What solid angle does that angular pixel represent?
K4iI: !x`;>0 To answer that question we project out from the local axis of the detector to construct a sphere some long distance away from the detector, centered on the detector.
We then (conceptually) fire rays from this point at x, y angles of (5, 40), (5, 41), (6, 41), and (6, 40). Now we know that patch of area, we can compute the solid angle subtended by that angular pixel.
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z-5GH| 红色标出的那句是什么意思?
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