[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? X@DW1<wEt  

我這邊有一個zpl可以直看出來~ ~.%HZzR6&  
如下: )|lxzlk  
!RIH: CHIEF RAY HEIGHT ON IMA MWh Y&I+  
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!CRA: CHIEF RAY ANGLE IN IMA SPACE Xv-p7$?f  
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!和取最?視角度 D:_W;b)  
w]0@V}}u$o  
MAXFIELD = MAXF() s;Gd`-S>d  
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IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 aZWj52  
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!獲曲面數 \x}\)m_7M<  
IFp%Ta  
n = NSUR() lhGJ/By- -  
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!主光線錐激 3T2]V?   
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u=.8
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RAYTRACE  0, 1, 0, 0, PWAV() eThaH0  
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Y_JQPup  
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MAX_RIH = RAYY(n) Q
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LjI`$r.B  
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MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   QrYF Lh  
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Re,;$_6o  
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PRINT   "MAX FIELD: " , maxfield, $4nAb^/  
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PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , Jb QK$[z"  
8s1nE_3  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH v'W{+>.  
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cFUD$mp  
Y![Q1D!  
PRINT "FIELD ",   AW]\n;f  
D'g,<-ahl  
PRINT "CHIEF RAY ANGLE," v675C#l(  
.kT]^rv ;  
PRINT  "CHIEF RAY HEIGFHT ON IMA." 6 c
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!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for sQJ\{'g  
!dLu($P  
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gP2zDI   
For j, 0, 20, 1 h?mDtMCw2  
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FHY = j/20 o(*\MTt?  
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RAYTRACE  0, FHY, 0, 0, PWAV() +\eJxyO  
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CRA = ACOS(RAYN(n-1))*180/3.1416 e"E8BU  
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OLDX = CRA fiGTI}=P  
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OLDY = RAYY(n) yw^P
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*~#I5s\s!  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY 2u3Kyn  
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)+-R  
-DI >O/  
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NEXT \V? .^/  
B=|R?t(*  
!繪出該點數據 V]7/hN-Y}  
qSY\a\.<  
4V@%Y,:ee  
YYWD\Y`8  
GRAPHICS ZQ`8RF *v  
6/UOzV,[  
%_(vSpk  
A@A8xn%  
RAYTRACE 0, 1, 0, 0, PWAV() I\l&'Q^0@  
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MAX_RIH = RAYY(n) r2-iISxg+  
dyQ7@K.E  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 jPWONz(#  
67j kU!  
X_WIDE = XMAX() /1.6 .S k+"iH5  
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Y_WIDE = YMAX() /1.6 .n8R%|C5  
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SEGMENT = 40 ;s+/'(*  
jSI1t
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FOR j, 0, SEGMENT-1,1 };Q}C0E  
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mskG2mA  
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FHY = j/SEGMENT q[s,
q3n~  
b}! cEJY  
RAYTRACE 0, FHY, 0, 0, PWAV() Kb;*"@LX  
kWr1>})'  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 K[T0);hZR  
Z(MZbzY7Hq  
RIH = RAYY(n) hek+zloB+  
Y@FYo>0O  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) T`#nn|  
N:`_Vl  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) u?,>yf.;s  
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<"3q5ic/Z  
q{w|`vIb  
%]P{)*y-?  
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RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() tA(oD4H9  
d"|_NG`vr  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 EQyX!  
mP)bOAU  
RIH = RAYY(n)       a6Vfd&  
7
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NEWX = X_WIDE * (CRA/MAX_CRA+2/20) PzJ(Q  
o/-RGLzAo  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) #9GfMxH  
8a6.77c  
=%U&$d|@G  
utck{]P  
LINE OLDX,OLDY,NEWX,NEWY ?mNB:-Q  
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A$ = "0"  q0ktABB  
tl dK@!E3  
gtext OLDX,OLDY,0, A$ 2J=`"6c  
c/$].VG0  
NEXT V Rv4p5  
i*$+>3Q-  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " !/G}vu  
i$kB6B#==  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" +.Vh<:?
 
2)IM<rf'^  
dNR/|  
<lzC|>BG  
GRAPHICS OFF p@pb[Bx~[  
ZV{C9S&  

楼上的回答非常棒！谢谢分享这个宏！ }@LIb<Y  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 }Bv1fbD4U  

学习了！！！！！！！！！！！！！！！！！！！

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