[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 Sa?5iFg  
function sjr=nfdre(~) Ie&b<k  
{[t"O u  
%系统焦距及各镜间距输入，间距取负正负 Jt>[]g$  
jo;uRl  
f=input('f:'); k4F"UG-`  
d1=input('d1:'); U|Z>SE<k  
d2=input('d2:'); =Kt9,d08x  
d3=input('d3:'); 5hH6G  
<K#'3&*$s  
A=f^2/(d3*d2)-f/d1; ZkB6bji  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); hLytKPgt  
C=d3/d2-f/d1; $v'Y
:  
:m++ iR  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 <{NYD.  
a2=d3/(a1*f);%α2 @"{'j  
b2=a1*(1-a2)*f/d2;%β2 "h;;.Y8e  
b1=(1-a1)*f/(d1*b2);%β1 !V]MLA`  
Z]aK'  
U!\2K~  
%曲率半径 i2FD1*=/?  
R7B,Q(q2-  
R1=2*f/(b1*b2) y  KYP  
R2=2*a1*f/(b2*(1+b1)) txml*/zL  
R3=2*a1*a2*f/(1+b2) ^YG7dd_  
Hw?2XDv j  
A1=b2^3*(a1-1)*(1+b1)^3; Clt5  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Jny)uo8  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; zY1s7/$i  
iF [?uF  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); i[2bmd!H
 
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); k'@7ZH  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); A{aw< P|+  
<g3du~  
CB=[C1 B1;C2 B2]; -3G 4vRIo  
AB=[A1 B1;A2 B2]; 5PGlR!^  
AC=[A1 C1;A2 C2]; \o:ELa HY  
tM^;?HL]  
%非球面系数 Hbjb7Y?[  
k2=-(det(CB)/det(AB)); wc7mJxJxA  
k3=-(det(AC)/det(AB)); _(oP{wgB  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 L$29L:  
k2=k2 >~5lYD  
k3=k3 kqKj7L  
`dv}a-Q)c  
end 't|Un G  
cBLR#Yu;O5  
%有中间像，焦距输入为正数 ceFsGdS  
[lNqT1%]  
function sjr=yfdre(~) K\IYx|Hm a  
&Y54QE".  
f=input('f:'); ]6t]m2~\  
d1=input('d1:'); Uvjdx(fY[a  
d2=input('d2:'); %RQC9!  
d3=input('d3:'); rU=b?D)n!w  
Mw"xm9(Q  
A=f^2/(d3*d2)-f/d1; .M9d*qp`S  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); bJQ5- *F  
C=d3/d2-f/d1; $J QWfGwR  
RzA2*]%a  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); bZNIxkc[Dh  
a2=d3/(a1*f); A1T<  
b2=a1*(1-a2)*f/d2; q2x|%HRF  
b1=(1-a1)*f/(d1*b2); $Wit17j  
?HrK\f3wWO  
%曲率半径 {&2$[g=[ ^  
tcBC!_vF  
R1=2*f/(b1*b2) PsU9R#HL1  
R2=2*a1*f/(b2*(1+b1)) u0m5JD0/  
R3=2*a1*a2*f/(1+b2) 7 I_1 #O  
KX?o nsZ  
A1=b2^3*(a1-1)*(1+b1)^3; 3iE
-6udCS  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; $ A-+E\vQ@  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; _W)`cr  
+kjzn]}f  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); (k%GY< bP  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); hi!L\yi  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); :GU,EDps  
9
$Ig~W)  
CB=[C1 B1;C2 B2]; wL4ZW8_  
AB=[A1 B1;A2 B2]; ipG5l  
AC=[A1 C1;A2 C2]; )!tCC-Cr  
)O,wRd>5  
%二次系数 3`8dii  
>qR7'QwP  
k2=-(det(CB)/det(AB)); 8g\wVKkTQp  
k3=-(det(AC)/det(AB)); OnZF6yfN=3  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 nD7|8,
'  
k2=k2 v`y6y8:>  
k3=k3  )|v^9  
&!ED# gs  
end

谢谢分享，学习一下 W+_RhJ