切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10098阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: V[RF </2T  
    C_( *>!Z%  
    >=qf/K +#  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: ^ UciW  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) ]_Vx{oT7  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 VyXKZ%\dQ/  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 VF&(8X\   
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: QCD .YFM  
    1.判断点在区域中函数 RU'=ERYC  
    2.计算夹角函数 ed]=\Key  
    3.转置函数 GD&uQ`Y5  
    4.得到区域中心点,及区域半径函数 6o!!=}'E[  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) "An,Q82oHf  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 c%^7!FSg  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single uX"H4l O~  
       cax = x2 - x1 NC8t) X7  
       cay = y2 - y1 cCSs  
       cbx = x2 - x3 >] qc-{>&  
       cby = y2 - y3 k o5@qNq  
       mo_jj = cax * cbx + cay * cby P#E&|n7DT  
       mo_ca = Sqr(cax * cax + cay * cay) ,QOG!T4  
       mo_cb = Sqr(cbx * cbx + cby * cby) fsmN)_T  
       cos_acb = mo_jj / (mo_ca * mo_cb) 9 3U_tQ&1?  
       'ff_cos = cos_acb 8|b3j^u  
       If cos_acb >= 1 Then }^4Xv^dW>g  
       nn = 0 %OtFHhb  
       ElseIf cos_acb <= -1 Then Eav[/cU  
       nn = 3.14159265258979 H ;7(}:.  
       Else 0v6)t.]s  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) u~r=)His  
       End If pe0F0Ruy  
       'ff_angle = nn HpR]q05d  
       ff_angle = nn * 180 / 3.14159265258979 ;5wn67'  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 yTyj'-4  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean  ^le<}  
    Dim aob, boc, cod, doa, sum As Single ZkgV_<M|  
      If ppx = p1x And ppy = p1y Then =31"fS@  
         point_in = True sI43@[  
         Exit Function d]`CxI]  
      End If jy7\+i  
      If ppx = p2x And ppy = p2y Then a! (4Ch  
         point_in = True s J\BF  
         Exit Function < 3(LWxw  
      End If uzXCIv@  
       If ppx = p3x And ppy = p3y Then h,QKd>4:CF  
         point_in = True ?M$.+V{a  
         Exit Function SD#]$v  
      End If hrmut*<|  
         qsL) }sC^8  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y) (w&F/ynO:  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) 4pe'06:  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) )Z[ft  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) yZd +^QN  
        sum = aob + boc + cod + doa "vA}FV%tRq  
        If 360.01 > sum And sum > 359.99 Then $v,dz_O*\  
           point_in = True &6DMk-  
        Else hS_6  
           point_in = False QU#w%|  
        End If ?m![Pg%  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 Kfm5i Q  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() z+ s6)Ad  
        '求得中心点坐标 KuWWUjCE  
    Dim tt As String Yaj0;Lo[wt  
    Dim rt(3) As Single UYFwS/ RW}  
        '判断是否平行 .#wqXRd  
       acx = p3x - p1x gHhh>FFAq  
       acy = p3y - p1y n 9\ C2r  
       bdx = p4x - p2x jQk*8   
       bdy = p4y - p2y Kqun^"Df  
       If acx * bdy = acy * bdx Then og4UhP^UET  
          rt(0) = 0 ^ K|;~}P  
          Exit Function Hip&8NW  
       Else t'9*R7=  
          '判断斜率存在否 * +'x~a  
          If p1x = p3x And p2x <> p4x Then Rfn9s(m  
             tt = "ac_n_bd_y" vesJEaw7  
          ElseIf p1x <> p3x And p2x = p4x Then rJFc({ 0  
             tt = "ac_y_bd_n" Z -,J)gW  
          ElseIf p1x <> p3x And p2x <> p4x Then .tkT<o-u<J  
             tt = "ac_y_bd_y" lW<PoT  
          End If ^Y<|F!0  
        Select Case tt r~+\ Y"rM  
             Case "ac_n_bd_y" GRMiQa  
                'bd线段方程 tcI}Ca>u  
                k_bd = bdy / bdx A"`foI$0  
                b_bd = p2y - k_bd * p2x pp.6Ex (R  
                p_x = p1x m1n.g4Z&*  
                p_y = k_bd * p_x + b_bd s?zAP O8Sz  
             Case "ac_y_bd_n" ktK_e  
                'ac线段方程 (&&4J{`W9  
                k_ac = acy / acx *o-.6OxZ$  
                b_ac = p1y - k_ac * p1x |nbf'  
                p_x = p2x nM\eDNK  
                p_y = k_ac * p_x + b_ac Q F-LU  
            Case "ac_y_bd_y" 1?)Xp|O  
               'ac,bd线段都要求 RbCPmiZcH  
               k_ac = acy / acx pX/n)q[  
               b_ac = p1y - k_ac * p1x iQ4);du  
               k_bd = bdy / bdx YWMGB#=  
               b_bd = p2y - k_bd * p2x a UxGzMZ  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) o]Ol8I  
               p_y = k_ac * p_x + b_ac / y A7%2  
            End Select T_X6Ulp  
          rt(1) = p_x {*[\'!d--.  
          rt(2) = p_y \|]Z8t7  
         kgy:Q'  
    '计算最大半径 XGJj3-eW {  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) klQC2drS  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) fR)m%m  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) o[v\|Q`d  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) $KUo s+%  
    Dim bb(5) As Single z?[r  
      bb(1) = rr1 Dw=gs{8D  
      bb(2) = rr2 6&DX] [G  
      bb(3) = rr3 "8 ~:[G#  
      bb(4) = rr4 4&xZ]QC)O5  
      nb = rr1 baJxU:Y=p  
    For i = 1 To 4 iv?gZg   
        If nb <= bb(i) Then RG3l.jL  
           nb = bb(i) Y7#-Fra0W  
        End If fLDg~;3  
    Next i CSGz3uC2D  
        rt(0) = Sqr(nb) pAb.c  
        rr = rt() !Gu%U$d  
      End If S;~g3DC d  
             ?q(\=;Y  
    End Function
    离线lifei0715
    发帖
    1239
    光币
    8446
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  Q~MC7-n>  
    I.Y['%8,5~  
    有热压工艺方面的人才或者资料分享下; {^ m(,K_  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 /erN;Oo%<  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.