# i nclude<stdio.h> U ;gp)=JNT
# i nclude<stdio.h> KjYDFrR4
# i nclude<math.h> JS7dsO0;
#define PI 3.1415926 &<h?''nCy
void ydgl(); k1i Lnza%
float d,am,ro,e,h,p,dt0,d0,s,ds,r,al; t/ eo]
int f; gj ;@?o0
main() T} 8CfG_ j
{ printf("Determaination the prime circle of cam\n"); o? dR\cxj
printf("----------------------------\n"); q?i Cc c
printf( "input ro=");scanf("%f",&ro); oD,C<[(p
printf("input h=");scanf("%f",&h); kY!C_kFcn
printf("input e=");scanf("%f",&e); Tc_do"uU
printf("input dt0=");scanf("%f",&dt0); T6=-hA^A
am=0;p=PI/180; w_H2gaQ
printf("The initial data:ro=%f\n",ro); hVZo"XUb
printf("h=%f e=%f dt0=%f\n",h,e,dt0); %uuH^ A
do tgW kX
{ro=ro+5; N 8}lt
for(f=0;f<=dt0;f=f+2) [<Jp#&u6sb
{d=PI*f/dt0; k<O y %+C
ydgl(); *(nJX.7
} ^j iE9k)
} -fPT}v
while(am>30*p); {Zwf..,
printf("The intermediate results: am=%f\n",am/p); LE| <O
printf("ro=%f\n",ro); 4d-q!lR pa
do fz8h]PZ
{ro=ro-1; 5Hy3\_ +
if(ro<e) Y?t2,cm
break; 4 cB &Hk
+"Ub/[J{G1
for(f=0;f<=dt0;f=f+2) `WlH*p)z9
{d=PI*f/dt0; C9pnU,[
ydgl(); |h D~6a
} @T/q d>T o
} Um'Ro 4
while((am>30*p)||(am<=29.5*p)); , QA9k$`
printf("The final results:max alfa=%f\n",am/p); 9'X@@6b*'
printf(" min ro=%f\n",ro); U/ 5$%0)
getch(); N"~ qoJO
} E [*0Bo]
void ydgl() YM8rJ-
{ d0=dt0*p; D&f!( n
s=0.5*h*(1-cos(d)); 1b+h>.gWar
ds=0.5*h*PI*sin(d)/d0; b-4dsz 'ai
r=sqrt(ro*ro-e*e); ,P~QS
if((s+r)==0) ) H+d.Y
return; "?[7#d])
al=atan((ds-e)/(s+r)); kkL(;H:%
if(al>am) N5ci};?
am=al; L,W:,i/C
}
