切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10241阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: ;q6FdS  
    Q?\rwnW?U  
    Nq3q##Ut:  
    本主题包含附件,请 登录 后查看, 或者 注册 成为会员
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: Wi?37EHr  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) k 8Swra?j  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 X)K3X:~L+  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 !Xbr7:UPN1  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: _"PT O&E  
    1.判断点在区域中函数 i 7fQj, q  
    2.计算夹角函数 ~ZSP K;D[  
    3.转置函数 $Qv+*%c  
    4.得到区域中心点,及区域半径函数 9W{=6D86e  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) x"Hi!h)v  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 O/9dPod  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single Xz'pZ*Hr$v  
       cax = x2 - x1 >5&'_  
       cay = y2 - y1 99@uU[&IJ  
       cbx = x2 - x3 8Vkw vc  
       cby = y2 - y3 <|NP!eMsw8  
       mo_jj = cax * cbx + cay * cby a{7>7%[  
       mo_ca = Sqr(cax * cax + cay * cay) &i8AB{OU  
       mo_cb = Sqr(cbx * cbx + cby * cby) t%e}'?#^  
       cos_acb = mo_jj / (mo_ca * mo_cb) /HsJyp+t  
       'ff_cos = cos_acb ISI\< qx  
       If cos_acb >= 1 Then 8I)66  
       nn = 0 a W`q  
       ElseIf cos_acb <= -1 Then uoYG@L2  
       nn = 3.14159265258979 yVvO!  
       Else 3[E3]]OVa  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) C:/O]slH  
       End If 7u!i)<pn  
       'ff_angle = nn TKpka]nJ  
       ff_angle = nn * 180 / 3.14159265258979 ErK5iTSD  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 RU3:[ (7  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean D.zEE-cGyb  
    Dim aob, boc, cod, doa, sum As Single 5w)tsGX\  
      If ppx = p1x And ppy = p1y Then GndU}[0J  
         point_in = True a9C8Q l  
         Exit Function gwDQ@  
      End If cXiNO ke&  
      If ppx = p2x And ppy = p2y Then eXY*l>B  
         point_in = True w yP|#Z\  
         Exit Function +jePp_3$O  
      End If NGIbUH1[  
       If ppx = p3x And ppy = p3y Then M=$ qus  
         point_in = True !63p?Q=  
         Exit Function T u>5H`  
      End If ?IR]y-r  
         >J+'hm@  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) ezn%*X y,  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) Tf/jd 3>  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) <rZ( B>$  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) fvn`$  
        sum = aob + boc + cod + doa +;uP) "Q/L  
        If 360.01 > sum And sum > 359.99 Then P,-f]k[_  
           point_in = True yOwo(+ 2  
        Else W($}G_j[B1  
           point_in = False TbqH-R3W  
        End If @>n7  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 IE7%u 92  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() THC7e>P4  
        '求得中心点坐标 M0Y#=u.  
    Dim tt As String _m.u@+g  
    Dim rt(3) As Single KY5it9e  
        '判断是否平行 }+/j/es{]  
       acx = p3x - p1x a6\0XVU  
       acy = p3y - p1y |>_e& }Y%L  
       bdx = p4x - p2x FXMrD,qVg  
       bdy = p4y - p2y jeb ]3i=pw  
       If acx * bdy = acy * bdx Then 3@#WYvD  
          rt(0) = 0 }8 V/Cd9  
          Exit Function gR7in!8  
       Else \4$V ;C/n,  
          '判断斜率存在否 ]fxYS m  
          If p1x = p3x And p2x <> p4x Then []^fb,5a  
             tt = "ac_n_bd_y" }7?n\I+n"  
          ElseIf p1x <> p3x And p2x = p4x Then \ZNUt$\  
             tt = "ac_y_bd_n" @">^2  
          ElseIf p1x <> p3x And p2x <> p4x Then ViZ Tl~  
             tt = "ac_y_bd_y" X5[.X()M4  
          End If +H"[WZ5  
        Select Case tt $?x;?wS0V  
             Case "ac_n_bd_y" >3aB{[[N  
                'bd线段方程 MTI[Mez  
                k_bd = bdy / bdx vwF#;jj\  
                b_bd = p2y - k_bd * p2x K qK?w*Qw  
                p_x = p1x )W,tL*9[  
                p_y = k_bd * p_x + b_bd |E]`rfr  
             Case "ac_y_bd_n" ^w|D^F=o  
                'ac线段方程 *vFXe_.  
                k_ac = acy / acx +95: O 8  
                b_ac = p1y - k_ac * p1x dgbqMu"  
                p_x = p2x UdGa#rcNW  
                p_y = k_ac * p_x + b_ac 1u`{yl*+?  
            Case "ac_y_bd_y" $TU:iv1Fm  
               'ac,bd线段都要求 E4}MU}C#[  
               k_ac = acy / acx `^d[$IbDW  
               b_ac = p1y - k_ac * p1x {3)^$F=T  
               k_bd = bdy / bdx W20qn>{z  
               b_bd = p2y - k_bd * p2x 9:\#GOg  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) "W71#n+ [  
               p_y = k_ac * p_x + b_ac r<)>k.] !  
            End Select FdwlRuG  
          rt(1) = p_x %"yy8~|  
          rt(2) = p_y )t?_3'W  
         4Su|aWL-  
    '计算最大半径 :`Sd5b>  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) rjaG{ i  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) bM@8[&t a  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) XEX-NE"]  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) "gIjU~'A  
    Dim bb(5) As Single vV$6fvS  
      bb(1) = rr1 =|j~*6Hd  
      bb(2) = rr2 5~!&x@  
      bb(3) = rr3 pw, <0UhV  
      bb(4) = rr4 _6Z}_SiOl  
      nb = rr1 B5R/GV  
    For i = 1 To 4 K?J?]VCw  
        If nb <= bb(i) Then ABG>W>H-S  
           nb = bb(i) x<=<Lx0B;  
        End If d,V]j-  
    Next i &YpWfY&V  
        rt(0) = Sqr(nb) j&y>?Y&Sb  
        rr = rt() m[w 8|[  
      End If B k yW  
             h.t2;O,b  
    End Function
    离线lifei0715
    发帖
    1250
    光币
    8511
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  A_}%YHb  
    K26x,m]p  
    有热压工艺方面的人才或者资料分享下; fNZ:l=L3):  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 "YQ%j+  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.