[求助]请教：Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别？ [复制链接]

在Tracepro的照度图选项中有一项“Normalize to emitted flux”，选择和不选择的情况出来的照度图有什么区别？哪位能详细解答一下。 Z#}sK5s  

图片:未命名.JPG

说明书：规范从所有发光源发出的所有出射通量给图的数据，这个选项允许你使通量和光照规范为总共的通量，如果这个框被选中后，TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率，会非常有用。 bkdXBCBx?  
也就是说，比如你的总光源有10lm，得出的照度图在没有选择norm～选项的时候是显示正常的照度，在勾选了之后显示的照度值是原来的/总流明，可以认为是没流明所产生的照度值

谢谢版主的耐心解答，^_^

suezl9 $W|JQ h  
哈哈

有中文说明书么？可以共享一下么？

Normalize |?jgjn&RQ  
Normalize the map data to the total emitted flux from all sources. (su7*$wV  
This option allows you to have the flux and irradiance normalized to the total e,#w*|  
emitted flux. When this box is checked, TracePro divides the values in the D0 k ,8|  
irradiance map and the total flux by the emitted flux. This is especially useful for KRGj6g+  
calculating system transmittance for an optical system, or lighting efficiency for a :kcqf,7  
lighting calculation. ]4B;M Ym*  
Example 1: System Transmittance Z[[*:9rY|  
Suppose you need to calculate the system transmittance of an optical system. UQkd$w<  
You would probably use the grid raytrace option, and the emitted flux is equal to 3_G0eIE"u  
the sum of the flux in all the emitted rays. When you display an irradiance map, #3ZAMV  
the system transmittance is equal to the total flux, displayed at the bottom of the <- sr&  
irradiance map window, divided by the emitted flux. To get the system hwk] ;6[  
transmittance, check the Normalize to emitted flux box and press the Apply B!<B7Q  
button. The map will be redisplayed, and the Normalized Flux value will be equal _=x*yDPG}  
to the system transmittance. /)v+|%U  
Example 2: Lighting Efficiency DMA7eZf'Hv  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating <gX({FA  
a plane. You would probably choose the Surface Source raytrace option, and the Hwd^C2v  
emitted flux is equal to the flux you specified when you defined the sources. When @Wd(>*"zw  
you display an irradiance map, the total flux incident on the observation plane is 29 !QE>Q  
displayed at the bottom of the window. The lighting efficiency is equal to the total CUdpT$$x3  
flux divided by the emitted flux. To get the lighting efficiency directly, check the UazK0{t<f  
Normalize to emitted flux box and press the Apply button. The map will be )M.g<[=^  
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency o *U-.&  
of the luminaire.

可以看成均匀性吗？