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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 倒序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html X|y0pH:S  
    o)H| #9h5  
    其中使用Ghost focus generator后的结果为: 1czU$!MV  
    3lgD,_&  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx aUKa+"`S  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm )9+H[  
    Type: Double Bounces +B4i,]lCx  
    The '****' denotes a possible internal focus T^Hq 5Oy  
    RMS is the RMS spot radius on axis at the primary wavelength. }U**)"  
    RMS values of 0.00 indicate that an accurate RMS 9/O\769"'  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is \4uj!LgTb  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) hO(A_Bw  
    Surf     Marginal          F/#          RMS )Zrn?KM  
       1  5.0000E+000     5.737068  3.5355E+000 @`HW0Y_:  
       2  4.7160E+000     4.595701  3.3570E+000 _SQ]\Z  
       1  4.3614E+000     0.990012  3.1277E+000 /L` +  
       2  2.7155E+000     0.607262  1.9876E+000 % xBQX  
       3 -2.2309E+000     0.916280  2.6065E+000 ?Xq kf>  
       4 -2.7766E+000     0.514753  0.0000E+000 MgH O WoF  
       5 -7.3909E+000     0.888038  0.0000E+000 3 op{h6  
       6 -9.0530E+000     0.823473  0.0000E+000 %/RT}CBBsW  
       7 -3.4681E+001     0.823473  0.0000E+000 %%lJyLq'Vk  
    Marginal ray height    :       -34.6809 ~_ko$(;A  
    Chief ray height       :       -24.8107 cZAf?,>u  
    Distance to ghost pupil:       -50.9613 BuS[(  
    Distance to ghost focus:       -57.1176 H WFnIUv  
    Effective focal length :         8.2347
    .<6'*X R  
    请问这个结果怎么看? %\!@$]3q  
    *++}ll6  
    其中:Ghost reflection off surface 2 then 1,什么意思? ]MB6++.e  
    最后的光线高度能用来分析什么?? A9LVS&52  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 [2z >8 SL  
    Effective focal length : 8.2347 |43Oc:Ah+  
    这有代表什么,求高手啊
     
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    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? =lx~tSiS  
    _[N*k"  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好