[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 ]:\dPw
`A  
function sjr=nfdre(~) bu"!jHPB  
%PJQ%~ A  
%系统焦距及各镜间距输入，间距取负正负 m4yL@d,Yw  
=I~mKn  
f=input('f:'); bYPKh  
d1=input('d1:'); (4EI-e*6  
d2=input('d2:'); ei{eTp4HpV  
d3=input('d3:'); nNU2([  
4'Zp-k?5`  
A=f^2/(d3*d2)-f/d1; dq[xwRU1  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Hq 188<  
C=d3/d2-f/d1; e~':(/%|5;  
)F2OT<]m,  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1
!Rt>xD  
a2=d3/(a1*f);%α2 :/Qq@]O>  
b2=a1*(1-a2)*f/d2;%β2 I!?}jo3  
b1=(1-a1)*f/(d1*b2);%β1 ]g&TKm  
!v0LBe4  
Wxe0IXq3Nn  
%曲率半径 O7IJ%_A&  
NN`uI6=  
R1=2*f/(b1*b2)
\'bzt"f$j  
R2=2*a1*f/(b2*(1+b1)) !0cD$^7  
R3=2*a1*a2*f/(1+b2) O8.5}>gDn.  
*D3/@S$B  
A1=b2^3*(a1-1)*(1+b1)^3; xZv#Es%#  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; puM3g|n@  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; t<viX's  
VM,]X.  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); I 2|Bg,e  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); #N cK X  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); E\,
-XH  
_f:W?$\ho  
CB=[C1 B1;C2 B2]; |H+Wed|  
AB=[A1 B1;A2 B2]; LE>]8[f6S  
AC=[A1 C1;A2 C2]; ^ovR7+V  
]P?vdgEM&  
%非球面系数 xK\
d4"  
k2=-(det(CB)/det(AB)); xUistwq  
k3=-(det(AC)/det(AB)); (*)hD(C5  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ^]-6u:J!  
k2=k2 ,nB5/Lx  
k3=k3 N
T
I+  
igR";OQk  
end FG*r'tC~r  
A$:U'ZG_  
%有中间像，焦距输入为正数 Np0u,t%vs  
46&/gehr  
function sjr=yfdre(~) 0s2v'A[\  
<yFu*(Q  
f=input('f:'); W1=H8O  
d1=input('d1:'); 'ub@]ru|  
d2=input('d2:'); Fun^B;GA:  
d3=input('d3:'); ~O&:C{9=  
=rCIumqD-}  
A=f^2/(d3*d2)-f/d1; b`O'1r\Y;  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 1^(ad;BCy  
C=d3/d2-f/d1; 8eHyL  
[ ~&/s:Vvo  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); V /V9B2.$  
a2=d3/(a1*f); $@"g^,n  
b2=a1*(1-a2)*f/d2; _t #k,;  
b1=(1-a1)*f/(d1*b2); c|@bwat4  
d,n 'n  
%曲率半径 wT8DSq  
g~A`N=r;h  
R1=2*f/(b1*b2) K}MK<2vU  
R2=2*a1*f/(b2*(1+b1)) ByNn  
R3=2*a1*a2*f/(1+b2) DG:Z=LuJr  
&AbNWtCV+G  
A1=b2^3*(a1-1)*(1+b1)^3; dvJM6W>^=  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; o
rMwAV  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; X=fYWj[H,  
<s<n  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); iVq'r4S  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); !\.pq 2  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); EVC]sUT  
GH:jH]u!V  
CB=[C1 B1;C2 B2]; %.-4!vj  
AB=[A1 B1;A2 B2]; iN8zo:&Z  
AC=[A1 C1;A2 C2]; *VhL\IjN]  
V7fq4O^:  
%二次系数 DKJmTH]rUg  
A1>OY^p3%  
k2=-(det(CB)/det(AB)); %%gc2s  
k3=-(det(AC)/det(AB)); >rKIG~P_  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ]tRu2Ygf  
k2=k2 G[I"8iS,  
k3=k3 =Qj{T  
%oa-WmWm  
end

谢谢分享，学习一下 ZWU)\}}_R