[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? vPV=K+1  

我這邊有一個zpl可以直看出來~ H'L~8>  
如下: v\Y362Xv  
!RIH: CHIEF RAY HEIGHT ON IMA B/(]AWi+  
\&&jzU2  
!CRA: CHIEF RAY ANGLE IN IMA SPACE RaS7IL:e  
$_6DvJ0  
!和取最?視角度 6QCU:2IiL  
TZT1nj"n  
MAXFIELD = MAXF() _pXy}D  
FQbF)K~e  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 .}}w@NO  
Ax=k0%M[&  
!獲曲面數 .@Z-<P"  
;xnJ+$//U  
n = NSUR() 24T
Ql<H{  
(W<n<sl:-  
!主光線錐激 K%) K$/A  
2BU%4IG  
J~0_  
(f^K\7HM  
RAYTRACE  0, 1, 0, 0, PWAV()  xZ*.@Pkr  
[jD.l;jF  
`&.]>H)N*  
Z
/-!-  
MAX_RIH = RAYY(n) AwhXCq|k  
.c[v /SB]  
<z3:*=!  
S C8r.
  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   j5*W[M9W
 
.=WsB@+   
}c>[m,lz  
SBBDlr^P  
PRINT   "MAX FIELD: " , maxfield, kKV`9&d
Ze  
Rh7unJ
 
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , n
VqFCBB  
x[Xj[O  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH \:cr2w'c  
w<?v78sT  
%&L]k>n^  
<$WRc\}&g  
PRINT "FIELD ",   5*=a*nD11  
<lHelX=/  
PRINT "CHIEF RAY ANGLE," $a|D
R  
%KxL{HY  
PRINT  "CHIEF RAY HEIGFHT ON IMA." ?@"B:#l  
?QGAiu0  
k T$yHB #  
BJgg-z{Y  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for M<t>jM@'A#  
-G<$wh9~3  
Sb=cWn P  
J1I"H<}-6  
For j, 0, 20, 1 .6Sw
c?  
\Uun2.K  
FHY = j/20 Ol4)*/oZ  

-1ke3  
RAYTRACE  0, FHY, 0, 0, PWAV() zi~_[l-  
xU/Eu;m  
CRA = ACOS(RAYN(n-1))*180/3.1416 6,j6,Q(67  
_w+ix9Fr?  
OLDX = CRA Q ^%+r"h  
9QaEUy*,  
OLDY = RAYY(n) dQ97O{O:i  
<r (Y:2  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY }-H<wQ&x  
41y}n{4n8  
#/'5N|?  
o<f[K}t9  
_5I" %E;S  
JV|GEn\@N  
NEXT OM!CP'u#{  
%C*oy$.  
!繪出該點數據 y0vo-)E]-]  
>#z*gCO5,  
K8y/U(@|D  
IS0RhtGy/  
GRAPHICS f $MVgX  
45l/)=@@B  
1<_i7.{k  
riqvv1Nce  
RAYTRACE 0, 1, 0, 0, PWAV() RG=!,#X  
p:u?a,p  
MAX_RIH = RAYY(n) Ilvz@=  
0eY$K7 U  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 ai% fj*  
:_YpSw<Q  
X_WIDE = XMAX() /1.6 &) 7umdSgi  
@)mH"u!(7  
Y_WIDE = YMAX() /1.6 W!g'*L/#L  
n|F$qV_p\  
SEGMENT = 40 TCJH^gDt  
}0
c  
FOR j, 0, SEGMENT-1,1 \?)@ #Qs  
C.dN)?O  
`As
.1@  
e"^* ~'mJ  
FHY = j/SEGMENT Jq)!)={  
[i24$UT  
RAYTRACE 0, FHY, 0, 0, PWAV() /7
X:=~m  
'M2Jw8i  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 yjZxD[ Z  
B3u
v>\  
RIH = RAYY(n) &G?b|Tb2  
dV#h~  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) %\-u&  
0hK)/!Y  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) %76N$`{u  
U]Q2EL\%  
pulE6T7x  
'bj$ZM9  
}ex2tkz  
Ro`Hm8o/  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() )y-y-B=+T  
RP&H9>  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 rwr>43S5<3  
qJ!&H  
RIH = RAYY(n)       _ v\=ag  
-xtj:UO  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) zZDa71>  
lil1$K: i  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) 1Iu^
+  
;,n{6`  
I$v*SeVHE  
^yiRrcOo  
LINE OLDX,OLDY,NEWX,NEWY
hb7H- Z2  
::N'tcZ^2  
A$ = "0" * 3mF.^  
HjUs}#</  
gtext OLDX,OLDY,0, A$ pA9^-:\*  
^.
y}2  
NEXT 1I^[_ /_\y  
[5^"U+`{x  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " ^0ZabR'  
2:^Dv1J)rD  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" 37Vs9w  
d4F3!*@(  
:Zl@4}  
_M= \s>;G  
GRAPHICS OFF w$4fS
 
@D&VOJV  

楼上的回答非常棒！谢谢分享这个宏！ mnswGvY  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 }stc]L{79  

学习了！！！！！！！！！！！！！！！！！！！

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