# i nclude<stdio.h> 0-OKbw5%=b
# i nclude<stdio.h> 3W ]zLUn
# i nclude<math.h> 5fs,UH
#define PI 3.1415926 pno}`Cer
void ydgl(); hc$m1lLn
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; C!547(l[
int f; U`N?<zm<oO
main() CUTjRWQ
{ printf("Determaination the prime circle of cam\n"); ((AK7hb
printf("----------------------------\n"); f3,LX]zKA
printf( "input ro=");scanf("%f",&ro); RJ3uu NK7
printf("input h=");scanf("%f",&h); | J'k9W"
printf("input e=");scanf("%f",&e); ,c&t#mu*0
printf("input dt0=");scanf("%f",&dt0); >&>EjK4?
am=0;p=PI/180; p4O[X\T
printf("The initial data:ro=%f\n",ro); <%^WZ:c
printf("h=%f e=%f dt0=%f\n",h,e,dt0);
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do 0 -M i
q
{ro=ro+5; b!MN QGs
for(f=0;f<=dt0;f=f+2)
d8 ~%(I9
{d=PI*f/dt0; GLub5GrxR
ydgl(); zGme}z;1@
} YG?4DF
} bCTN^
while(am>30*p); LIJ#nb
printf("The intermediate results: am=%f\n",am/p); V*?QZ;hCP
printf("ro=%f\n",ro); 'G[G;?F
do nIlx?(=pu
{ro=ro-1; w"D1mI!L
7
if(ro<e) Y]~-S
break; xIc||o$
2xi;13?
for(f=0;f<=dt0;f=f+2) EGFP$nvq
{d=PI*f/dt0; :SwA) (1
ydgl(); ,6^Xn=o #
} VNz?e&>
} 7uUq+dp
while((am>30*p)||(am<=29.5*p)); O.Te"=^"F
printf("The final results:max alfa=%f\n",am/p); g"!cO^GkT
printf(" min ro=%f\n",ro); TXd6o=
getch(); EAr;
} ~T9QpL1OJ
void ydgl() [Djx@x
{ d0=dt0*p; >^W6'Q$P<
s=0.5*h*(1-cos(d)); TWRnty-C
ds=0.5*h*PI*sin(d)/d0; n<)A5UB5-
r=sqrt(ro*ro-e*e); FP y}Wc*UA
if((s+r)==0) GM8>u O
return; MdEds|D
al=atan((ds-e)/(s+r)); LH`$<p2''r
if(al>am) ETX>wZ
am=al; O\oRM2^u}
}