[求助]求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [复制链接]

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? }CnqJ@>C5  

我這邊有一個zpl可以直看出來~ g^ZsV:D  
如下: eSo/1D  
!RIH: CHIEF RAY HEIGHT ON IMA ~L$B]\/A5  
3mKmd iD  
!CRA: CHIEF RAY ANGLE IN IMA SPACE v'nM=  
P=PcO>  
!和取最?視角度 )';Rb$<Qn  
iU3)4(R  
MAXFIELD = MAXF() Seh[".l  
g /D@/AU1u  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0  $0>>Z  
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!獲曲面數 ]v
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Z0*Lm+d9z  
n = NSUR() 3Z=OUhn9  
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!主光線錐激 c&r8q]u  
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,0+%ji^V  
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RAYTRACE  0, 1, 0, 0, PWAV() ?&#z3c$}  
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v Yt-Nx  
MAX_RIH = RAYY(n) 3]xe7F'`  
lg` Qi&  
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P'f0KZL;  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   b<,Z^Z_  
2,,zN-9mt  
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^.bYLF  
PRINT   "MAX FIELD: " , maxfield, "#bL/b'{  
Pw:(X0@  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , sute%6yM  
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PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH *>Sb4:  
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PRINT "FIELD ",   Wy^43g38'p  
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PRINT "CHIEF RAY ANGLE," :&D>?{b0  
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PRINT  "CHIEF RAY HEIGFHT ON IMA."  E~oQ%X~  
0{M=^96  
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!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for 7oY}=281  
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For j, 0, 20, 1 &t)dE7u
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YrAaL"20  
FHY = j/20 lK;/97Ze  
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RAYTRACE  0, FHY, 0, 0, PWAV() 8joJe>9VJ  
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CRA = ACOS(RAYN(n-1))*180/3.1416 -$Bom  
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OLDX = CRA w)I!q&`Y  
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OLDY = RAYY(n) uv*OiB"  
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PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY \(UEjlo  
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7{=<_  
GRpS^%8i@  
:ie7HF  
(WT0j  
NEXT Bkg/A;H  
4ujw/`:/m  
!繪出該點數據 C~o6]'+F_  
X\3IY:Q@T  
1B~H*=t4h  
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GRAPHICS 3UeG>5R  
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y7M"Dr%t^  
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RAYTRACE 0, 1, 0, 0, PWAV() YpQ/ )fSEV  
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MAX_RIH = RAYY(n) zRyZrt,%&  
2YvhzL[um  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 #5HJW[9  
$I(2}u?1+d  
X_WIDE = XMAX() /1.6 9:0JWW^so  
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Y_WIDE = YMAX() /1.6 d!) &@k  
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SEGMENT = 40 k,0RpE  
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FOR j, 0, SEGMENT-1,1 @DK,ka(  
w
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:w_J/k5Zd  
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FHY = j/SEGMENT O?Xg%k#  
`T $lTP  
RAYTRACE 0, FHY, 0, 0, PWAV() $x;wnXXXM  
_$/(l4\T[  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 yI\  
k^I4z^O=-;  
RIH = RAYY(n) xy`aR< L  
(1\!6  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) j6Acd~y\2  
c0ET]  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) ,vP9
oY[n  
w#_xV =  
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R:YX{Tq  
DV +DJcF  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() l'-dB  
6TS+z7S81L  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 !pl<  
xin<.)!E  
RIH = RAYY(n)       04NI.Jv  
QFIdp R.  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) Dw  
 
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NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) S*rgYe!E  
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lwPK^)|}  
LINE OLDX,OLDY,NEWX,NEWY 7)G- EAF  
?m#X";^V  
A$ = "0" 2Jrr;"r  
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gtext OLDX,OLDY,0, A$ {6'5K U*RH  
: :8UVLX  
NEXT {c
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> taT;[Oa  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " ]hTYh^'e  
x, a[ p\1  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" rs2~spN;h  
ga^O
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[qlq&?"  
YMLo~j4J  
GRAPHICS OFF 0wXfu"E{  
\tLJ( <8  

楼上的回答非常棒！谢谢分享这个宏！ 8e)k5[\m  
还有一个简单的方法，利用Ray Trace观察主光线的ray angle以及imaging height，参见http://www.opticsky.cn/read-htm-tid-51156.html，此贴介绍的很详细。 }
Y[Z`w  

学习了！！！！！！！！！！！！！！！！！！！

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