[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 uQ vW@Tt  
function sjr=nfdre(~) B(:Kw;r?  
>#$(M5&}-  
%系统焦距及各镜间距输入，间距取负正负 awHfd5nRS  
^t*+hFEI  
f=input('f:'); P9B@2#  
d1=input('d1:'); P qagep d  
d2=input('d2:'); HsR#dp+s~  
d3=input('d3:'); prlB9,3|C  
h:z;b;  
A=f^2/(d3*d2)-f/d1; YRG+I GX  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); .sbU-_ij@U  
C=d3/d2-f/d1; ngsa
x1xO  
>QE^KtZ  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 ojs&W]r0Z  
a2=d3/(a1*f);%α2 Zj<oh8  
b2=a1*(1-a2)*f/d2;%β2 dsR{ P,!  
b1=(1-a1)*f/(d1*b2);%β1 ~BERs;4  
d#ya"e>  
N5}vy$t_P  
%曲率半径
YUT"A{L  
IywovN Tr  
R1=2*f/(b1*b2) 7v?tSob:b  
R2=2*a1*f/(b2*(1+b1)) S4qh8c  
R3=2*a1*a2*f/(1+b2) 7@fd[  
CV]PCq!  
A1=b2^3*(a1-1)*(1+b1)^3; Gxi;h=J2)>  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Y@9L8XNP>  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; E;VBoN [  
g"(N_sv?  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); %b\xRt[0v7  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); +A~lPXAXW  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2);  7z<!2  
pqMvYF  
CB=[C1 B1;C2 B2]; }td+F&l($V  
AB=[A1 B1;A2 B2];
4=o3ZRV  
AC=[A1 C1;A2 C2]; iUS379wM
}  
n
\,TW&3  
%非球面系数 ])m",8d&T  
k2=-(det(CB)/det(AB)); "'t<R}t!A  
k3=-(det(AC)/det(AB)); F|xXMpC.f  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 rJ\A)O+Mq(  
k2=k2 7 aDI6G  
k3=k3 _N/]&|.. !  
6WceDY  
end ?=r!b{9  
Qbl6~>T  
%有中间像，焦距输入为正数 _9!Ru!u~  
"Y(S G  
function sjr=yfdre(~) aI8wy-3I  
+bdkqdB9  
f=input('f:'); )@R:$l86  
d1=input('d1:'); ?#04x70  
d2=input('d2:'); w2+RX-6Ie  
d3=input('d3:'); M8KfC!  
 %ef+
Z  
A=f^2/(d3*d2)-f/d1; m+OR W"o  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); _& KaI }O  
C=d3/d2-f/d1; _JR4 PKtx  
!cSD9q*  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); a.%]5%O;t  
a2=d3/(a1*f); ik8e  
b2=a1*(1-a2)*f/d2; \?3];+c9  
b1=(1-a1)*f/(d1*b2); Tw
!x*  
2mU}"gf[  
%曲率半径 u52;)"&=)  
Qbv)(&i#~  
R1=2*f/(b1*b2) (]7@0d88  
R2=2*a1*f/(b2*(1+b1)) p-*BB_J"  
R3=2*a1*a2*f/(1+b2) {F@;45)o  
fi bR:8  
A1=b2^3*(a1-1)*(1+b1)^3; >W-e0kkH  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; @Cz1rKU^l  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; &v 5yo}s  
}}_WZ},h  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); LR9'BUfFv  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 6@l:(-(j2A  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 3>L1}zyM]  
p%3';7W\  
CB=[C1 B1;C2 B2]; //wmJ |  
AB=[A1 B1;A2 B2]; xHD!8B)  
AC=[A1 C1;A2 C2]; QQ!,W':  
Llk`  
%二次系数 8De `.!Gg  
@F3d9t-  
k2=-(det(CB)/det(AB)); .-W
CB  
k3=-(det(AC)/det(AB)); |ZZ3Qr+%S  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 57[O)5u.+  
k2=k2 JBoo7a1  
k3=k3 X(WG:FP27  
\H" (*["&  
end

谢谢分享，学习一下 x1Si&0T0P<