[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 npltsK):  
function sjr=nfdre(~) X
Xum2eA  
)VkVZf | S  
%系统焦距及各镜间距输入，间距取负正负 a<q9~QS  
z2YYxJc&w  
f=input('f:'); LF!KP  
d1=input('d1:'); dY&v(~&;]  
d2=input('d2:'); F$tzsz,9n  
d3=input('d3:'); z@3gNY&7.8  
STjb2t,a  
A=f^2/(d3*d2)-f/d1; "[~yu* S  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Nmz5:Rq  
C=d3/d2-f/d1; 7V::P_aUY  
iXo;e  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 ^g6v#]&WA  
a2=d3/(a1*f);%α2 `)y ;7%-  
b2=a1*(1-a2)*f/d2;%β2 bT2c&VPCE  
b1=(1-a1)*f/(d1*b2);%β1 gPB=Z!  
F]6G<6T[  
%/w-.?bX  
%曲率半径 59D'*!l-  
? bWc<]  
R1=2*f/(b1*b2) ];Noe9o  
R2=2*a1*f/(b2*(1+b1)) G`%rnu  
R3=2*a1*a2*f/(1+b2) Tdh.U
{Nz  
n$SL"iezW?  
A1=b2^3*(a1-1)*(1+b1)^3; yOl
VS@7  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; jW8ad
{  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 3l~7  
q[qX O5  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); >
Um(gbG  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); `Z>=5:+G@2  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); v2]N5  
U~yPQ8jD  
CB=[C1 B1;C2 B2]; ^E\4`  
AB=[A1 B1;A2 B2]; ?E!M%c@,  
AC=[A1 C1;A2 C2]; apJXRH`  
WNjG/U  
%非球面系数 Mj>QV(L8t  
k2=-(det(CB)/det(AB)); [g"nu0sOK  
k3=-(det(AC)/det(AB)); 8hww({S2  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 uYlyU~M:D  
k2=k2 ~u0<c:C^  
k3=k3 cCiDe`T\F  
)g8Kicox5  
end A?n5;mvq#  
GJU(1%-  
%有中间像，焦距输入为正数 W^HE1Dt]  
tIV9Y=ckr0  
function sjr=yfdre(~)
'tMD=MH  
FU*q9s`  
f=input('f:'); W+GBSl
 
d1=input('d1:'); 6j1C=O@S  
d2=input('d2:'); er BerbEEH  
d3=input('d3:'); d7X7_  
=s.0 f:(  
A=f^2/(d3*d2)-f/d1; WyB^b-QmDh  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ryzNM3  
C=d3/d2-f/d1; /ioBc}]  
dqBN_P%  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); l%0-W  
a2=d3/(a1*f); C %j%>X`  
b2=a1*(1-a2)*f/d2; VS`
{k^^  
b1=(1-a1)*f/(d1*b2); Hv' OO@z  
PD^ 6Ywn>s  
%曲率半径 l*CCnqE  
aS>cXJ;=  
R1=2*f/(b1*b2) 3,hu3"@k  
R2=2*a1*f/(b2*(1+b1)) D^s#pOZS  
R3=2*a1*a2*f/(1+b2) hZo  f  
M
=3w  
A1=b2^3*(a1-1)*(1+b1)^3; Ed-3-vJej6  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ^)`e}}  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; TZg1,Z  
F_/ra?WVH  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); j}J=ZLr/V"  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); JXt_
  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); {7$jwk  
'4M;;sKW  
CB=[C1 B1;C2 B2]; IQd~` G  
AB=[A1 B1;A2 B2]; z'O+B}  
AC=[A1 C1;A2 C2]; P_p\OK*l]o  
T>hm\!  
%二次系数 23'<R i  
w|0
:0Rc~u  
k2=-(det(CB)/det(AB)); t-}IKrbv  
k3=-(det(AC)/det(AB)); *.1#+h/]3  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 &U([Wd?E2  
k2=k2 oSYbx:2wo  
k3=k3 |-cXb.M[  
'|Lv-7  
end

谢谢分享，学习一下 4v{Ye,2