切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10284阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: b`?M9f5  
    KD9Ca $-  
    {8W |W2o$!  
    本主题包含附件,请 登录 后查看, 或者 注册 成为会员
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: )8\Z=uC  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) WoJ]@Me8  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 ~ 6TfW~V  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 o(BYT9|.kw  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: I*%&)Hj~  
    1.判断点在区域中函数 ;o&_:]S  
    2.计算夹角函数 ZD iW72&Q  
    3.转置函数 !<JG&9ODP  
    4.得到区域中心点,及区域半径函数 O7E;W| ]  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) b'i%B9yU:%  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 m|g$'vjk  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single *m2d#f  
       cax = x2 - x1 4p0IBfVG  
       cay = y2 - y1 .T[!!z#^  
       cbx = x2 - x3 M}{n6T6B  
       cby = y2 - y3 \:18Uoe7  
       mo_jj = cax * cbx + cay * cby }6b7a1p  
       mo_ca = Sqr(cax * cax + cay * cay) .XZ 71E  
       mo_cb = Sqr(cbx * cbx + cby * cby) !)=#p9  
       cos_acb = mo_jj / (mo_ca * mo_cb) KG7X8AaK#  
       'ff_cos = cos_acb 9'1;-^U1  
       If cos_acb >= 1 Then VbY>l' rY  
       nn = 0 :5n"N5Go  
       ElseIf cos_acb <= -1 Then _j|n}7a  
       nn = 3.14159265258979 ?.|wfBI  
       Else xf{C 'uF/  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) =[43y%   
       End If zYNM<W;  
       'ff_angle = nn "Hsq<oV8  
       ff_angle = nn * 180 / 3.14159265258979 Z\o AE<$  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 D q_{O  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean d(dw]6I6  
    Dim aob, boc, cod, doa, sum As Single /ltP@*bo  
      If ppx = p1x And ppy = p1y Then ML9T (th6v  
         point_in = True 4YB7og%P  
         Exit Function  Cq~ah  
      End If kcZ;SYosj  
      If ppx = p2x And ppy = p2y Then Rqd%#v  
         point_in = True (J?}eb;>n  
         Exit Function 1\7"I-  
      End If 'AlSq:gZ  
       If ppx = p3x And ppy = p3y Then PSrt/y!  
         point_in = True 4<K ,w{I  
         Exit Function Wy0a2Ve  
      End If MX< ($M  
         k%4A::=  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) }Rf :DmPE  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) He$mu=$q{  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) O (sFs1  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) [laL6  
        sum = aob + boc + cod + doa IbNTdg]/F`  
        If 360.01 > sum And sum > 359.99 Then OYRR'X.E  
           point_in = True C`K9WJOD  
        Else S0o,)`ZB  
           point_in = False `peJ s~V  
        End If y^+[eT&  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 g>oYEFFJ  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() mWFZg.#?  
        '求得中心点坐标 i:Ct6[  
    Dim tt As String ~!+h"%'t  
    Dim rt(3) As Single oG_'<5Bv>  
        '判断是否平行 \?ws0Ax  
       acx = p3x - p1x mUY:S |  
       acy = p3y - p1y zSM7x  
       bdx = p4x - p2x nQYS{`hk  
       bdy = p4y - p2y Z 5YW L4s  
       If acx * bdy = acy * bdx Then R*5;J`TW  
          rt(0) = 0 7 V1k$S(  
          Exit Function _q 9lr8hx  
       Else )p_LkX(  
          '判断斜率存在否 )A+j  
          If p1x = p3x And p2x <> p4x Then (7#lN  
             tt = "ac_n_bd_y" >wm$,%zk  
          ElseIf p1x <> p3x And p2x = p4x Then bb_jD^  
             tt = "ac_y_bd_n" PY:#F|uHS`  
          ElseIf p1x <> p3x And p2x <> p4x Then =}o>_+"  
             tt = "ac_y_bd_y" XGl13@=O  
          End If - 5Wt9  
        Select Case tt :/[ZgreN6  
             Case "ac_n_bd_y" XI(@O)  
                'bd线段方程 ,* vnt6C*  
                k_bd = bdy / bdx 5dEO_1q %  
                b_bd = p2y - k_bd * p2x }AfPBfgC1z  
                p_x = p1x {3uSg)  
                p_y = k_bd * p_x + b_bd X@4d~6k?  
             Case "ac_y_bd_n" l@F e(^5E  
                'ac线段方程 |g^W @.P  
                k_ac = acy / acx C>;8`6_!gU  
                b_ac = p1y - k_ac * p1x iiDkk  
                p_x = p2x PC7.+;1  
                p_y = k_ac * p_x + b_ac kb\v}gfiD/  
            Case "ac_y_bd_y" (_5+`YsV  
               'ac,bd线段都要求 [hj'Yg8{  
               k_ac = acy / acx Ln%_8yth  
               b_ac = p1y - k_ac * p1x '>3RZ& O  
               k_bd = bdy / bdx {O oNhN9  
               b_bd = p2y - k_bd * p2x %}5"5\Zz  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) _~q^YZ  
               p_y = k_ac * p_x + b_ac % +"AF+c3r  
            End Select )g<qEyJR  
          rt(1) = p_x RSeezP6#  
          rt(2) = p_y s H[34gCh;  
         E1v<-UPbA  
    '计算最大半径 DL!s)5!M  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) Elk$9 < <  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) )_.H #|r  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) zO]dQ$r\Z  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) C:EoUu  
    Dim bb(5) As Single '^Np<  
      bb(1) = rr1 d>-EtWd  
      bb(2) = rr2 SO<K#HfE$?  
      bb(3) = rr3 li XD2N  
      bb(4) = rr4 `8bp6}OD,  
      nb = rr1 vt=S0X^$yc  
    For i = 1 To 4 3A1kH` X^q  
        If nb <= bb(i) Then e(5R8ud  
           nb = bb(i) PS]X Lz  
        End If <W^~Y31:0  
    Next i 9'aR-tFun;  
        rt(0) = Sqr(nb) \Rt  
        rr = rt() UzwIV{  
      End If IT33E%G  
             tR/ JY;jn  
    End Function
    离线lifei0715
    发帖
    1250
    光币
    8511
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  J<D =\  
    hw1s^:|+2  
    有热压工艺方面的人才或者资料分享下; Zf! 7pM  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 na>B{6  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.