[求助]请教：Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别？ [复制链接]

在Tracepro的照度图选项中有一项“Normalize to emitted flux”，选择和不选择的情况出来的照度图有什么区别？哪位能详细解答一下。 |YMzp8Da(  

图片:未命名.JPG

说明书：规范从所有发光源发出的所有出射通量给图的数据，这个选项允许你使通量和光照规范为总共的通量，如果这个框被选中后，TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率，会非常有用。 l#<}|b  
也就是说，比如你的总光源有10lm，得出的照度图在没有选择norm～选项的时候是显示正常的照度，在勾选了之后显示的照度值是原来的/总流明，可以认为是没流明所产生的照度值

谢谢版主的耐心解答，^_^

suezl9 S &lTKYP  
哈哈

有中文说明书么？可以共享一下么？

Normalize }.|5S+J?[  
Normalize the map data to the total emitted flux from all sources. >^\>-U|  
This option allows you to have the flux and irradiance normalized to the total He_(JXTP  
emitted flux. When this box is checked, TracePro divides the values in the q?]@' ^:;  
irradiance map and the total flux by the emitted flux. This is especially useful for '?>O  
calculating system transmittance for an optical system, or lighting efficiency for a i7!mMO8]  
lighting calculation. (l!D=qy  
Example 1: System Transmittance AqKx3p6  
Suppose you need to calculate the system transmittance of an optical system. |I^Jn@Mq:  
You would probably use the grid raytrace option, and the emitted flux is equal to )PoI~km  
the sum of the flux in all the emitted rays. When you display an irradiance map, zhm!sMlO  
the system transmittance is equal to the total flux, displayed at the bottom of the Jc#)T;#6  
irradiance map window, divided by the emitted flux. To get the system FC-*?  
transmittance, check the Normalize to emitted flux box and press the Apply $$;2jX"I  
button. The map will be redisplayed, and the Normalized Flux value will be equal "M#`y!__  
to the system transmittance. HF=C8ZtlL  
Example 2: Lighting Efficiency a4qpnr]0  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating 0N[DV]  
a plane. You would probably choose the Surface Source raytrace option, and the ~JRuMP  
emitted flux is equal to the flux you specified when you defined the sources. When 96E7hp !:  
you display an irradiance map, the total flux incident on the observation plane is iF_r'+j  
displayed at the bottom of the window. The lighting efficiency is equal to the total D.CsnfJ  
flux divided by the emitted flux. To get the lighting efficiency directly, check the c:_i)":  
Normalize to emitted flux box and press the Apply button. The map will be <7-,`   
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency r~!%w(N|M  
of the luminaire.

可以看成均匀性吗？