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    [讨论]如何分析Ghost focus generator的结果 [复制链接]

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    离线sansummer
     
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    只看楼主 倒序阅读 楼主  发表于: 2011-06-27
    例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html u= ( kii=/  
    )|f!}( p  
    其中使用Ghost focus generator后的结果为: ?1 $.^  
    :|xV}  
    Ghost Trace Data
    File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx S5]rIcM  
    Title: A SIMPLE COOKE TRIPLET.
    Units are Millimeters.
    Wavelength: 0.550000 μm . Rxz;-VA  
    Type: Double Bounces l=%v  
    The '****' denotes a possible internal focus ipfiarT~)  
    RMS is the RMS spot radius on axis at the primary wavelength. 'bj$ZM9  
    RMS values of 0.00 indicate that an accurate RMS hH8:7i  
    could not be computed, usually due to ray errors.
    This analysis may be inaccurate if the system is - 8&M^-  
    non-rotationally symmetric or uses non-standard surfaces.
    Ghost reflection off surface 2 then 1. (GH002001.ZMX) )y-y-B=+T  
    Surf     Marginal          F/#          RMS RP&H9>  
       1  5.0000E+000     5.737068  3.5355E+000 rwr>43S5<3  
       2  4.7160E+000     4.595701  3.3570E+000 1cWUPVQ  
       1  4.3614E+000     0.990012  3.1277E+000 :N5R.@9  
       2  2.7155E+000     0.607262  1.9876E+000 8E1swH5 z  
       3 -2.2309E+000     0.916280  2.6065E+000 5'gV_U  
       4 -2.7766E+000     0.514753  0.0000E+000 ~0r:Wcj x  
       5 -7.3909E+000     0.888038  0.0000E+000 +K2jYgy  
       6 -9.0530E+000     0.823473  0.0000E+000 DWZ!B7Ts  
       7 -3.4681E+001     0.823473  0.0000E+000 xS]=WO*  
    Marginal ray height    :       -34.6809 [#V?]P\uV  
    Chief ray height       :       -24.8107 1t/#ZT!X/  
    Distance to ghost pupil:       -50.9613 G (Fi  
    Distance to ghost focus:       -57.1176 \'6hv>W@  
    Effective focal length :         8.2347
    BKe~ y  
    请问这个结果怎么看? ;_)&#X,?(  
    wN8-M e  
    其中:Ghost reflection off surface 2 then 1,什么意思? yU3fM?a  
    最后的光线高度能用来分析什么?? 0t ?:  
    Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 ?n9gqwO  
    Effective focal length : 8.2347 Dsc{- <v  
    这有代表什么,求高手啊
     
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    离线sansummer
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    只看该作者 1楼 发表于: 2011-06-27
    我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? AdDlS~\?  
    Xc -'&"  
    Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
    离线superyu2009
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    只看该作者 2楼 发表于: 2011-11-22
    用CODE V分析更好