[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 hVcV_  
function sjr=nfdre(~) ?0
VLx,kp  
M6b; DQ  
%系统焦距及各镜间距输入，间距取负正负 ;tF7GjEp  
<2a7>\74E0  
f=input('f:'); `<L6Q2Y>j  
d1=input('d1:'); iE$/ Rcp  
d2=input('d2:'); ]+B#SIC;  
d3=input('d3:'); -IB~lw
 
W|FPj^*t  
A=f^2/(d3*d2)-f/d1; g2<xr;<t^  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); zF[>K4  
C=d3/d2-f/d1; #'-L`])7uw  
? h$>7|  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 vO)nqtw  
a2=d3/(a1*f);%α2 ^r<bi%@C$  
b2=a1*(1-a2)*f/d2;%β2 H[{ch t h  
b1=(1-a1)*f/(d1*b2);%β1 @"m? #  
=y/VrF.bV  
p&L`C|0  
%曲率半径 5[|MO.CB$  
U9KnW]O%"  
R1=2*f/(b1*b2) 5"[Qs|VjA6  
R2=2*a1*f/(b2*(1+b1)) TY=BP!s  
R3=2*a1*a2*f/(1+b2) 46dh@&U  
,z?Re)qm  
A1=b2^3*(a1-1)*(1+b1)^3; <o_H]c->  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; q lL6wzq,  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; l\yFx  
#isBE}sT{  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); j!;?=s  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); .s_wP  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); u=I>DEe@c  
L`ZH.fN  
CB=[C1 B1;C2 B2]; 3H%oTgWk  
AB=[A1 B1;A2 B2]; g|PVOY+|^  
AC=[A1 C1;A2 C2]; 7K`A2  
3`&2-  
%非球面系数 7 3k3(r
Z  
k2=-(det(CB)/det(AB)); Aov=qLWJ  
k3=-(det(AC)/det(AB)); hIw<gb4J%  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 7:1c5F~M  
k2=k2 1x]U&{do  
k3=k3 Nvs8t%  
WZ'3
 
end bf `4GD(  
b0i]T?#  
%有中间像，焦距输入为正数 Ftm%@S?  
!V.'~xj  
function sjr=yfdre(~) [KR`%fD0  
gJ>?<F;  
f=input('f:'); JQ%`]=n(/  
d1=input('d1:'); //W<\  
d2=input('d2:'); =F ZvtcCa  
d3=input('d3:'); }`yIO"{8n  
nVoPTr  
A=f^2/(d3*d2)-f/d1; Ku_`F2Q  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); L^VG?J  
C=d3/d2-f/d1; c{j0A;XMS  
@7%nMTZ@&v  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); POc< G^  
a2=d3/(a1*f); Gu&?Gn oc  
b2=a1*(1-a2)*f/d2; L&lNpMT  
b1=(1-a1)*f/(d1*b2); K.] *:fd  
@3{'!#/  
%曲率半径 jGEUl=W  
Y*0%lq({H  
R1=2*f/(b1*b2) lC.Yu$O5  
R2=2*a1*f/(b2*(1+b1)) L^)&"6oSa  
R3=2*a1*a2*f/(1+b2) HW{osav9  
iy8UrgG;l  
A1=b2^3*(a1-1)*(1+b1)^3; ;*+jCL2F  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; {y'c*NS  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; b IcLMG s  
@q2Yka  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ZYrXav<  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); rU5gQq
;  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); OUe@U;l{Z  
;|b D
@%@  
CB=[C1 B1;C2 B2]; iU{F\>  
AB=[A1 B1;A2 B2]; T<DQi  
AC=[A1 C1;A2 C2]; y-{^L`%Mk  
<O>r e3s  
%二次系数 @Wy>4B^  
on+ c*#  
k2=-(det(CB)/det(AB)); z:|4S@9  
k3=-(det(AC)/det(AB)); d)(61  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 r<Ll>R  
k2=k2 zMKW@  
k3=k3 JMpjiB,A}  
YQiTx)_  
end

谢谢分享，学习一下 U/m6% )Yx(