切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9728阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: $4jell  
    zF4[}*  
    OdMO=Hy6d  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: %7Kooq(i  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) ,_!6U  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 cYNJhGY  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 VC5_v62&.  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: 4 ;Qlu  
    1.判断点在区域中函数 wLuv6\E  
    2.计算夹角函数 XwM611  
    3.转置函数 Ql?^ B SqG  
    4.得到区域中心点,及区域半径函数 A`O<6   
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) dsK&U\ej}  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 ^[TV;9I*  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single ?_6YtR,{  
       cax = x2 - x1 2k7bK6=nm  
       cay = y2 - y1 _BnTv$.P  
       cbx = x2 - x3 9-*NW0  
       cby = y2 - y3 YHxbDf dA  
       mo_jj = cax * cbx + cay * cby ]pTvMom$6  
       mo_ca = Sqr(cax * cax + cay * cay) Hr;h4J  
       mo_cb = Sqr(cbx * cbx + cby * cby) S_J :&9L  
       cos_acb = mo_jj / (mo_ca * mo_cb) z?8~[h{i%  
       'ff_cos = cos_acb ScnY3&rc  
       If cos_acb >= 1 Then (J:dK=O@Z  
       nn = 0 f<[jwhCWV  
       ElseIf cos_acb <= -1 Then jigs6#  
       nn = 3.14159265258979 OVoO6F ]  
       Else HgJb4Fi  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) !7H6i#g*  
       End If O^{1RV3:,T  
       'ff_angle = nn V7CoZnz  
       ff_angle = nn * 180 / 3.14159265258979 (VHND%7P  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 u'9gVU B  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean [p;*r)f2}  
    Dim aob, boc, cod, doa, sum As Single Yt1mB[&f^  
      If ppx = p1x And ppy = p1y Then #JNy  
         point_in = True Uf,fX/:!  
         Exit Function H;vZm[\0N-  
      End If Z-Wfcnk  
      If ppx = p2x And ppy = p2y Then =v2%Vs\7k  
         point_in = True eO5ktEoJ  
         Exit Function cFfTYP9  
      End If vgPUIxB@  
       If ppx = p3x And ppy = p3y Then &/F_*=VE  
         point_in = True `bgb*Yaod  
         Exit Function 4!%]fg}Um  
      End If &{^eU5  
         >Gd.&flSj  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) w$Ux?y- L  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) 'Tf9z+0;  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) 9 pKm*n&  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) #a}N"*P  
        sum = aob + boc + cod + doa n E :'Zxj  
        If 360.01 > sum And sum > 359.99 Then R8sck)k'}  
           point_in = True ~Yk"Hos  
        Else q(9%^cV6  
           point_in = False r%MyR8'k]  
        End If rZC3\,W  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 `!Ln|_,d  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() m#ad6 \  
        '求得中心点坐标 x`2pr  
    Dim tt As String ]Y5dl;xrM)  
    Dim rt(3) As Single kkfCAM  
        '判断是否平行 Fzs>J&sY&  
       acx = p3x - p1x y9 uVCR  
       acy = p3y - p1y ) hdgz$cl  
       bdx = p4x - p2x @a;sV!S{  
       bdy = p4y - p2y hmzair3X  
       If acx * bdy = acy * bdx Then gH H&IzHF  
          rt(0) = 0 4!'1/3cY  
          Exit Function i+U51t<  
       Else GMb!Q0I8  
          '判断斜率存在否 'wE\{1~_[+  
          If p1x = p3x And p2x <> p4x Then cju@W]!  
             tt = "ac_n_bd_y" !u0U5>ccw  
          ElseIf p1x <> p3x And p2x = p4x Then Oy'0I,  
             tt = "ac_y_bd_n" a(Sv,@/  
          ElseIf p1x <> p3x And p2x <> p4x Then $~hdm$  
             tt = "ac_y_bd_y" "gg(tp45  
          End If N l|^o{#  
        Select Case tt J[+Tj @n'  
             Case "ac_n_bd_y" Jk~UEqr+  
                'bd线段方程 &Q+]t"OA!  
                k_bd = bdy / bdx #Y: ~UVV  
                b_bd = p2y - k_bd * p2x (\uA AW"  
                p_x = p1x Ns~ g+C9  
                p_y = k_bd * p_x + b_bd 5=.7\#D  
             Case "ac_y_bd_n" % &+|==-  
                'ac线段方程 8!6<p[_  
                k_ac = acy / acx g5<ZS3tQ  
                b_ac = p1y - k_ac * p1x }!knU3J  
                p_x = p2x yUj;4vd  
                p_y = k_ac * p_x + b_ac B{4"$Mi  
            Case "ac_y_bd_y" w*2^/zh  
               'ac,bd线段都要求 j,ZW[*M  
               k_ac = acy / acx -g$O OJB6  
               b_ac = p1y - k_ac * p1x Yoe les-  
               k_bd = bdy / bdx * S{\#s  
               b_bd = p2y - k_bd * p2x QS%,7'EG  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) (V^QQ !:  
               p_y = k_ac * p_x + b_ac $uTlbAuv  
            End Select S#hu2\9D,  
          rt(1) = p_x B,:23[v  
          rt(2) = p_y _we3jzMW  
         _32/WQF6  
    '计算最大半径 +E)e1 :8  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) : (RL8  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) FcY$k%;'Q  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) M+\rX1T  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) TA<hj[-8  
    Dim bb(5) As Single L&rO  6  
      bb(1) = rr1 zH'!fhcy  
      bb(2) = rr2 q>c+bo 6  
      bb(3) = rr3 JH-nvv  
      bb(4) = rr4 )*+u\x_Hx  
      nb = rr1 mn Qal>0~  
    For i = 1 To 4 ]&/0  
        If nb <= bb(i) Then EqYz,%I%  
           nb = bb(i) |#!eMJ&0  
        End If $kM '  
    Next i XZ!cW=bqS  
        rt(0) = Sqr(nb) |\rSa^:5  
        rr = rt() 5=Zp%[ #  
      End If HI7]%<L  
             o<~-k,{5P  
    End Function
    离线lifei0715
    发帖
    1236
    光币
    8439
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  }1X11+/W  
    I?^Q084  
    有热压工艺方面的人才或者资料分享下; q\ \8b{~  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 1]D/3!  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.