[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 s,;L6nX"  
function sjr=nfdre(~) \xexl1_;  
gL6.,4q+1  
%系统焦距及各镜间距输入，间距取负正负 tf?"AY4  
y_N h5  
f=input('f:'); I"r[4>>B>0  
d1=input('d1:'); g2W ZW#a)  
d2=input('d2:'); Tlz~o[`&  
d3=input('d3:'); pJ H@v &a  
`NARJ9M   
A=f^2/(d3*d2)-f/d1; zc%HBZ3p  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); SoL"M[O  
C=d3/d2-f/d1; m15> ^i^W  
p#tbN5i[{7  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 #tlhH\Pr[  
a2=d3/(a1*f);%α2 ^F`\B'8MF  
b2=a1*(1-a2)*f/d2;%β2 5u
&hp  
b1=(1-a1)*f/(d1*b2);%β1 ThJ`-Ro  
_$BH.I  
299uZz}Y  
%曲率半径 4+4C0/$Y  
qBXIR}  
R1=2*f/(b1*b2) W,sPg\G 3  
R2=2*a1*f/(b2*(1+b1)) I vD M2q8f  
R3=2*a1*a2*f/(1+b2) 3[}w#n1  
6eHw\$/  
A1=b2^3*(a1-1)*(1+b1)^3; d}(b!q9  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; b?%Pa\,!  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 8PwPI
%Pb  
&U0Y#11Cx  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); :`20i*  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); Ur2)];WZ  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); ,NoWAmv  
D|E,9
|=v  
CB=[C1 B1;C2 B2]; YTYCv7  
AB=[A1 B1;A2 B2];  o C#W  
AC=[A1 C1;A2 C2]; uEcK0>xp  
*d$r`.9j  
%非球面系数 Eaw
tT  
k2=-(det(CB)/det(AB)); b{hdEb  
k3=-(det(AC)/det(AB)); +U*:WKdI?  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 j`ybzG^  
k2=k2 |!.V
pN&  
k3=k3 zvHeoM,  
z2cd1HxN  
end 7Hzv-s  
+a}>cAj*  
%有中间像，焦距输入为正数 +n&9ZCH  
ipn0WQG  
function sjr=yfdre(~) >*S ;z+!&  
>\5IB5'j  
f=input('f:'); h^=9R6im  
d1=input('d1:'); &VfMv'%x  
d2=input('d2:'); e{7"7wn=  
d3=input('d3:'); 4&+lc*  
f~Q]"I8w  
A=f^2/(d3*d2)-f/d1; nZ8f}R!f:  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); QPJz~;V2  
C=d3/d2-f/d1; 9>hK4&m^  
2r>I,T
NHl  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); $V2.@X  
a2=d3/(a1*f); .YxcXe3#  
b2=a1*(1-a2)*f/d2; Spt;m0W90  
b1=(1-a1)*f/(d1*b2); X82
12[7  
+N:=|u.g  
%曲率半径 "=vH,_"Ql  
Z}s56{!.  
R1=2*f/(b1*b2) ^P}c0}^  
R2=2*a1*f/(b2*(1+b1)) 1@{qPmf^  
R3=2*a1*a2*f/(1+b2) ooIA#u  
2!;U.+(  
A1=b2^3*(a1-1)*(1+b1)^3; 66%4p%#b4  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; U<jAZU[L  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; SWPb=[WEz  
&n-)Alx  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ^F4h:  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 2}jC%jR2  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); J{h?=vK  
d+Au`'{>  
CB=[C1 B1;C2 B2]; w!~85""  
AB=[A1 B1;A2 B2]; G*\U'w4w|*  
AC=[A1 C1;A2 C2]; 6
8,(+vkB  
!@wG22iC4d  
%二次系数 VSW"/{Lp  
Ze-M
B0w  
k2=-(det(CB)/det(AB)); q"|#KT^)  
k3=-(det(AC)/det(AB)); .}x:yKyi@  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 YMD&U   
k2=k2 uPQrDr5  
k3=k3 d gRTV<vM  
=%ZR0cWPoI  
end

谢谢分享，学习一下 L qdzqq