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    [求助]请教:Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别? [复制链接]

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    离线ruskie
     
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    只看楼主 倒序阅读 楼主  发表于: 2008-05-10
    Tracepro照度图选项中有一项“Normalize to emitted flux”,选择和不选择的情况出来的照度图有什么区别?哪位能详细解答一下。 CZ>Ujw=&k  
     
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    离线suezl9
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    只看该作者 1楼 发表于: 2008-05-12
    说明书:规范从所有发光源发出的所有出射通量给图的数据,这个选项允许你使通量和光照规范为总共的通量,如果这个框被选中后,TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率,会非常有用。 f{u S  
    也就是说,比如你的总光源有10lm,得出的照度图在没有选择norm~选项的时候是显示正常的照度,在勾选了之后显示的照度值是原来的/总流明,可以认为是没流明所产生的照度值
    离线ruskie
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    只看该作者 2楼 发表于: 2008-05-13
    谢谢版主的耐心解答,^_^
    离线qiudonglai
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    只看该作者 3楼 发表于: 2008-08-19
    suezl9 [Dmf.PUe  
    哈哈
    离线norrin
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    只看该作者 4楼 发表于: 2008-08-21
    有中文说明书么?可以共享一下么?
    离线lightgirl
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    只看该作者 5楼 发表于: 2008-08-22
    Normalize J HV  
    Normalize the map data to the total emitted flux from all sources. !89hO4 0r  
    This option allows you to have the flux and irradiance normalized to the total fzAkUvo  
    emitted flux. When this box is checked, TracePro divides the values in the N P5K1:  
    irradiance map and the total flux by the emitted flux. This is especially useful for )J2UNIgN  
    calculating system transmittance for an optical system, or lighting efficiency for a r=p^~tuyxr  
    lighting calculation. /b/  6*&  
    Example 1: System Transmittance J,s:CBCGL  
    Suppose you need to calculate the system transmittance of an optical system. B]mMwqM#  
    You would probably use the grid raytrace option, and the emitted flux is equal to : #so"O  
    the sum of the flux in all the emitted rays. When you display an irradiance map, P m&^rC;  
    the system transmittance is equal to the total flux, displayed at the bottom of the w'7J`n: {]  
    irradiance map window, divided by the emitted flux. To get the system m9 ]Ge]  
    transmittance, check the Normalize to emitted flux box and press the Apply 2L51 H(  
    button. The map will be redisplayed, and the Normalized Flux value will be equal 4vkqe6  
    to the system transmittance. DJqJ6z:'  
    Example 2: Lighting Efficiency QIJ/'72  
    Suppose you need to calculate the lighting efficiency of a luminaire in illuminating L"0?g(< 5  
    a plane. You would probably choose the Surface Source raytrace option, and the 4r86@^c*  
    emitted flux is equal to the flux you specified when you defined the sources. When g_?Q3  
    you display an irradiance map, the total flux incident on the observation plane is c `.BN(  
    displayed at the bottom of the window. The lighting efficiency is equal to the total 9E4^hkD&  
    flux divided by the emitted flux. To get the lighting efficiency directly, check the \'|t>|zhp  
    Normalize to emitted flux box and press the Apply button. The map will be g1]bI$;  
    redisplayed, and the Normalized Flux value will be equal to the lighting efficiency 2OqEyXh  
    of the luminaire.
    离线kaoyanming
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    只看该作者 6楼 发表于: 2015-06-02
    可以看成均匀性吗?