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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 倒序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html fH_Xm :%  
    I]N!cEr;@-  
    其中使用Ghost focus generator后的结果为: "(E%JAwZ^W  
    Ns[.guWu-  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx d%ncI0f`  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm `b[@GGv  
    Type: Double Bounces bg,VK1  
    The '****' denotes a possible internal focus <V4"+5cJ8  
    RMS is the RMS spot radius on axis at the primary wavelength. KRj3??b  
    RMS values of 0.00 indicate that an accurate RMS P6 mDwR  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is boIFN;Aq"  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) 8X= 2#&)  
    Surf     Marginal          F/#          RMS -"n8Wv  
       1  5.0000E+000     5.737068  3.5355E+000 T;B/ Wm!x  
       2  4.7160E+000     4.595701  3.3570E+000 BlfW~l'mx  
       1  4.3614E+000     0.990012  3.1277E+000 ?B:],aztf  
       2  2.7155E+000     0.607262  1.9876E+000 lJBZ0  
       3 -2.2309E+000     0.916280  2.6065E+000 ]\J(  
       4 -2.7766E+000     0.514753  0.0000E+000 7e<\11uI]a  
       5 -7.3909E+000     0.888038  0.0000E+000 ~ePtK~,dv  
       6 -9.0530E+000     0.823473  0.0000E+000 o%73M!-  
       7 -3.4681E+001     0.823473  0.0000E+000 #4?:4Im#  
    Marginal ray height    :       -34.6809 3+:uV  
    Chief ray height       :       -24.8107 ny+_&l^R~(  
    Distance to ghost pupil:       -50.9613 ]"\XTL0  
    Distance to ghost focus:       -57.1176 FGRG?d4?h  
    Effective focal length :         8.2347
    Yk#$-"c/a  
    请问这个结果怎么看? <p8>"~ R  
    hHqsI`7c  
    其中:Ghost reflection off surface 2 then 1,什么意思? ;5}y7#4C  
    最后的光线高度能用来分析什么?? C= PV-Ul+  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 L"V~M F  
    Effective focal length : 8.2347 &Zm1(k6&K  
    这有代表什么,求高手啊
     
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    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? JWs?az  
     ,zrShliU  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好