# i nclude<stdio.h> <9ifPSvJ
# i nclude<stdio.h> %idk@~H Cg
# i nclude<math.h> D.*>;5:0'
#define PI 3.1415926 Ld(NhB'7
void ydgl(); %0XvJF)s
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; B:9.e?t
int f; *)> do
L
main() 5v9Vk`3'
{ printf("Determaination the prime circle of cam\n"); `,Orf ZMb
printf("----------------------------\n"); .Yx_:h=u
printf( "input ro=");scanf("%f",&ro); J%Mnjk^_\S
printf("input h=");scanf("%f",&h); HY)ESU
!
printf("input e=");scanf("%f",&e); ]sj0~DI*m
printf("input dt0=");scanf("%f",&dt0); V1<`%=%_W
am=0;p=PI/180; 6D/ '`
printf("The initial data:ro=%f\n",ro); KcXpH]>!9
printf("h=%f e=%f dt0=%f\n",h,e,dt0); c2<,|D|
do 2z\;Q8g){r
{ro=ro+5; G7-!`-Nk
for(f=0;f<=dt0;f=f+2) ?)i1b\4Go
{d=PI*f/dt0; -BhTkoN)
ydgl(); qLjT.7 .x
} \##5O7/1
} eVt1d2.O
while(am>30*p); !wh&>3~
printf("The intermediate results: am=%f\n",am/p); 5=Lq=,K$
printf("ro=%f\n",ro); q;A;H)?g
do V'StvU
{ro=ro-1; _x % 1 F
if(ro<e) ]b}B2F'n
break; =u|~
<zQw
8_Z/ o5s
for(f=0;f<=dt0;f=f+2) YBjdp=als
{d=PI*f/dt0; V3.t;.@
ydgl(); \dkOK`)b
} keCRvl Z4
} Cs1>bpY*R6
while((am>30*p)||(am<=29.5*p)); kso*} uh0
printf("The final results:max alfa=%f\n",am/p); 97LpY_sU
printf(" min ro=%f\n",ro); ]vo_gKZ
getch(); 4~|<`vqN
} SY
_='9U
void ydgl() /Ox)|)l
{ d0=dt0*p; 91d },Mq:
s=0.5*h*(1-cos(d)); .\)A@ua^
ds=0.5*h*PI*sin(d)/d0; 'HaD~pa
r=sqrt(ro*ro-e*e); kGHC]Fb)
if((s+r)==0) j[e,?!8;
return; v?j!&d>
al=atan((ds-e)/(s+r)); ([LIjaoi
if(al>am) R$6qoqv{yG
am=al; "JT;gaEm
}