What solid angle does that angular pixel represent?
CCp&P5[67 sV{M#UF2 To answer that question we project out from the local axis of the detector to construct a sphere some long distance away from the detector, centered on the detector.
We then (conceptually) fire rays from this point at x, y angles of (5, 40), (5, 41), (6, 41), and (6, 40). Now we know that patch of area, we can compute the solid angle subtended by that angular pixel.
r:u, How is Radiant Intensity Defined 3#7D
g't .\1{>A |Rk$u 红色标出的那句是什么意思?
`[vm{+i u`Kjs}F' ln}2 |pB[g>~V