# i nclude<stdio.h> @(k}q3b<
# i nclude<stdio.h> q#}#A@Rg
# i nclude<math.h> tXlo27J
#define PI 3.1415926 H);O. m
void ydgl(); dS+/G9X^
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; ;;A8*\*$
int f; *OoM[wEY
main() w]<a$C8*y:
{ printf("Determaination the prime circle of cam\n"); iR_j
h=2{
printf("----------------------------\n"); /&PRw<}>_o
printf( "input ro=");scanf("%f",&ro); ar+ j`QIe
printf("input h=");scanf("%f",&h); 16;r+.FB'
printf("input e=");scanf("%f",&e); (4;m*'X
printf("input dt0=");scanf("%f",&dt0); NI^=cN,l
am=0;p=PI/180; "4`i]vy8
printf("The initial data:ro=%f\n",ro); ]VuB2L[D
printf("h=%f e=%f dt0=%f\n",h,e,dt0); 2h_XfY'3pX
do \w;d4r8x
{ro=ro+5; 25:[VH$:4
for(f=0;f<=dt0;f=f+2) xEULV4Qw
{d=PI*f/dt0; MM+x}g.?
ydgl(); U-b(
} nU^ -D1s{
} {>x6SVF
while(am>30*p); J(0E'o{ug
printf("The intermediate results: am=%f\n",am/p); S-^:p5{r
printf("ro=%f\n",ro); 9FGe(t<
do 1=*QMEv1G
{ro=ro-1; q?&Ap*
if(ro<e) o#p{0y
break; bSG}I|
8Uv2p{ <#
for(f=0;f<=dt0;f=f+2) yniXb2iM
{d=PI*f/dt0; T+a\dgd
ydgl(); BVJ6U[h`
} /b|V=j}W
} <./r%3$;7
while((am>30*p)||(am<=29.5*p)); IdHydY1
printf("The final results:max alfa=%f\n",am/p); 5c8tH=
printf(" min ro=%f\n",ro); *h <_gn
getch(); F rKI=8
} j=q*b Qr
void ydgl() xJ&E2Bf
{ d0=dt0*p; 4lVvs(W?
s=0.5*h*(1-cos(d)); H}ie D"T_
ds=0.5*h*PI*sin(d)/d0; sxP1.= W
r=sqrt(ro*ro-e*e); >ocDh~@aP
if((s+r)==0) Lm!/iseGv
return; x>C_O\
al=atan((ds-e)/(s+r)); ;?q>F3n
if(al>am) iJ-z&=dOe
am=al; ekR/X
}