[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? x'?p?u~[  

我這邊有一個zpl可以直看出來~ \p.yR.  
如下: F_-xp1|  
!RIH: CHIEF RAY HEIGHT ON IMA xR kw+  
.Mb0++% W  
!CRA: CHIEF RAY ANGLE IN IMA SPACE |qj"p  
4sORp^t'Q  
!和取最?視角度 g5pFr=NV  
;ow)N <Z  
MAXFIELD = MAXF() Sx J0Y8#z  
!x ~s`z  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 ZI1]B944ni  
7T6Zlp  
!獲曲面數 cNwHY Z'  
xk/-TXB 0  
n = NSUR() 7q;`~tbC  
-G/qfd|s/  
!主光線錐激 Q
nP3U  
^Lc\{,m  
<FU?^
*~  
]&P\|b1*g  
RAYTRACE  0, 1, 0, 0, PWAV() H#V&5|K%  
ZB)R4  
;ltk}hJ]
 
eCsk\f`  
MAX_RIH = RAYY(n) Y-y yg4JH  
^vT!24sK  
RjvW*'2G  
~ffT
}q7^  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   !Tv3WQ@  
3+uL@LXd  
x$o^;2Z  
?$)5NQB%  
PRINT   "MAX FIELD: " , maxfield, \$.{*f   
3TCRCz  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , ojlyW})$%  
2YKa <?_  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH 9`N5$;NzY  
$F# 5/gDVQ  
ZfqN4  
[yk-<}#B  
PRINT "FIELD ",   6*>Lud  
7XyCl&Dc:  
PRINT "CHIEF RAY ANGLE," 4LB8p7$|a3  
%EVgSF!r  
PRINT  "CHIEF RAY HEIGFHT ON IMA." ^s7!F.OC  
h ':ZF  
Mhti  
54z.@BJhE  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for ZGR5"el!  
0stc$~~v  
HLwMo&*rA  
ML\>TDt  
For j, 0, 20, 1 r*l3Hrho~K  
PgK7CG7G  
FHY = j/20 ;TWLo_  
p+V#86(3  
RAYTRACE  0, FHY, 0, 0, PWAV() "t.`/4R2w  
gHstdp_3  
CRA = ACOS(RAYN(n-1))*180/3.1416 f!#!  
@lE'D":?  
OLDX = CRA ;mk[!  
c'eZ-\d{  
OLDY = RAYY(n) sNo8o1Hby  
jO&*E'pk  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY \/Mx|7<  
iI IXv  
gd*Gn"  
[#q>Aq$11  
+ tMf&BZ  
Q&I`uS=F  
NEXT C{zp8 A(Dh  
,?|$DY+=  
!繪出該點數據 yzhNl'Rz  
v wEbGx  
\\FT.e
6  
/gZyl|kdy  
GRAPHICS <ErX<(0`ig  
, [|aWT%9  
MY@&^71i4  
zd=O;T;.  
RAYTRACE 0, 1, 0, 0, PWAV() _rwJ:r  
RTm/-6[N  
MAX_RIH = RAYY(n) |R0f--;  
c[,h|~K/_?  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 PVo7Sy!'H  
D=#RQ-  
X_WIDE = XMAX() /1.6 ~Ba=nn8Cq  
K"0IWA  
Y_WIDE = YMAX() /1.6 (jc& F
k  
{p84fR1P  
SEGMENT = 40 XnQR(r)pR2  
g F*AS(9  
FOR j, 0, SEGMENT-1,1 g|>LT_  
CBEf;I
g  
XVN`J]XHk  
!5o j~H  
FHY = j/SEGMENT @x}"aJgl  
__g k:a>oQ  
RAYTRACE 0, FHY, 0, 0, PWAV() }uZs)UQ|$  
>[fu&r1  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 |vI`u[P  
R c+olJ^5  
RIH = RAYY(n) SMX]JZmH  
Y_JQPup  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) _B0(1(M<2  
 K& #il  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) <&3P\aM>  
{]T?)!Vm  
6Wu*zY_+  
JLoF!MK}  

<q'l7S  
4dX{an]Cz  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() /;*_[g5*i  
,CfslhO{j  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 k QuEG5n.-  
X4 Arn,  
RIH = RAYY(n)       rAH!%~  
lG7PM^Eb
 
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) tVAi0`DV  
 w4U,7%V  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) AW]\n;f  
zjpZ] $  
3p0v  
xb,XI/
 
LINE OLDX,OLDY,NEWX,NEWY yLnQ9BXB&  
_K^Q]V[nZ  
A$ = "0" #-0e0  
VdlT+'HF  
gtext OLDX,OLDY,0, A$ kxMvOB$  
 LR97FG  
NEXT z'YWomfZm  
YM}a>o  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " .-d'*$ yJ  
aM}9ZurI  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" *f[5rr4  
D*M `qPX~  
*w+'I*QSt~  
R}nvSerVb  
GRAPHICS OFF aLa<zEssz  
IO\l8G  

楼上的回答非常棒！谢谢分享这个宏！ O^L]2BVC  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 pY31qhoZ.  

学习了！！！！！！！！！！！！！！！！！！！

用宏指令看

什么事宏指令

这个宏厉害了

这个宏厉害了