[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 hD9'`SQ  
function sjr=nfdre(~) L3hxe]mr  
1_dMe%53  
%系统焦距及各镜间距输入，间距取负正负 NIXcib"tG  
y1jGf83  
f=input('f:'); wYS KtG~/S  
d1=input('d1:'); sLpCWIy  
d2=input('d2:'); ^F{)&#4  
d3=input('d3:'); VQW)qOR9  

l7r N  
A=f^2/(d3*d2)-f/d1; /w0v5X7  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); GXvo't@N  
C=d3/d2-f/d1; ~sU! 1  
eABdye  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 5l7L@Ey  
a2=d3/(a1*f);%α2 j/`qd(=B  
b2=a1*(1-a2)*f/d2;%β2 ;hRpAN  
b1=(1-a1)*f/(d1*b2);%β1 ^zluO
 
'frL/[S  
0tm "kzy  
%曲率半径 HBf8!\0|/  
u g$\&rM>
 
R1=2*f/(b1*b2) #*aGzF  
R2=2*a1*f/(b2*(1+b1)) y2ws*IZ"  
R3=2*a1*a2*f/(1+b2) !Pjg&19  
nJ0eZBgB]  
A1=b2^3*(a1-1)*(1+b1)^3; `0WA!(W  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; VNEZBy"F  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; )LMuxj  
N(/<q
v  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); F p=Q$J|  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); $izpH  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); tJF~Xv2L!  
VKJ~ZIO@A  
CB=[C1 B1;C2 B2]; )tQ6rd'  
AB=[A1 B1;A2 B2]; ='||BxB  
AC=[A1 C1;A2 C2]; &)}:Y!qiu  
]f @LhC1x  
%非球面系数 teNQUIe-  
k2=-(det(CB)/det(AB)); 7tO$'q*h  
k3=-(det(AC)/det(AB)); ?D 9#dGK  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 b
2kbuk]  
k2=k2 P\0%nyOG(%  
k3=k3 GoA>sK  
h_"/@6  
end ;mKU>F<V  
rd~W.b_b  
%有中间像，焦距输入为正数 -#M~NbI,  
$ttr_4=  
function sjr=yfdre(~) q x }fn/:  
QjbPBk Q  
f=input('f:'); /4BXF4ksi,  
d1=input('d1:'); CP#MNNvgrw  
d2=input('d2:'); 7%}}m&A7h  
d3=input('d3:'); z`7C)p:  
/s_$CSiB  
A=f^2/(d3*d2)-f/d1; ~i#xjD5  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); q)i(wEdUZ  
C=d3/d2-f/d1; ADUI@#vk  
7ij=%if2@k  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); l@jJJ)Qyk  
a2=d3/(a1*f); &y+*3,!n8  
b2=a1*(1-a2)*f/d2; y_r6T XnGL  
b1=(1-a1)*f/(d1*b2); R7b*(33  
S
kUP9  
%曲率半径 He23<hd!  
+:Zi(SuS]  
R1=2*f/(b1*b2) !+l, m8Hly  
R2=2*a1*f/(b2*(1+b1)) hY9u#3  
R3=2*a1*a2*f/(1+b2) N^at{I6C  
9>P(eN  
A1=b2^3*(a1-1)*(1+b1)^3; :UciFIa  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; bm?TMhC  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; !IU*Ayg  
g/gLG:C  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); =c4U%d2  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 'M/&bu r  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); I78pul8!  
Lo4t:H&  
CB=[C1 B1;C2 B2]; x N)Ck76  
AB=[A1 B1;A2 B2]; H0 t1& :  
AC=[A1 C1;A2 C2]; X=~QE}x  
6 [E"  
%二次系数 IuD<lMeJJ  
*ni|I@8
 
k2=-(det(CB)/det(AB)); Hy'&x?F6  
k3=-(det(AC)/det(AB)); *uR'eXW  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 dZZ/(oE>  
k2=k2 ,fRb6s-  
k3=k3 5N0H^  
7dZ!GX?\y  
end

谢谢分享，学习一下 cqDnZ`|6