[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 2c*2\93>  
function sjr=nfdre(~) ~l4Q~'  
<v-92?  
%系统焦距及各镜间距输入，间距取负正负 A'(k Yc  
CCwK8`%  
f=input('f:'); LQ|<3]  
d1=input('d1:');  m"1 ?  
d2=input('d2:'); otZ JY)  
d3=input('d3:'); ri;r7Y9V9`  
1 pYsjo~  
A=f^2/(d3*d2)-f/d1; PE +qYCpP9  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); a\|X^%2g  
C=d3/d2-f/d1;  pe|\'<>i  
zkvH=wL  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 JG1
LS$p^  
a2=d3/(a1*f);%α2 Is~yVB02  
b2=a1*(1-a2)*f/d2;%β2 LDSbd,GF  
b1=(1-a1)*f/(d1*b2);%β1 s UvKA0  
 K oL%}u&  
r]Z.`}Kkm  
%曲率半径 ]dQZ8yVK
 
RH1U_gp4 ]  
R1=2*f/(b1*b2) @V*a
u:  
R2=2*a1*f/(b2*(1+b1)) /Ir 7 DZK  
R3=2*a1*a2*f/(1+b2) E,Dlaq  
ZW`HDrP`  
A1=b2^3*(a1-1)*(1+b1)^3; 96k(XLR  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; gS0,')w  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 7E@$}&E  
:K5V/-[|V1  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); rUhWZta  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); HM;4=%  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); ZO]E@?Oav  
-U&098}<K  
CB=[C1 B1;C2 B2]; agGgJ@  
AB=[A1 B1;A2 B2]; </~1p~=hAt  
AC=[A1 C1;A2 C2]; %,h!: Ec^c  
E%KC'TN^D  
%非球面系数 G;Pt
|F?c  
k2=-(det(CB)/det(AB)); iOE9FW|e  
k3=-(det(AC)/det(AB)); lb=2*dFJ1  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 15RI(BN  
k2=k2 ~ly`u  
k3=k3 * N2#{eF&]  
HE4`9$kVLr  
end *(>F'>F1"  
Ji)%Y5F  
%有中间像，焦距输入为正数 noWRYS%  
4"`=huQ  
function sjr=yfdre(~) @|JPE%T   
n C\(+K1%  
f=input('f:'); eU<]h>2  
d1=input('d1:'); mJU>f-l  
d2=input('d2:'); f4qS OVv
 
d3=input('d3:'); UzP@{?  
ci#Zvhtkr  
A=f^2/(d3*d2)-f/d1; K]lb8q}Z~  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); U<#$w{d:  
C=d3/d2-f/d1; ~{kA) :  
}j]<&I}  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); /i\uwa,  
a2=d3/(a1*f); Ej9/_0lt  
b2=a1*(1-a2)*f/d2; ([z<TS#Md  
b1=(1-a1)*f/(d1*b2); lUy*549,  
Zi15wE  
%曲率半径 +Px<DX+  
n:{-Vvt  
R1=2*f/(b1*b2) |~1rKzZwF  
R2=2*a1*f/(b2*(1+b1)) yAZ.L/jyr  
R3=2*a1*a2*f/(1+b2) 
Z)b)v  
T% jjs  
A1=b2^3*(a1-1)*(1+b1)^3; Iltg0`  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; F5om-tzy  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; S:"z<O  
4rGO8R  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ZKiL-^dob  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 3tx0y
 
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); QZz{74]n  
pEqr0Qwh  
CB=[C1 B1;C2 B2]; [7ek;d;'t  
AB=[A1 B1;A2 B2]; X8NO;w@z#  
AC=[A1 C1;A2 C2]; D|8sjp4  
H_xQ>~b
 
%二次系数 .j]OO/,  
RLeSA\di  
k2=-(det(CB)/det(AB)); )SlUQ7f>  
k3=-(det(AC)/det(AB)); v\r7.l:hf  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 UH.}B3H  
k2=k2 ~ L i%  
k3=k3 6O[wVaC1u  
Y~\`0?ST  
end

谢谢分享，学习一下 `mHOgS>|