[求助]请教：Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别？ [复制链接]

在Tracepro的照度图选项中有一项“Normalize to emitted flux”，选择和不选择的情况出来的照度图有什么区别？哪位能详细解答一下。 FPM l;0{  

说明书：规范从所有发光源发出的所有出射通量给图的数据，这个选项允许你使通量和光照规范为总共的通量，如果这个框被选中后，TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率，会非常有用。 Mz\l C)\B  
也就是说，比如你的总光源有10lm，得出的照度图在没有选择norm～选项的时候是显示正常的照度，在勾选了之后显示的照度值是原来的/总流明，可以认为是没流明所产生的照度值

谢谢版主的耐心解答，^_^

suezl9 w4M;e;8m[U  
哈哈

有中文说明书么？可以共享一下么？

Normalize e<[ ] W4"A  
Normalize the map data to the total emitted flux from all sources. Z*Gf`d:  
This option allows you to have the flux and irradiance normalized to the total >P&1or)e%  
emitted flux. When this box is checked, TracePro divides the values in the fc9@l a  
irradiance map and the total flux by the emitted flux. This is especially useful for -esQyLx  
calculating system transmittance for an optical system, or lighting efficiency for a 7D4tuXUq2  
lighting calculation. Ak8Y?#"wz  
Example 1: System Transmittance ! Dj2/][  
Suppose you need to calculate the system transmittance of an optical system. #<ST.f@*  
You would probably use the grid raytrace option, and the emitted flux is equal to RS l*u[fB  
the sum of the flux in all the emitted rays. When you display an irradiance map, 7nFOVZ  
the system transmittance is equal to the total flux, displayed at the bottom of the $/B~bJC  
irradiance map window, divided by the emitted flux. To get the system P^48]Kj7  
transmittance, check the Normalize to emitted flux box and press the Apply
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button. The map will be redisplayed, and the Normalized Flux value will be equal XM
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to the system transmittance. cD}]4  
Example 2: Lighting Efficiency X2rKH$<g  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating "H<us?r{  
a plane. You would probably choose the Surface Source raytrace option, and the 7CvBE;i  
emitted flux is equal to the flux you specified when you defined the sources. When <aDZ{T%  
you display an irradiance map, the total flux incident on the observation plane is ~!!|#A)W  
displayed at the bottom of the window. The lighting efficiency is equal to the total K,$rG%czX  
flux divided by the emitted flux. To get the lighting efficiency directly, check the $LFL4Q  
Normalize to emitted flux box and press the Apply button. The map will be /XEW]/4  
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency }v4dOGc?  
of the luminaire.

可以看成均匀性吗？