[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 RJ7/I/yD|  
function sjr=nfdre(~) 'R-JQE-]  
zYNM<W;  
%系统焦距及各镜间距输入，间距取负正负 QB oZCLv  
+$an*k9  
f=input('f:'); ;nHo%`Zt  
d1=input('d1:'); I NFzX  
d2=input('d2:'); {&Gk.ODI7  
d3=input('d3:'); kKI!B`j=  
h1D~AgZOVj  
A=f^2/(d3*d2)-f/d1; ,T1XX2?:  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); zrWq!F*-V\  
C=d3/d2-f/d1; 6H. L!tUI  
(urfaZ;@+  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 3IRRFIiO  
a2=d3/(a1*f);%α2 e`gGzyM  
b2=a1*(1-a2)*f/d2;%β2 LU 5 `!0m  
b1=(1-a1)*f/(d1*b2);%β1 Xk7$?8r4&  
UO7a}Tz<  
?
geWR_Z  
%曲率半径 [{fF)D<tC  
^FyvaO  
R1=2*f/(b1*b2) <aQ; "O~   
R2=2*a1*f/(b2*(1+b1)) kAKqW7,q"  
R3=2*a1*a2*f/(1+b2) _|Kv~\G!  
Z-;uzx  
A1=b2^3*(a1-1)*(1+b1)^3; %V" +}Dr  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; [F9KC^%S  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; =6q*w^ET  
emDvy2uA#  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); PY3V
u]zD  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); "Ee/q:`  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); hU)f(L  
1x<rh\oo  
CB=[C1 B1;C2 B2]; WRU@i;l  
AB=[A1 B1;A2 B2]; ,:Ix s^-  
AC=[A1 C1;A2 C2]; vN6]6nUOiT  
qjRiTIp9q  
%非球面系数 \gk3w,B?E  
k2=-(det(CB)/det(AB)); @
8 yE(  
k3=-(det(AC)/det(AB)); 7 +W?Qo  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 9gIJX?  
k2=k2 |@n{tog+-  
k3=k3 {Z{NH:^  
,LW%'tQ~"  
end K
Lv  
3YNkT"~T  
%有中间像，焦距输入为正数 4 d1Y\  
RX<^MzCDV  
function sjr=yfdre(~) (nZ=9+j]d  
TB3T:A>2  
f=input('f:'); MBTt'6M  
d1=input('d1:'); jU9zCMyNF  
d2=input('d2:'); laRKt"A  
d3=input('d3:'); DEeL48{R  
$vicHuX!  
A=f^2/(d3*d2)-f/d1; m
WFZg.#?  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); i:Ct6[  
C=d3/d2-f/d1; ~!+h"%'t  
oG_'<5Bv>  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); E*b[.vUp  
a2=d3/(a1*f); #$z-]i  
b2=a1*(1-a2)*f/d2; o>,z %+  
b1=(1-a1)*f/(d1*b2); ,/?V+3l  
KD3To%  
%曲率半径 8`*9jr  
0tL/:zID  
R1=2*f/(b1*b2) Vv"wf;#  
R2=2*a1*f/(b2*(1+b1)) QNI|h;D  
R3=2*a1*a2*f/(1+b2) ^~IcQ!j/5  
*9:6t6x  
A1=b2^3*(a1-1)*(1+b1)^3; %T*+t"\)  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; HyYQQ  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; L$kAe1 V^m  
fvAV[9/-  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); Ch!Q?4  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); KI QBY!N+  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); }8]uZ)[p=  
GSb)|mj  
CB=[C1 B1;C2 B2]; &,kB7r"  
AB=[A1 B1;A2 B2]; xla^A}{  
AC=[A1 C1;A2 C2]; %v)'`|i  
KX}dn:;(3  
%二次系数 3\.)y49,1  
1? hd  
k2=-(det(CB)/det(AB)); ={0{X9t?'j  
k3=-(det(AC)/det(AB)); ?4?j
G3p  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1  /lok3J:  
k2=k2 nMvIL2:3  
k3=k3 v#2qwd3x  
9wJmX<Rm  
end

谢谢分享，学习一下 >A "aOV>K