ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ `@eo <6
一下是我的Prescription Data数据： m22M[L(q
GENERAL LENS DATA: |d\ rCq >
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Surfaces : 3 ~?TG SD@(
Stop : 1 HQl hT
System Aperture : Object Space NA = 0.12 lL_M=td8W
Glass Catalogs : Schott Cg[]y1Ne
Ray Aiming : Paraxial Reference, Cache On %upnXRzw
X Pupil shift : 0 0O+[z9
Y Pupil shift : 0 p_T>"v
Z Pupil shift : 0 22lC^)`TE
Apodization : Gaussian, factor = 1.00000E+000 mVFz[xI
************************************************************* $ K1 /^
Effective Focal Length : 1.639158 (in air at system temperature and pressure) `\LhEnIwu
Effective Focal Length : 1.639158 (in image space) "X4L+] "$g
************************************************************* ZS[(r-)$F
Back Focal Length : -1.061568 Blv!%es
Total Track : 4.318 v3SH+Ej4
Image Space F/# : 3.417255 !pY=\vK;
Paraxial Working F/# : 2.950535 [!9 dA.tF
Working F/# : 2.961912 <>\s#Jf/
Image Space NA : 0.1670788 -{H; w=9
Object Space NA : 0.12 "e. Q iK
Stop Radius : 0.2398355 C;7?TZ&x w
Paraxial Image Height : 0 DtkY;Yl
Paraxial Magnification : 0 n 46A
Entrance Pupil Diameter : 0.4796709 )QS4Z{)U
Entrance Pupil Position : 0 k{_ Op/k}V
Exit Pupil Diameter : 2.511155 %%J)@k^vH
Exit Pupil Position : 7.420935 ? ->:,I=<~
Field Type : Angle in degrees -+fb K/
Maximum Field : 0 I`Goc!5t
Primary Wave : 1.31 xE%1C6~C<
Lens Units : Millimeters _cr a_(b
Angular Magnification : 0 Z^? 1MJ:`
M , qX
Fields : 1 ,'[&" Eg
Field Type: Angle in degrees |tL57Wu93
# X-Value Y-Value Weight I L d RN
1 0.000000 0.000000 1.000000 Us4J[MW<
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Vignetting Factors Fl{:aq "3
# VDX VDY VCX VCY VAN wcGI2aflD
1 0.000000 0.000000 0.000000 0.000000 0.000000 jS a9UD
Cw`8[)=}o
Wavelengths : 1 3k)W0]:|<
Units: Microns sjh> i>t
# Value Weight WmU5YZ(mAq
1 1.310000 1.000000 -< rQOPH %
>s#[dr\ww
CARDINAL POINTS: h%'4V<V
eZDqW)x
Object space positions are measured with respect to surface 1. 0ox
8_l
Image space positions are measured with respect to the image surface. E({+2}=1
The index in both the object space and image space is considered. O^fg~g X
52+;j[ ]/O
Object Space Image Space e.pm`%5bO
W = 1.310000 (Primary) R? aE:\A
************************************************************ 6u-@_/O5R3
Focal Length : -1.639015 1.639015 ]L0GIVI E
************************************************************ q-c9YOz _
Focal Planes : 0.313078 -1.159568 aq-`Bar
Principal Planes : 1.952094 -2.798584 #hinb[fQ
Anti-Principal Planes : -1.325937 0.479447 J6 x#c`Y
Nodal Planes : 1.952094 -2.798584 fQ>=\*b9x^
Anti-Nodal Planes : -1.325937 0.479447 5~(.:R X:q
Cj~45)r
我用*号，标出了需要注意的地方，请高手指教！
