切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 10090阅读
    • 26回复

    [分享]绝对随机网点分布(excel之vba) [复制链接]

    上一主题 下一主题
    离线safeng1122
     
    发帖
    286
    光币
    26
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2013-04-08
    想学习的请研究下,直接给程序就没意思了,由于公司想做一套导光板模具,没有现成的软件可用,就自己做了较简单的程序,虽然简单,但基本功能已经满足了导光板网点设计的要求;具备功能:任意多边形区域;含有光轴,且可以根据光源调整;网点密度可沿光轴方向调整,效果图如下: ')ZZ)&U>z  
    `!<#'PR  
    "Fz1:VV&  
     
    分享到
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 1楼 发表于: 2013-04-08
    关键点说几个: V^_U=Ed@M  
    1.区域是由点围成的,所以EXCEL中需要定义点的坐标(区域) lqvP Dz  
    2.需要定义光轴的方向;简便的方法就是指定光源坐标,及网点区域坐标,这样光轴就确定了 0B"_St}3D  
    3.网点区域密度可调;把区域分成若干小块,每块的密度不同即可 <GSp%r  
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 2楼 发表于: 2013-04-08
    以下是几个重要的函数: \zhCGDm1_  
    1.判断点在区域中函数 p,14'HS%@  
    2.计算夹角函数 PNH>LT^  
    3.转置函数 iB+ _+A  
    4.得到区域中心点,及区域半径函数 J7@Q;gcl:  
    5.再有就是若干个点抽取其中一部分;或者采用随机分布(该方法会有重合点,所以没采用) ON"p^o>/_?  
    6.文件开启与关闭,这个最常见了,就不说了
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 3楼 发表于: 2013-04-08
    '计算夹角函数 L;fz7?_j  
    Function ff_angle(x1 As Single, y1 As Single, x2 As Single, y2 As Single, x3 As Single, y3 As Single) As Single =69sWcC8  
       cax = x2 - x1 YD#L@:&gv  
       cay = y2 - y1 !ZY1AhGZ  
       cbx = x2 - x3 f;!L\$yKy  
       cby = y2 - y3 /sSM<r]5j  
       mo_jj = cax * cbx + cay * cby .Dy2O*`  
       mo_ca = Sqr(cax * cax + cay * cay) <g64N  
       mo_cb = Sqr(cbx * cbx + cby * cby) VUD9ZyPw  
       cos_acb = mo_jj / (mo_ca * mo_cb) ,My'_"S?  
       'ff_cos = cos_acb B^.:dn  
       If cos_acb >= 1 Then uM9Gj@_  
       nn = 0 _p<wATv?7t  
       ElseIf cos_acb <= -1 Then 5kCXy$"%  
       nn = 3.14159265258979 Rb0{W]opt+  
       Else (]-RL A>  
       nn = Atn(-cos_acb / Sqr(-cos_acb * cos_acb + 1)) + 2 * Atn(1) ]'Gz~Z%>F  
       End If =-avzuy#  
       'ff_angle = nn pv^:G;  
       ff_angle = nn * 180 / 3.14159265258979 ;8cTy8  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 4楼 发表于: 2013-04-08
    '判断点在区域内函数 azG"Mt |7Z  
    Function point_in(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single, ppx As Single, ppy As Single) As Boolean J^zB 5W,)  
    Dim aob, boc, cod, doa, sum As Single &td   
      If ppx = p1x And ppy = p1y Then WsT   
         point_in = True >|mZu)HIY;  
         Exit Function 0iKAg  
      End If s<5PsR  
      If ppx = p2x And ppy = p2y Then I(b]V!mj:  
         point_in = True | g"K7XfM4  
         Exit Function HIda%D  
      End If <VhD>4f{]  
       If ppx = p3x And ppy = p3y Then ),2|TlQ  
         point_in = True sYB2{w   
         Exit Function ;,xM*  
      End If k h6n(B\  
         GQ sE5Vb  
        aob = ff_angle(p1x, p1y, ppx, ppy, p2x, p2y)  p+-IvU  
        boc = ff_angle(p2x, p2y, ppx, ppy, p3x, p3y) /)sP<WPQ 6  
        cod = ff_angle(p3x, p3y, ppx, ppy, p4x, p4y) KfQ?b_H.  
        doa = ff_angle(p4x, p4y, ppx, ppy, p1x, p1y) D#[<N  
        sum = aob + boc + cod + doa u[nLrEnD  
        If 360.01 > sum And sum > 359.99 Then BW ux!  
           point_in = True RQ4+EW 1G  
        Else A.(e=;0bu  
           point_in = False GE=PaYz  
        End If L0Ajj=  
    End Function
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 5楼 发表于: 2013-04-08
    '得到点半径,得到交点坐标函数 0D0uzUD-  
    Function rr(p1x As Single, p1y As Single, p2x As Single, p2y As Single, p3x As Single, p3y As Single, p4x As Single, p4y As Single) As Single() z`,dEGfh^  
        '求得中心点坐标 lUw=YM  
    Dim tt As String h)s&Nqg1B  
    Dim rt(3) As Single @h(Z;  
        '判断是否平行 3mL(xpT.8z  
       acx = p3x - p1x )5u#'5I>  
       acy = p3y - p1y h~O^~"jc  
       bdx = p4x - p2x l nJ  
       bdy = p4y - p2y cv. j  
       If acx * bdy = acy * bdx Then V 7D<'!  
          rt(0) = 0 fP 3t0cp  
          Exit Function -J0I2D  
       Else _|#P~Ft  
          '判断斜率存在否 M|R\[ Zf  
          If p1x = p3x And p2x <> p4x Then Hm+VGH'H?  
             tt = "ac_n_bd_y" a6?t?: ~|  
          ElseIf p1x <> p3x And p2x = p4x Then !vuun |  
             tt = "ac_y_bd_n" 'r1X6?d J  
          ElseIf p1x <> p3x And p2x <> p4x Then /?a9g>G%N  
             tt = "ac_y_bd_y" ,l.+$G  
          End If [7  t  
        Select Case tt E:[!)UG|y  
             Case "ac_n_bd_y" /JIVp_-p  
                'bd线段方程 !E,|EdIr  
                k_bd = bdy / bdx tH:?aP*2  
                b_bd = p2y - k_bd * p2x [}4\CWM  
                p_x = p1x 09i7 7  
                p_y = k_bd * p_x + b_bd r4fd@<=g  
             Case "ac_y_bd_n" n^nQrRIp  
                'ac线段方程 yM7FR);  
                k_ac = acy / acx {c7@`AV]  
                b_ac = p1y - k_ac * p1x - %?> 1n  
                p_x = p2x Y oZd,} i  
                p_y = k_ac * p_x + b_ac XW+-E^d  
            Case "ac_y_bd_y" :*-O;Yw?S@  
               'ac,bd线段都要求 >f D%lq;  
               k_ac = acy / acx 5i'KGL  
               b_ac = p1y - k_ac * p1x =6N=5JePB  
               k_bd = bdy / bdx "B9zQ,[Q  
               b_bd = p2y - k_bd * p2x rddn"~lm1  
               p_x = -(b_bd - b_ac) / (k_bd - k_ac) @6-3D/=  
               p_y = k_ac * p_x + b_ac Jg$ NYs.xZ  
            End Select !/1 ~  
          rt(1) = p_x bPMf='F{r  
          rt(2) = p_y "#pN  
         WGo ryvEx  
    '计算最大半径 JB!*{{  
       rr1 = (p1x - p_x) * (p1x - p_x) + (p1y - p_y) * (p1y - p_y) #v4^,$k>  
       rr2 = (p2x - p_x) * (p2x - p_x) + (p2y - p_y) * (p2y - p_y) Y5*A,piq  
       rr3 = (p3x - p_x) * (p3x - p_x) + (p3y - p_y) * (p3y - p_y) YVk +zt~S  
       rr4 = (p4x - p_x) * (p4x - p_x) + (p4y - p_y) * (p4y - p_y) \aN5:Yy  
    Dim bb(5) As Single '1zC|:,  
      bb(1) = rr1 DLO#_t^v.  
      bb(2) = rr2 fT=ZiHJ3Gu  
      bb(3) = rr3 AP9\]qZ(7  
      bb(4) = rr4 U^-RyE!}  
      nb = rr1 )=5*iWe  
    For i = 1 To 4 }IQ![T5  
        If nb <= bb(i) Then mXu";?2  
           nb = bb(i) 5nK|0vv%2  
        End If ncpA\E;ff^  
    Next i ) }k"7"  
        rt(0) = Sqr(nb) @f-rS{  
        rr = rt() V1A7hRjxvG  
      End If S)"vyGv  
             ,S?:lQuK5  
    End Function
    离线lifei0715
    发帖
    1239
    光币
    8446
    光券
    0
    只看该作者 6楼 发表于: 2013-04-08
    高手啊.人才啊.
    离线safeng1122
    发帖
    286
    光币
    26
    光券
    0
    只看该作者 7楼 发表于: 2013-04-09
    回 lifei0715 的帖子
    lifei0715:高手啊.人才啊. (2013-04-08 19:15)  GZ"J6/0-|  
    N_E :?Jo  
    有热压工艺方面的人才或者资料分享下; 7me1 :}4  
    我公司主要做透镜类产品,现在有客户要审核我公司的导光膜工艺,头疼 .fS1  
    离线windcgp86
    发帖
    151
    光币
    39
    光券
    0
    只看该作者 8楼 发表于: 2013-04-10
    高手真多!
    离线allansweruni
    发帖
    100
    光币
    25
    光券
    0
    只看该作者 9楼 发表于: 2013-04-11
    楼主威武霸气.