[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? S#l)|c_~  

我這邊有一個zpl可以直看出來~ hEAP,)>F  
如下: iJzW3%E  
!RIH: CHIEF RAY HEIGHT ON IMA 9`G}GU]@}  
e89IT*  
!CRA: CHIEF RAY ANGLE IN IMA SPACE NLZUAt
x(  
L87=*_!B;  
!和取最?視角度 7-c3^5gn{  
g>H\"cUv  
MAXFIELD = MAXF() rQ&F Gb  
Kbcr-89Gv~  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0  &W? hCr  
'/@i} digf  
!獲曲面數 M~-jPY,+  
0]2@T=*kTY  
n = NSUR() ?Bsc;:KF  
aKw7m={  
!主光線錐激 `:5W1D(  
&u0on)E  
E\XD~
 
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RAYTRACE  0, 1, 0, 0, PWAV() 89[OaT_hs  
y-vQ4G5F|  
^spASG-o  

Pql;5 ~/  
MAX_RIH = RAYY(n) Q9sxI}D )R  
N>',[4pJ|  
@mu=7_$U  
Fr]B]Hj  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   B/bS:  
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5 DvD  
c8M'/{4rH  
PRINT   "MAX FIELD: " , maxfield, sU;aA0kz  
H6i;MQ  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , kT4Oal+4  
laGIu0s{  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH ~k/GmH  
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!z?;L_Lb  
mW_ N-z  
PRINT "FIELD ",   0 A6%!h  
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PRINT "CHIEF RAY ANGLE," >l(|c9OWM  
5hE mXZ%  
PRINT  "CHIEF RAY HEIGFHT ON IMA." DeGcS1_?
 
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xJF}6yPm@  
#mH4\s  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for j$}W%ibj
 
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4'U #<8  
P> ilRb  
For j, 0, 20, 1 ys Td'J  
VT5o#NR{R  
FHY = j/20 cA2
5FD  
F;<cG`|Rx  
RAYTRACE  0, FHY, 0, 0, PWAV() bs\7 juHt  
)L%[(iI,x  
CRA = ACOS(RAYN(n-1))*180/3.1416 wsyAq'%L  
ewp&QH4  
OLDX = CRA G|.5.FK^  
Nk&$b  
OLDY = RAYY(n) O`Ge|4  
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PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY sboX<  
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5_= HtM[v]  
V~_aM@q1  
!%Qm{R  
:/941?%M  
NEXT 18kzR6(W  
8@- UvT&o  
!繪出該點數據 QzX|c&&>u2  
@>SirYh  
)%=oJ!)  
GV(@(bI*  
GRAPHICS {8Uk]   
cuW&X9\m,  
C6cEt5  
'}.Z' %;  
RAYTRACE 0, 1, 0, 0, PWAV() 9_<>#)u5  
Kitx%P`i  
MAX_RIH = RAYY(n) y{]iwO;  
@O Rk  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 mq*Efb)!  
c2d=dGP>~f  
X_WIDE = XMAX() /1.6 uf<nVdC.  
=TG[isC/F9  
Y_WIDE = YMAX() /1.6 hRKA,u/G  
5 Yf T
 
SEGMENT = 40 yPhTCr5pK  
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FOR j, 0, SEGMENT-1,1 ^ ;XJG9a0\  
T\Ld)'fNv  
>V1v.JH  
{e'V^l.v  
FHY = j/SEGMENT |H7f@b]Sk  
F;;\
I  
RAYTRACE 0, FHY, 0, 0, PWAV() I#U"DwM  
XlGDv*d:#d  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 LIZsDTU  
`bx}!;{lx  
RIH = RAYY(n) z c7P2@  
0.}WZAYy~  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) ]E!b&  
01/yog
 
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) FyV)Nmc%t  
Mp`2[S@$  
0k\BE\PQk  
cgevP`*]  
u>W:SM  
s8 c#_  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() [~#]p9|L  
sF+Bu'9
A  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 %;-]HI  
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RIH = RAYY(n)       >wOqV!0<  
AV%t<fDG#  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) ~M!s0jT  
1?}5.*j<  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) w%L::Z4  
7_*k<W7|  
3!:?OUhx  
ub,GF?9  
LINE OLDX,OLDY,NEWX,NEWY ;('(Yn7~  
9p{7x[C  
A$ = "0" y>YQx\mK
 
mOQN$d[  
gtext OLDX,OLDY,0, A$ ^< o"3?  
,KyG^;Riy  
NEXT Zj]jE%AT  
eNEMyv5{w4  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " i,z^#b7JQ  
8n1<nS<  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" 6< T@\E  
N&]GPl0  
@W+m;4HH  
ft"t  
GRAPHICS OFF wYLi4jYm  

0 P]+/  

楼上的回答非常棒！谢谢分享这个宏！ ;?K>dWf3f  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 @7j$$  

学习了！！！！！！！！！！！！！！！！！！！

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