切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 8718阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: ,a eQXI#@  
    F^ 7qLvh  
    5B#q/d1/a  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: (MY#;v\AYE  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) CnSfGsE>  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 /vll*}}  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 eqU2>bI f  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: C,~wmS )@  
    1.判断点在区域中函数 0{^vqh.La  
    2.计算夹角函数 T]-yTsto  
    3.转置函数 zs e<b/G1G  
    4.得到区域中心点,及区域半径函数 wwrP7T+d  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) dU1w)Y  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 ph{p[QI:{X  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single z%$ E6Im  
       cax = x2 - x1 ~\kJir  
       cay = y2 - y1 D X GClH  
       cbx = x2 - x3 R,R[.2Vi  
       cby = y2 - y3 5v <>%=  
       mo_jj = cax * cbx + cay * cby )]WWx-Uf'  
       mo_ca = Sqr(cax * cax + cay * cay) U/F<r3.`#  
       mo_cb = Sqr(cbx * cbx + cby * cby) $2B _a  
       cos_acb = mo_jj / (mo_ca * mo_cb) Ri4t/H  
       'ff_cos = cos_acb N`XJA-DE  
       If cos_acb >= 1 Then x{{QS$6v  
       nn = 0 i)9}+M 5  
       ElseIf cos_acb <= -1 Then i{[=N9U5o  
       nn = 3.14159265258979 )OQhtxK  
       Else U<,@u,_Ja  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) u$ [R>l9  
       End If L08>9tf`  
       'ff_angle = nn e~R; 2bk  
       ff_angle = nn * 180 / 3.14159265258979 V ij P;  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 W}m-5L  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean V.zKjoky@  
    Dim aob, boc, cod, doa, sum As Single q-s! hiK  
      If ppx = p1x And ppy = p1y Then q/y4HT,x  
         point_in = True 272j$T  
         Exit Function L9tjH C]  
      End If ZeewGa^r  
      If ppx = p2x And ppy = p2y Then XMhDx  
         point_in = True @X`~r8&  
         Exit Function AA][}lU:5  
      End If [MSLVTR  
       If ppx = p3x And ppy = p3y Then 9~+A<X]Hd  
         point_in = True *hVbjI$  
         Exit Function mF!/8qk   
      End If )aoB -Lu  
         D|-^}I4  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) f[,9WkC  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) ?^Sk17G  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) !iKR~&UpAL  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) y,qP$ 5xiq  
        sum = aob + boc + cod + doa _&S?uz m  
        If 360.01 > sum And sum > 359.99 Then .K?',x  
           point_in = True p- 5)J&  
        Else JA W}]:jC  
           point_in = False &`>[4D*  
        End If }~P%S(zB  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 WqN=  D5  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() | \Nj  
        '求得中心点坐标 j,Sg?&"%=  
    Dim tt As String `abQlBb*  
    Dim rt(3) As Single vQrce&  
        '判断是否平行 @rs(`4QEh  
       acx = p3x - p1x #.O,JG#H  
       acy = p3y - p1y SNP.n))   
       bdx = p4x - p2x qGMM3a)Q  
       bdy = p4y - p2y qh Ezv~  
       If acx * bdy = acy * bdx Then pT]M]/y/:  
          rt(0) = 0 SsA;T5:6  
          Exit Function }qfr&Ffh@  
       Else w?CbATQ   
          '判断斜率存在否 dDH+`;$.  
          If p1x = p3x And p2x <> p4x Then g-'y_'%0G  
             tt = "ac_n_bd_y" D|I(2%aC  
          ElseIf p1x <> p3x And p2x = p4x Then h"VQFqQy  
             tt = "ac_y_bd_n" 0 eZfHW&  
          ElseIf p1x <> p3x And p2x <> p4x Then &{QB}r  
             tt = "ac_y_bd_y" d7N;F a3yL  
          End If XfA3Ez,}  
        Select Case tt `}o4&$  
             Case "ac_n_bd_y" `NA[zH,w3  
                'bd线段方程 G%)?jg@EA  
                k_bd = bdy / bdx WujIaJt-  
                b_bd = p2y - k_bd * p2x 7}bjJR "  
                p_x = p1x GZT}aMMSJ  
                p_y = k_bd * p_x + b_bd <B 5^  
             Case "ac_y_bd_n" P# 2&?.d\  
                'ac线段方程 A9PXu\%y  
                k_ac = acy / acx \3K6NA!L  
                b_ac = p1y - k_ac * p1x KtJE  
                p_x = p2x Ab7hW(/  
                p_y = k_ac * p_x + b_ac gd<8RVA  
            Case "ac_y_bd_y" Cw?AP6f%  
               'ac,bd线段都要求 o;Ijv\Em  
               k_ac = acy / acx RAKQ+Y"nl  
               b_ac = p1y - k_ac * p1x A/N*Nc  
               k_bd = bdy / bdx XuJwZN!(  
               b_bd = p2y - k_bd * p2x %sC,;^wla'  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) (ohkM`83k  
               p_y = k_ac * p_x + b_ac vl$! To9R"  
            End Select S-Va_ t$  
          rt(1) = p_x ]i*q*]x2u  
          rt(2) = p_y rh2pVDS  
         R#~}ZUk2  
    '计算最大半径 vZ 4Z+;.  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) b qB[ vPsI  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) 'R*gSqx~  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) =1^a/  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) .G+}Kn9!  
    Dim bb(5) As Single o^RdVSkU;  
      bb(1) = rr1 n ! qm  
      bb(2) = rr2 cb&y8!ci~  
      bb(3) = rr3 QxnP+U~N  
      bb(4) = rr4 x$CpUy{6  
      nb = rr1 oSNB\G<  
    For i = 1 To 4 8DTk<5mW~  
        If nb <= bb(i) Then ..FUg"sSO  
           nb = bb(i) iM2 EEC  
        End If 3sGrX"0D  
    Next i MIa].S#  
        rt(0) = Sqr(nb) L:YsAv  
        rr = rt() QOuy(GY  
      End If GQqw(2Ub}  
             1E$Z]5C9  
    End Function
    离线lifei0715
    发帖
    1217
    光币
    8214
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  1pzU=!R?-O  
    xmiF!R  
    有热压工艺方面的人才或者资料分享下; !Z=`Wk5  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 [*}[W6 3v  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.