ZEMAX中priscription data会给出系统的许多有用的数据,其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致,这时怎么回事? wOs t).
一下是我的Prescription Data数据: zM2_z
GENERAL LENS DATA: |kh7F0';"
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Surfaces : 3 j NkobJ1
Stop : 1 B0|!s
System Aperture : Object Space NA = 0.12 %,Lv},%Y
Glass Catalogs : Schott &*8_ w-
Ray Aiming : Paraxial Reference, Cache On rki0! P`
X Pupil shift : 0 <3C/t|s
Y Pupil shift : 0 ~"nF$DB
Z Pupil shift : 0 ?]PE!7H
Apodization : Gaussian, factor = 1.00000E+000 TNkvdE-S
************************************************************* )4e?-?bK!
Effective Focal Length : 1.639158 (in air at system temperature and pressure) <S68UN(Ke
Effective Focal Length : 1.639158 (in image space) jWqjGX`
************************************************************* kqQT^6S
Back Focal Length : -1.061568 6,a:s:$>}R
Total Track : 4.318 +Fa!<txn
Image Space F/# : 3.417255 (]N- HN]v
Paraxial Working F/# : 2.950535 M2lvD&
Working F/# : 2.961912 G[$g-NU+
Image Space NA : 0.1670788 :kQydCuK
Object Space NA : 0.12 f O ,5
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Stop Radius : 0.2398355 N`et]'_A}
Paraxial Image Height : 0 ;9$71E
Paraxial Magnification : 0 Xli$4 uL
Entrance Pupil Diameter : 0.4796709 zy(NJ
Entrance Pupil Position : 0 &OsO _F
Exit Pupil Diameter : 2.511155 3>QkO.b
Exit Pupil Position : 7.420935 +^|_vq^XR
Field Type : Angle in degrees _9:r4|S
Maximum Field : 0 G4]( !f!Kv
Primary Wave : 1.31 3t9Weo)
Lens Units : Millimeters y~n1S~5cI
Angular Magnification : 0 .bY
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Fields : 1 YpI|=mv
Field Type: Angle in degrees zd|n!3;
# X-Value Y-Value Weight 0TWd.+
1 0.000000 0.000000 1.000000 #f<3[BLx
5Ky(C6E$s
Vignetting Factors T:Nc^QP|tm
# VDX VDY VCX VCY VAN 49.B!DqQW&
1 0.000000 0.000000 0.000000 0.000000 0.000000 LyH1tF
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Wavelengths : 1 pZz\o
Units: Microns 4-m6e$p;
# Value Weight AVi&cvhs
1 1.310000 1.000000 lFl(Sww!\
8W Etm}
CARDINAL POINTS: ! k 1 Ge+
YS:p(jtd
Object space positions are measured with respect to surface 1. F3[,6%4v
Image space positions are measured with respect to the image surface. g%<n9AUl
The index in both the object space and image space is considered. F1meftK
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Object Space Image Space Y>6N2&Q
W = 1.310000 (Primary) !<24Cy
************************************************************ X|-[i hp;
Focal Length : -1.639015 1.639015 Y (pUd3y
************************************************************ S5V:H Rj{?
Focal Planes : 0.313078 -1.159568 5] LfJh+"n
Principal Planes : 1.952094 -2.798584 m?kyAW'|
Anti-Principal Planes : -1.325937 0.479447 hd6O+i
Y4
Nodal Planes : 1.952094 -2.798584 !2h ZtX
Anti-Nodal Planes : -1.325937 0.479447 k.z(.uc=
,u>[cRqw
我用*号,标出了需要注意的地方,请高手指教!