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    [求助]请教:Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别? [复制链接]

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    离线ruskie
     
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    只看楼主 倒序阅读 楼主  发表于: 2008-05-10
    Tracepro照度图选项中有一项“Normalize to emitted flux”,选择和不选择的情况出来的照度图有什么区别?哪位能详细解答一下。 ldGojnS  
     
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    离线suezl9
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    只看该作者 1楼 发表于: 2008-05-12
    说明书:规范从所有发光源发出的所有出射通量给图的数据,这个选项允许你使通量和光照规范为总共的通量,如果这个框被选中后,TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率,会非常有用。 y500Xs[c  
    也就是说,比如你的总光源有10lm,得出的照度图在没有选择norm~选项的时候是显示正常的照度,在勾选了之后显示的照度值是原来的/总流明,可以认为是没流明所产生的照度值
    离线ruskie
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    只看该作者 2楼 发表于: 2008-05-13
    谢谢版主的耐心解答,^_^
    离线qiudonglai
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    只看该作者 3楼 发表于: 2008-08-19
    suezl9 ]ikomCg   
    哈哈
    离线norrin
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    只看该作者 4楼 发表于: 2008-08-21
    有中文说明书么?可以共享一下么?
    离线lightgirl
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    只看该作者 5楼 发表于: 2008-08-22
    Normalize *sw7niw  
    Normalize the map data to the total emitted flux from all sources. CZ<~3bEF  
    This option allows you to have the flux and irradiance normalized to the total q.#[TI ^  
    emitted flux. When this box is checked, TracePro divides the values in the px;/8c-  
    irradiance map and the total flux by the emitted flux. This is especially useful for w Y   
    calculating system transmittance for an optical system, or lighting efficiency for a ->^~KVh&  
    lighting calculation. %dST6$Z  
    Example 1: System Transmittance 5kypMHJm  
    Suppose you need to calculate the system transmittance of an optical system. FQz?3w&ia  
    You would probably use the grid raytrace option, and the emitted flux is equal to +pm[f["C.  
    the sum of the flux in all the emitted rays. When you display an irradiance map, A3N]8?D  
    the system transmittance is equal to the total flux, displayed at the bottom of the 8~lIe:F-  
    irradiance map window, divided by the emitted flux. To get the system }x0- V8  
    transmittance, check the Normalize to emitted flux box and press the Apply =sJ _yq0#R  
    button. The map will be redisplayed, and the Normalized Flux value will be equal 4Y> Yi*n  
    to the system transmittance. %V`F!D<D  
    Example 2: Lighting Efficiency I` K$E/ns  
    Suppose you need to calculate the lighting efficiency of a luminaire in illuminating Yap?^&GV  
    a plane. You would probably choose the Surface Source raytrace option, and the *l+OlQI0+  
    emitted flux is equal to the flux you specified when you defined the sources. When B+d<F[ |  
    you display an irradiance map, the total flux incident on the observation plane is *^\HU=&  
    displayed at the bottom of the window. The lighting efficiency is equal to the total *OJ/V O  
    flux divided by the emitted flux. To get the lighting efficiency directly, check the 51C2u)HE  
    Normalize to emitted flux box and press the Apply button. The map will be <h).fX  
    redisplayed, and the Normalized Flux value will be equal to the lighting efficiency oX@ya3!Pz  
    of the luminaire.
    离线kaoyanming
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    只看该作者 6楼 发表于: 2015-06-02
    可以看成均匀性吗?