[原创]在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解 [复制链接]

%无中间像，焦距输入为负数 |;gx;qp4cN  
function sjr=nfdre(~) >dAl*T  
y3oq{Z>  
%系统焦距及各镜间距输入，间距取负正负 B{Cm`f8E  
@M'k/jl  
f=input('f:'); tiK M+ ;C  
d1=input('d1:'); 7P{= Pv+  
d2=input('d2:'); Id=
20og  
d3=input('d3:'); )PN8HJAArh  
P27Ot1px  
A=f^2/(d3*d2)-f/d1; Vl5r~+$|  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 7U [C=NL  
C=d3/d2-f/d1; $[T~<I  
~>:JwTy  
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 0LQRQuh1  
a2=d3/(a1*f);%α2 (TeH)j!  
b2=a1*(1-a2)*f/d2;%β2 ;j0.#P:a  
b1=(1-a1)*f/(d1*b2);%β1 ,+i^]yF3j  
+Y?Tri  
 4!!|P  
%曲率半径 fG2)r  
0AnL]`"t.3  
R1=2*f/(b1*b2) k=)U  
R2=2*a1*f/(b2*(1+b1)) :DH@zR  
R3=2*a1*a2*f/(1+b2) SzLlJUVX  
*"^X)Y{c+l  
A1=b2^3*(a1-1)*(1+b1)^3; ]T
rJ*~  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 3U6QYD55]]  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; /E6)>y66  
11PL1zzH  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); JQ+Mg&&Q  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); #A>*pF  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); @5Z|e  
s.z)l$  
CB=[C1 B1;C2 B2]; %jAc8~vW?  
AB=[A1 B1;A2 B2]; _kD5pC =  
AC=[A1 C1;A2 C2]; icG 9x  
)QAYjW!Z  
%非球面系数 as:=
QMV  
k2=-(det(CB)/det(AB)); {tVA(&\<  
k3=-(det(AC)/det(AB)); X0*+]tRg  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ],c0nz^%BR  
k2=k2 % 3#g-  
k3=k3 1^k}GXsWmE  
yK{P%oh)  
end :$Cm]RZ  
i%yKyfD  
%有中间像，焦距输入为正数 Nr@,In|JS  
(0`rfYv5.R  
function sjr=yfdre(~) thPAD+u.3  
-IIrrY O  
f=input('f:'); 3g7]$}  
d1=input('d1:'); 2`i&6iz  
d2=input('d2:'); X}
B]5  
d3=input('d3:'); /8Lb_QH{  
0,0WdJAe  
A=f^2/(d3*d2)-f/d1; ,5 8-h?B0v  
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Mx}r! Q  
C=d3/d2-f/d1; jzi%[c<G  
`c:r`Oi?  
a1=(-B-sqrt(B^2-4*A*C))/(2*A); S> Fb'rJ3  
a2=d3/(a1*f); q4:zr   
b2=a1*(1-a2)*f/d2; mcwd
2)  
b1=(1-a1)*f/(d1*b2); li3X}
  
aR6~r^jB  
%曲率半径 qLBQ!>lR  
65B&>`H~  
R1=2*f/(b1*b2) dhLd2WSyH  
R2=2*a1*f/(b2*(1+b1)) covCa)kf  
R3=2*a1*a2*f/(1+b2) FUI/ A>  
L<  
A1=b2^3*(a1-1)*(1+b1)^3; s2sJJdN  
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; D[T\_3W  
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; .yDR2sW  
Njo.-k  
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); u}'m7|)8  
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); dnANlNMk?  
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); >>=zkPy  
,9OER!$y  
CB=[C1 B1;C2 B2]; T&dc)t`o  
AB=[A1 B1;A2 B2]; 6\h*SBI?(  
AC=[A1 C1;A2 C2]; *"|f!t  
;&b=>kPlZ  
%二次系数 Y}vV.q  
=)#XZ[#F  
k2=-(det(CB)/det(AB)); kH06Cb  
k3=-(det(AC)/det(AB)); Kj"n Id)  
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 %PVu>^  
k2=k2 $hM9{  
k3=k3 \hJLa  
-6q7ze{@  
end

谢谢分享，学习一下 "t{D5{q|[k