切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10043阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: zfA GtT <  
    R?o$Y6}5  
    Az;t"  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: G3G#ep~)vC  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) },+wJ1  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 Qv,"($n\  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 {(U %i\F\  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: "#[!/\=?:  
    1.判断点在区域中函数 +gtrt^:]l  
    2.计算夹角函数 ),G=s Oo  
    3.转置函数 X/iT)R]b  
    4.得到区域中心点,及区域半径函数 g35DV6  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) M`rl!Ci#  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 B!vmQR*1  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single 'nXl>  
       cax = x2 - x1 0T Q$C-%  
       cay = y2 - y1 J ]nohICe  
       cbx = x2 - x3 UrqRx?#  
       cby = y2 - y3 >}+/{(K"E|  
       mo_jj = cax * cbx + cay * cby I 'V4D[H5  
       mo_ca = Sqr(cax * cax + cay * cay) N5a*7EJv+  
       mo_cb = Sqr(cbx * cbx + cby * cby) ;W>k@L  
       cos_acb = mo_jj / (mo_ca * mo_cb) -$\+' \  
       'ff_cos = cos_acb  ,%uo6%  
       If cos_acb >= 1 Then zuUW|r  
       nn = 0 W[Ls|<Q  
       ElseIf cos_acb <= -1 Then &YF^j2  
       nn = 3.14159265258979 Ney/[3 A  
       Else j'A_'g'^  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) mV3cp rRqv  
       End If S:h{2{  
       'ff_angle = nn mIK7p6  
       ff_angle = nn * 180 / 3.14159265258979 eEuvl`&  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 MF5[lK9e  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean @7IIM{  
    Dim aob, boc, cod, doa, sum As Single k?+?v?I =  
      If ppx = p1x And ppy = p1y Then <g"{Wv: h  
         point_in = True e)d`pQ6  
         Exit Function sS*3=Yh  
      End If #d6)#:uss  
      If ppx = p2x And ppy = p2y Then g:hjy@ w  
         point_in = True |?,A]|j  
         Exit Function sB7# ~p A  
      End If .+$ Q<L  
       If ppx = p3x And ppy = p3y Then $g> IyT[  
         point_in = True MN\HDKN  
         Exit Function x(1:s|Uyp{  
      End If ~E17L]ete  
         -XB/lnG  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) fdFo#P  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) VK m&iidU  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) fD[*_^;h)  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) +S o4rA*9  
        sum = aob + boc + cod + doa Q'=x|K#xj  
        If 360.01 > sum And sum > 359.99 Then d3\qKL!~  
           point_in = True ,o86}6Ag  
        Else vS;RJg=  
           point_in = False k\5c|Wq|g  
        End If g6j?,c|y  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 cr7 }^s  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() NcBIg:V\c  
        '求得中心点坐标 L/$H"YOv  
    Dim tt As String Ag-(5:  
    Dim rt(3) As Single XO.jl"xu  
        '判断是否平行 xQ7l~O b  
       acx = p3x - p1x n(1l}TJy  
       acy = p3y - p1y luh$2 \5B  
       bdx = p4x - p2x G#ZH.24Y  
       bdy = p4y - p2y #NEE7'&S  
       If acx * bdy = acy * bdx Then Yl Zso2  
          rt(0) = 0 n\mO6aJ  
          Exit Function b/+u4'"  
       Else f\|w '  
          '判断斜率存在否 )}Hpi<5N  
          If p1x = p3x And p2x <> p4x Then 03$mYS_?  
             tt = "ac_n_bd_y" )1?y 8_B  
          ElseIf p1x <> p3x And p2x = p4x Then ?+))}J5N\  
             tt = "ac_y_bd_n" ZF!h<h&,  
          ElseIf p1x <> p3x And p2x <> p4x Then 0"jY.*_EW  
             tt = "ac_y_bd_y" ^9v4OUG  
          End If `KZm0d{H  
        Select Case tt u|\1h LXX  
             Case "ac_n_bd_y" g|o,uD  
                'bd线段方程 yb<fpM  
                k_bd = bdy / bdx Vr3Zu{&2  
                b_bd = p2y - k_bd * p2x lU8l}Ndz"  
                p_x = p1x .Y tKS  
                p_y = k_bd * p_x + b_bd ROH|PKb7  
             Case "ac_y_bd_n" 'TTLo|@"-  
                'ac线段方程 j`{?OYD  
                k_ac = acy / acx =/@D8{pU  
                b_ac = p1y - k_ac * p1x s:n6rG  
                p_x = p2x sA+ }TNhq  
                p_y = k_ac * p_x + b_ac ( >LF(ll  
            Case "ac_y_bd_y" /2&c$9=1  
               'ac,bd线段都要求 9SX +  
               k_ac = acy / acx #|uCgdi  
               b_ac = p1y - k_ac * p1x Ki;*u_4{  
               k_bd = bdy / bdx Akq2 d;  
               b_bd = p2y - k_bd * p2x j * %  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) `}p0VmD{NE  
               p_y = k_ac * p_x + b_ac A @i  
            End Select W_JlOc!y  
          rt(1) = p_x ./\@Km?  
          rt(2) = p_y s n8Qk=K  
         akmkyrz'&  
    '计算最大半径 K%t*8 4j  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) D, k6$`  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) bTI|F]^!  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) z}.e]|b^H  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) dn& s*  
    Dim bb(5) As Single 8'[~2/  
      bb(1) = rr1 V.U| #n5  
      bb(2) = rr2 S;Fi?M  
      bb(3) = rr3 l5~os>  
      bb(4) = rr4 y5vvu>nd  
      nb = rr1 &5>Kl}7  
    For i = 1 To 4 EfqX y>W  
        If nb <= bb(i) Then Q-(zwAaE  
           nb = bb(i) ,<.V7(|t)  
        End If `~cqAs}6]Q  
    Next i ,>:U2%  
        rt(0) = Sqr(nb) |NlO7aQ>2H  
        rr = rt() :@yEQ#nFp  
      End If [|v][Hwv  
             (|2t#'m  
    End Function
    离线lifei0715
    发帖
    1237
    光币
    8444
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  BKCiIfkZ  
    8Al{+gx@?  
    有热压工艺方面的人才或者资料分享下; g{)dP!}  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 :LQYo'@yB  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.