[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 =j0x.fSe  
function sjr=nfdre(~) lhC6S'vq  
"fQRk  
%系统焦距及各镜间距输入，间距取负正负 wN37zPnV~  
SN+S6  
f=input('f:'); !rxp?V n -  
d1=input('d1:'); _baYn`tFw-  
d2=input('d2:'); Ccfwax+  
d3=input('d3:'); iZ[tHw||  
5T4"j;_.BL  
A=f^2/(d3*d2)-f/d1; dw@E)  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); -7'#2P<)  
C=d3/d2-f/d1; rqCa 2  
;~HNpu$  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1  *2u E  
a2=d3/(a1*f);%α2 p}]q d4j  
b2=a1*(1-a2)*f/d2;%β2 FYPz 4K  
b1=(1-a1)*f/(d1*b2);%β1 5IMSNGS  
aj|5 #  
U2*6}c<  
%曲率半径 +I|8Q|^SD  
Ri:p8  
R1=2*f/(b1*b2) PB~_I=  
R2=2*a1*f/(b2*(1+b1)) TW`mxj_J2  
R3=2*a1*a2*f/(1+b2) j.-VJo)   
0yof u  
A1=b2^3*(a1-1)*(1+b1)^3; ]S8LY.Az5  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; snk$^  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; PNF4>)  
rb_Z5T  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); _[E\=
 
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 7#4%\f+'t  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); fDuwgY0  
jOv"<  
CB=[C1 B1;C2 B2]; %= u/3b:o  
AB=[A1 B1;A2 B2]; iV)ac\  
AC=[A1 C1;A2 C2]; 6c\DJD  
*8!w&ME+.  
%非球面系数 Md9l+[@  
k2=-(det(CB)/det(AB)); 0M!0JJy#*  
k3=-(det(AC)/det(AB)); 4:
 sl(r  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 )bW5yG!  
k2=k2 $v&C@l \  
k3=k3 1)U}i ^  
@%B4;c  
end O_CT+Ou  
#\b ;2>  
%有中间像，焦距输入为正数 4;\Y?M}g?  
[_%,6e+  
function sjr=yfdre(~) aYj%w  
3i(Jon/p  
f=input('f:'); TSXTc'  
d1=input('d1:'); 5+FLSk  
d2=input('d2:'); N*1  
d3=input('d3:'); J9a $AU*  
uo 4xnzc  
A=f^2/(d3*d2)-f/d1; 6h@+?{F.  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); a 2Et,WA%  
C=d3/d2-f/d1; BvI 0v:  
BK*UR+,  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); _Y7:!-n}  
a2=d3/(a1*f); -R74/GBg  
b2=a1*(1-a2)*f/d2; @WJf)  
b1=(1-a1)*f/(d1*b2); =SL^>HS.fo  
.
pKN4  
%曲率半径 .)0gz!Z  
VwC4QK,d;  
R1=2*f/(b1*b2) `r9^:
TMN  
R2=2*a1*f/(b2*(1+b1)) P|v ?
 
R3=2*a1*a2*f/(1+b2) m>O2t-  
mVHFT~x7}  
A1=b2^3*(a1-1)*(1+b1)^3; E]?2!)mgce  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; kw;wlFU;  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; r.Lx%LZ\^  
>!<V\ Fj1  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); r=|vad$  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); hN}5u"pS  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 8W{ g  
#W.bZ]&WA  
CB=[C1 B1;C2 B2]; + p'\(Z(  
AB=[A1 B1;A2 B2]; }0krSzcn#,  
AC=[A1 C1;A2 C2]; ruWye1X;  
$*wu~  
%二次系数 z{AM2Z  
OY$7`8M[  
k2=-(det(CB)/det(AB)); 2Sv>C `FMU  
k3=-(det(AC)/det(AB)); 5,Qy/t}K  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Jr|K>  
k2=k2 0VG^GKmx  
k3=k3 ;k-g
_{M  
K T%i,T  
end

谢谢分享，学习一下 I3V{"Nx6