[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? OOX[xv!b  

我這邊有一個zpl可以直看出來~ yM*f}S/ (  
如下: u8i!Fxu  
!RIH: CHIEF RAY HEIGHT ON IMA U8R*i7  
' lMPI@C6r  
!CRA: CHIEF RAY ANGLE IN IMA SPACE *Bm _  
_ -C{:rV  
!和取最?視角度 +{pS2I}d  
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MAXFIELD = MAXF() I<^&~==  
0}iND$6@a  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 "jMSF@lr  
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!獲曲面數 1o%E(*M4I  
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n = NSUR() { x/~gp
 
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!主光線錐激 &5o ln@YL  
G [$u`mxV^  
S"G`j!m1  
P\2UIAPa\b  
RAYTRACE  0, 1, 0, 0, PWAV() x|`o7.  
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9L9+zs3k  
T+U,?2nF:  
MAX_RIH = RAYY(n) @fO[{V  
EQ>]~  
U>=& 2Z2?  
F>/"If#  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   lD\v
q2  
ud,=O Xq  
C)xM>M_CB  
WXX)_L$2  
PRINT   "MAX FIELD: " , maxfield, TZYz`l+v  
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PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , sxFkpf_h  
2
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PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH ~s4o1^6L  
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nYbI =_-  
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PRINT "FIELD ",   0\2#(^  
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PRINT "CHIEF RAY ANGLE," O[O[E}8#  
5 i;n:&Y  
PRINT  "CHIEF RAY HEIGFHT ON IMA." @dx$&;w  
.T|1l$Jn  
TM2pE/P  
J.^%VnrFO9  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for 1'Y7h;\~\  
0` \!O(jJ  
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For j, 0, 20, 1 D +Ui1h-  
Ti!<{>  
FHY = j/20 7;x}W-`iF  
M
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RAYTRACE  0, FHY, 0, 0, PWAV() 8^>qzaf 8  
 mX&!/U  
CRA = ACOS(RAYN(n-1))*180/3.1416 nTQ&nu!  
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OLDX = CRA ! uX0G4  
FQW{c3%qZ  
OLDY = RAYY(n) vnOl-`Z ~  
O/1:2G/`  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY :7Jpt3  
0V[`zOO(o  
Y `ySNC  
(dgBI}Za  
~D1&CT#s  
5%1a!MM M  
NEXT O\&-3#e  
l`k""f69W  
!繪出該點數據 bji^b@us_  
!Un&OAy.!  
6#za\[  
-gK*&n~  
GRAPHICS dJ&f +  
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Z0#&D&2sV  
:N>n1tHL;A  
RAYTRACE 0, 1, 0, 0, PWAV() 8LH\a.>  
!)-)*T  
MAX_RIH = RAYY(n) wpI_yp  
X5w_ }Nhe  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 Uuq*;L  
yi&6HNb  
X_WIDE = XMAX() /1.6 3<R8_p  
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Y_WIDE = YMAX() /1.6 9^<Y~rkm  
Iy8fN"I9D  
SEGMENT = 40
odsLFU(  
DqN<bu2  
FOR j, 0, SEGMENT-1,1 0Q4i<4 XW  
>Sc/E}3  
:pXY/Pa  
\h48]ZjC`  
FHY = j/SEGMENT a4E{7c  
67D{^K"KT  
RAYTRACE 0, FHY, 0, 0, PWAV() [ @ASAhV^+  
V7(-<})8  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 LTlbrB  
-50Qy[0."  
RIH = RAYY(n) =;A>1g$  
Bj*\)lG<  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) `)WC|=w2  
 U!O"f  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) l?<DY$H 0  
;m#_Rj6  
wmB_)`QNP  
?R":"*eu  
t/B4?A@C  
s8V:;$ !  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() OuMj%
I  
[MXyOE  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 F!7\Za,  
WG]`Sy  
RIH = RAYY(n)      
'PWX19  
JA2oy09G  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) 0`KR8# A@  
f)1*%
zg%  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) T%]@R4z#q  
Zdy{e|-Zn  
>J) 9&?  
?M BOd9  
LINE OLDX,OLDY,NEWX,NEWY 8e"M
P\0V  
^y.|KA3[  
A$ = "0" eZ8DW6l*  
I_5[-9  
gtext OLDX,OLDY,0, A$ @~&1!  
LbUH`0:%t  
NEXT C8
KV<k  
%:N;+
1  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " t03T1.:(Mg  
UK5u"@T  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" 9c{T|+]  
7G=Q9^J.H  
^Eif~v  
Nnq r{ub  
GRAPHICS OFF QB"+B]rV  
xV"~?vD  

楼上的回答非常棒！谢谢分享这个宏！ C:.>*;?7  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 Q})&c.L  

学习了！！！！！！！！！！！！！！！！！！！

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