# i nclude<stdio.h> N'|zPFk g
# i nclude<stdio.h> 8h-6;x^^
# i nclude<math.h> Hd6Qy {,*-
#define PI 3.1415926 eEupqOF*:W
void ydgl(); C %y AMQ
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; 5U%u S^%DP
int f; 0=7C-A1(D
main() ;nSaZ$`5
{ printf("Determaination the prime circle of cam\n"); .(nq"&u-*
printf("----------------------------\n"); v5 $"v?PT
printf( "input ro=");scanf("%f",&ro); L}x"U9'C
printf("input h=");scanf("%f",&h); a&4>xZU #
printf("input e=");scanf("%f",&e); jb fMTb4
printf("input dt0=");scanf("%f",&dt0); =as ]>?<
am=0;p=PI/180; kLADd"C
printf("The initial data:ro=%f\n",ro); L 'H1\'
o
printf("h=%f e=%f dt0=%f\n",h,e,dt0); ,,b_x@y*
do T? _$
{ro=ro+5; 3| g'1X}
for(f=0;f<=dt0;f=f+2) ^vJ 08gu_W
{d=PI*f/dt0; WWH T;ST
ydgl(); d v"
} y7$e7~}/
} LYv+Sv
while(am>30*p); Y
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printf("The intermediate results: am=%f\n",am/p); bWG}>{fj
printf("ro=%f\n",ro); 44($a9oa2
do `{8Sr)
{ro=ro-1; K|E}Ni
if(ro<e) h}rrsVj3
break; p*n$iroy_{
'I*F(4x
for(f=0;f<=dt0;f=f+2) ]={ :VsnL
{d=PI*f/dt0; $Ob]JAf}
ydgl(); IiS1ubNtZ
} nEyP Nm )
} 5|wQeosXxI
while((am>30*p)||(am<=29.5*p)); c"77<Db$
printf("The final results:max alfa=%f\n",am/p); C&K%Q3V
printf(" min ro=%f\n",ro); <iv9Mg}
getch(); FL"I PX;S
} 1 NLawi6
void ydgl() " EQ}xj
{ d0=dt0*p; r]"
>
s=0.5*h*(1-cos(d)); |4x&f!%m
ds=0.5*h*PI*sin(d)/d0; 3zMmpeq
r=sqrt(ro*ro-e*e); qS+'#Sn
if((s+r)==0) fh:=ja?bM3
return; L&q~5 9
al=atan((ds-e)/(s+r)); ;@
%~eIlu
if(al>am) 31<hn+pE &
am=al; R qOEQ*k
}
