:
} pRxlvVt
void ydgl() %:be{Y6
{ d0=dt0*p; YCB 3
s=0.5*h*(1-cos(d)); V=l Q}sBY
ds=0.5*h*PI*sin(d)/d0; ev;5?9\E
r=sqrt(ro*ro-e*e); 'De'(I
if((s+r)==0) wJeqa
return; {HRxyAI!
al=atan((ds-e)/(s+r)); G5QgnxwP2
if(al>am) C_^R_
am=al; ".Deu|>
}