切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 9561阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: :XFQ}Cl  
    F\xIVY  
    1[O cZ CS  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: *W\3cS  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) /!5ohQlPJ  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 `oikSx$vB.  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 i=#\`"/  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: ^2Cqy%x-  
    1.判断点在区域中函数 ?GNR ab  
    2.计算夹角函数 D? %*L  
    3.转置函数 18%$Z$K,  
    4.得到区域中心点,及区域半径函数 >$rH,Er  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) \Qah*1  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 83V\O_7j  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single .$cX:"_Mk  
       cax = x2 - x1 `$1A;wg<  
       cay = y2 - y1 G2wSd'n*y  
       cbx = x2 - x3 C<a&]dN/  
       cby = y2 - y3 (G+)v[f  
       mo_jj = cax * cbx + cay * cby RjUrpS[I  
       mo_ca = Sqr(cax * cax + cay * cay) B]yO  
       mo_cb = Sqr(cbx * cbx + cby * cby) $> QJ%v9+  
       cos_acb = mo_jj / (mo_ca * mo_cb) ,|$1(z*a{c  
       'ff_cos = cos_acb D]iyr>V6'  
       If cos_acb >= 1 Then y{(Dv}   
       nn = 0 \PN*gDmX  
       ElseIf cos_acb <= -1 Then ckFPx l.  
       nn = 3.14159265258979 |qQ6>IZ  
       Else qmn l  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) <Af&Q0J  
       End If j-/$e,xX  
       'ff_angle = nn ]Gm4gd`  
       ff_angle = nn * 180 / 3.14159265258979 TW 1`{SM  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 n|H8O3@  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean cY!Pv  
    Dim aob, boc, cod, doa, sum As Single EFtn !T  
      If ppx = p1x And ppy = p1y Then mmjWLrhlu  
         point_in = True *7*cWO=  
         Exit Function X<Xiva85  
      End If 2H8\P+  
      If ppx = p2x And ppy = p2y Then } @3q;u)  
         point_in = True G,WLca[  
         Exit Function *@@dO_%6  
      End If `N}V i6FG  
       If ppx = p3x And ppy = p3y Then H^o_B1  
         point_in = True vY4}vHH2  
         Exit Function LrdED[Z  
      End If ]T5\LNyN  
         ?)<zzL",  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) v`Y{.>[H[  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) :>ca).cjac  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) A[fTpS~~%  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) nRX'J5Q m<  
        sum = aob + boc + cod + doa 4;32 f`  
        If 360.01 > sum And sum > 359.99 Then WCqa[=v)t  
           point_in = True 7;.Iat9gMf  
        Else !w/fw Oo  
           point_in = False M|@@ LJ'  
        End If I%Z=O=  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 C*RPSk  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() &N/dxKZcc  
        '求得中心点坐标 hhU\$'0B-  
    Dim tt As String !"hzGgOOX  
    Dim rt(3) As Single yP` K [/  
        '判断是否平行 g#1 Y4  
       acx = p3x - p1x ^)`e}}  
       acy = p3y - p1y mL#$8wUdt{  
       bdx = p4x - p2x 211T}a  
       bdy = p4y - p2y [T [] U   
       If acx * bdy = acy * bdx Then :1"k`AG  
          rt(0) = 0 V+U89j1g  
          Exit Function z.h;}QRJ,@  
       Else +4qR5(W  
          '判断斜率存在否 |h/{ qpsu  
          If p1x = p3x And p2x <> p4x Then # eFdu  
             tt = "ac_n_bd_y" ~(Q#G" t  
          ElseIf p1x <> p3x And p2x = p4x Then K2v[_a~@  
             tt = "ac_y_bd_n" F]<2nb7  
          ElseIf p1x <> p3x And p2x <> p4x Then dxS5-aWy9w  
             tt = "ac_y_bd_y" Y}C|4"V  
          End If 8y[Rwa  
        Select Case tt Jko=E   
             Case "ac_n_bd_y" 5vS[{;<&  
                'bd线段方程 4OAR ["f  
                k_bd = bdy / bdx vwa*'C  
                b_bd = p2y - k_bd * p2x G%!i="/9  
                p_x = p1x nLANWQk9  
                p_y = k_bd * p_x + b_bd 1BP/,d |+  
             Case "ac_y_bd_n" U ){4W0  
                'ac线段方程 [P}mDX  
                k_ac = acy / acx DV>;sCMJ %  
                b_ac = p1y - k_ac * p1x H_| re  
                p_x = p2x dd +lQJ c  
                p_y = k_ac * p_x + b_ac VH+3o?nrT  
            Case "ac_y_bd_y" CQ{{J{pU"  
               'ac,bd线段都要求 yVKl%GO  
               k_ac = acy / acx *c$UIg  
               b_ac = p1y - k_ac * p1x zR/mz)6_  
               k_bd = bdy / bdx tef>Py  
               b_bd = p2y - k_bd * p2x X68.*VHh0  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) ^;[_CF _  
               p_y = k_ac * p_x + b_ac ]!jfrj  
            End Select DqmKD U  
          rt(1) = p_x  B"5xs  
          rt(2) = p_y sK/ymEfRv  
         V_n tS& 2o  
    '计算最大半径 *]Cyc<  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) 0;OZ|;Z  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) E]a;Ydf~  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) xwHE,ykE  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) @~5Fcfmm  
    Dim bb(5) As Single $S2 /*  
      bb(1) = rr1 Z>X]'q03  
      bb(2) = rr2 S<i. O  
      bb(3) = rr3 -QBM^L  
      bb(4) = rr4 ,C_MB1u  
      nb = rr1 U.I 7p  
    For i = 1 To 4 W+4Bx=Mj  
        If nb <= bb(i) Then 2FO<Z %Y  
           nb = bb(i) pu ?CO A  
        End If 3Q7PY46  
    Next i k$DRX) e  
        rt(0) = Sqr(nb) e5; YY  
        rr = rt() y4=T0[ V  
      End If Q]RE,ZZ  
             ]n:R#55A  
    End Function
    离线lifei0715
    发帖
    1236
    光币
    8438
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  NJQy*~P  
    G)o:R iq  
    有热压工艺方面的人才或者资料分享下; W!+=`[Ff  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 ,*m|Lt%;R  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.