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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 倒序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html +rX,Sl`/  
    ;OyM~T gI  
    其中使用Ghost focus generator后的结果为: /_(Dq8^g@  
    ylJlICK  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx gJ7pu N  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm }y/t~f+  
    Type: Double Bounces *?'T8yf^  
    The '****' denotes a possible internal focus \H(,'w7H  
    RMS is the RMS spot radius on axis at the primary wavelength. ~h.B\Sc]Q  
    RMS values of 0.00 indicate that an accurate RMS 5+Ut]AL5  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is S22; g  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) :b-(@a7>  
    Surf     Marginal          F/#          RMS jm"xf7  
       1  5.0000E+000     5.737068  3.5355E+000 y_#wR/E)u{  
       2  4.7160E+000     4.595701  3.3570E+000 `,"Jc<R7Z  
       1  4.3614E+000     0.990012  3.1277E+000 O}V2> W$  
       2  2.7155E+000     0.607262  1.9876E+000 mqw.v$>  
       3 -2.2309E+000     0.916280  2.6065E+000 -nSqB{s!SD  
       4 -2.7766E+000     0.514753  0.0000E+000 p04w 83 jX  
       5 -7.3909E+000     0.888038  0.0000E+000 bcNYoZ8`  
       6 -9.0530E+000     0.823473  0.0000E+000 8uiQm;W  
       7 -3.4681E+001     0.823473  0.0000E+000 nU)f]4q{Ec  
    Marginal ray height    :       -34.6809 EK^2 2vi$  
    Chief ray height       :       -24.8107 Az[z} r4  
    Distance to ghost pupil:       -50.9613 'r CR8>k  
    Distance to ghost focus:       -57.1176 q?\D9aT9  
    Effective focal length :         8.2347
    yAe}O#dy  
    请问这个结果怎么看? ER+[gT1CQ  
    \ZH=$c*W  
    其中:Ghost reflection off surface 2 then 1,什么意思? na)_8r~  
    最后的光线高度能用来分析什么?? b"b!&u  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 @<L.#gtP  
    Effective focal length : 8.2347 cs)hq4-L`  
    这有代表什么,求高手啊
     
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    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? QPn c "!  
    |u[gI+TUE  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好