[求助]请教：Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别？ [复制链接]

在Tracepro的照度图选项中有一项“Normalize to emitted flux”，选择和不选择的情况出来的照度图有什么区别？哪位能详细解答一下。 Z?=o(hkd  

图片:未命名.JPG

说明书：规范从所有发光源发出的所有出射通量给图的数据，这个选项允许你使通量和光照规范为总共的通量，如果这个框被选中后，TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率，会非常有用。 ^J hs/HV  
也就是说，比如你的总光源有10lm，得出的照度图在没有选择norm～选项的时候是显示正常的照度，在勾选了之后显示的照度值是原来的/总流明，可以认为是没流明所产生的照度值

谢谢版主的耐心解答，^_^

suezl9 '4#NVXVQm  
哈哈

有中文说明书么？可以共享一下么？

Normalize Wql=PqF  
Normalize the map data to the total emitted flux from all sources. r7}KV| M  
This option allows you to have the flux and irradiance normalized to the total N`H`\+  
emitted flux. When this box is checked, TracePro divides the values in the 2{l|<'  
irradiance map and the total flux by the emitted flux. This is especially useful for
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calculating system transmittance for an optical system, or lighting efficiency for a ~Hg*vCd ?  
lighting calculation. D8E^[w!  
Example 1: System Transmittance ]xb2W~  
Suppose you need to calculate the system transmittance of an optical system. $Fc}K+  
You would probably use the grid raytrace option, and the emitted flux is equal to `<T4
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the sum of the flux in all the emitted rays. When you display an irradiance map, ~^'t70 :D  
the system transmittance is equal to the total flux, displayed at the bottom of the ? ][/hL@[  
irradiance map window, divided by the emitted flux. To get the system }c=Y<Cdh  
transmittance, check the Normalize to emitted flux box and press the Apply *'M+oi  
button. The map will be redisplayed, and the Normalized Flux value will be equal J%q)6&  
to the system transmittance. k[<i+C";  
Example 2: Lighting Efficiency m8b-\^eP7  
Suppose you need to calculate the lighting efficiency of a luminaire in illuminating k'e1ZAn  
a plane. You would probably choose the Surface Source raytrace option, and the 5oB#{
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emitted flux is equal to the flux you specified when you defined the sources. When 4~oRcO8!Y  
you display an irradiance map, the total flux incident on the observation plane is kDQE*o  
displayed at the bottom of the window. The lighting efficiency is equal to the total DW7Jk"\GH  
flux divided by the emitted flux. To get the lighting efficiency directly, check the 1_9Ka V  
Normalize to emitted flux box and press the Apply button. The map will be 9X#]Lg?b  
redisplayed, and the Normalized Flux value will be equal to the lighting efficiency bYhG`1,$-a  
of the luminaire.

可以看成均匀性吗？