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    [求助]请教:Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别? [复制链接]

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    离线ruskie
     
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    只看楼主 倒序阅读 楼主  发表于: 2008-05-10
    Tracepro照度图选项中有一项“Normalize to emitted flux”,选择和不选择的情况出来的照度图有什么区别?哪位能详细解答一下。 w/*G!o- <  
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    离线suezl9
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    只看该作者 1楼 发表于: 2008-05-12
    说明书:规范从所有发光源发出的所有出射通量给图的数据,这个选项允许你使通量和光照规范为总共的通量,如果这个框被选中后,TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率,会非常有用。 ]oV{JR]  
    也就是说,比如你的总光源有10lm,得出的照度图在没有选择norm~选项的时候是显示正常的照度,在勾选了之后显示的照度值是原来的/总流明,可以认为是没流明所产生的照度值
    离线ruskie
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    只看该作者 2楼 发表于: 2008-05-13
    谢谢版主的耐心解答,^_^
    离线qiudonglai
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    只看该作者 3楼 发表于: 2008-08-19
    suezl9 *eoH"UFYQ#  
    哈哈
    离线norrin
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    只看该作者 4楼 发表于: 2008-08-21
    有中文说明书么?可以共享一下么?
    离线lightgirl
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    只看该作者 5楼 发表于: 2008-08-22
    Normalize .9vS4C  
    Normalize the map data to the total emitted flux from all sources. &tZIWV1&  
    This option allows you to have the flux and irradiance normalized to the total U6/7EOW,  
    emitted flux. When this box is checked, TracePro divides the values in the ?IAu,s*u  
    irradiance map and the total flux by the emitted flux. This is especially useful for `e,}7zGR  
    calculating system transmittance for an optical system, or lighting efficiency for a [`GSc6j  
    lighting calculation. 1TQ?Fxj  
    Example 1: System Transmittance o)5zvnu7  
    Suppose you need to calculate the system transmittance of an optical system. anW['!T9{s  
    You would probably use the grid raytrace option, and the emitted flux is equal to J-<P~9m~I  
    the sum of the flux in all the emitted rays. When you display an irradiance map, +zMhA p  
    the system transmittance is equal to the total flux, displayed at the bottom of the 3q/Us0jr  
    irradiance map window, divided by the emitted flux. To get the system clU ?bF~e1  
    transmittance, check the Normalize to emitted flux box and press the Apply 6HCg<_j]  
    button. The map will be redisplayed, and the Normalized Flux value will be equal g*b`o87PI  
    to the system transmittance. tlQ6>v'  
    Example 2: Lighting Efficiency q.=Q  
    Suppose you need to calculate the lighting efficiency of a luminaire in illuminating W\>O$IX^e  
    a plane. You would probably choose the Surface Source raytrace option, and the ywp_,j9F  
    emitted flux is equal to the flux you specified when you defined the sources. When Q$U.vF7BnP  
    you display an irradiance map, the total flux incident on the observation plane is ]z'L1vQl7  
    displayed at the bottom of the window. The lighting efficiency is equal to the total #|E#Rkw!  
    flux divided by the emitted flux. To get the lighting efficiency directly, check the legWY)4D;  
    Normalize to emitted flux box and press the Apply button. The map will be I+ |uyc  
    redisplayed, and the Normalized Flux value will be equal to the lighting efficiency "J,|),Yd  
    of the luminaire.
    离线kaoyanming
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    只看该作者 6楼 发表于: 2015-06-02
    可以看成均匀性吗?