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    [求助]matlab画准直透镜曲线? [复制链接]

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    离线2102
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    只看该作者 10楼 发表于: 2013-04-16
    謝謝大大的分享
    离线gsh1128
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    只看该作者 11楼 发表于: 2013-06-24
    算出来也就自然画出来了啊
    离线ciomplj
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    只看该作者 12楼 发表于: 2014-06-22
    谢谢哈~
    离线hjg888
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    只看该作者 13楼 发表于: 2014-09-25
    看一下
    离线zouzili
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    只看该作者 14楼 发表于: 2014-12-29
    下来看看
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    只看该作者 15楼 发表于: 2015-07-15
    学习一下
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    只看该作者 16楼 发表于: 2016-01-11
    看看吧
    离线liunian
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    只看该作者 17楼 发表于: 2016-07-13
    看看e:matlab画准直透镜曲线?
    离线liunian
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    只看该作者 18楼 发表于: 2016-07-13
    程序如下: L' )(Zn1  
    % By Ruibin 08-9-25 :)MZgW  
    % InstructionThis program help design LED collimating lens , feedback aspheric parameters and several chief dimensions. ?dTz?C.w  
    O0Z'vbFG  
    clear all;clc +)F8YMg e  
    Q.8Jgel1  
    % The Frist Step: Define independent parameters  T  
    r=3.25;               %选择开孔半径 6: M   
    R=4.25;               %定义曲面底部半径 c''!&;[!  
    d=1;                  %设置透镜前方平板高度 E*'O))  
    n=1.4935;             %定义材料折射率 BS{">lPmx  
    dividing_angle=24;    %定义CoreTIR的分界角 ksK lw_%o  
    min_angle=1;          %设置计算精度 '<@PgO~  
    N=4;                  %设定拟合非球面系数阶数 4b<:67 %  
    )^r4|WYyt  
    % The Second StepCaculate induced variable *vj5J"Y(;t  
    angles_Core=(dividing_angle:-min_angle:0);angles_TIR=(90:-min_angle:dividing_angle); ,qr)}s-  
    num_Core=length(angles_Core);num_TIR=length(angles_TIR); k,&W5zBKe  
    for i=1:(num_Core) t qER;L  
    a_Core(i)=(angles_Core(i)*pi/180); W:tE ?Hu  
    k1(i)=cot(a_Core(i)); N .SszZh  
    k2(i)=(-k1(i)+(n^2*k1(i)^2+n^2)^(1/2))/(n^2*k1(i)^2-k1(i)^2+n^2); XCt}>/"s\h  
    end M$?~C~b!*  
    k1(num_Core)=999;k2(num_Core)=0; Db3tI#  
    for i=1:num_TIR (*M(gM{;  
    a_TIR(i)=(angles_TIR(i)*pi/180); *F9uv)[kz  
    k3(i)=tan((pi/2+asin(cos(a_TIR(i))/n))/2); _=cMa's  
    k4(i)=tan(asin(cos(a_TIR(i))/n)); .jRXHrK;  
    end 8T2$0  
    X0_TIR=R;X0_Core=r;Y0_TIR=0;Y0_Core=r*cot(a_Core(1)); \@80Z5?n  
    SWmdU]  
    % The Third Step:Solve functions b. t]p  
    for i=1:num_Core                    %Solve the curve of Core 8 {QvB"w  
    syms x; K1$Z=]a+  
    f1=k1(i)*x; .vb*|So  
    f2=k2(i)*(x-X0_Core)+Y0_Core; $QY(7Z"  
    f=f1-f2; j0OxR.S  
    x=double(solve(f));y=k1(i)*x; 5 &VLq  
    X0_Core=x;Y0_Core=y; ,0 ])]  
    Px_Core(i)=X0_Core;Py_Core(i)=Y0_Core; %f>V\z_C  
    end PgxU;N7Y  
    for i=1:num_TIR                      %Solve the curve of TIR L>PpXTWwy  
    syms x; #q=?Zu^Da  
    f1=k3(i)*(x-X0_TIR)+Y0_TIR; &-&6ARb7o  
    f2=k4(i)*(x-r)+r*cot(a_TIR(i)); / AW]12_  
    f=f1-f2; mH8"k+k  
    x=double(solve(f));y=k3(i)*(x-X0_TIR)+Y0_TIR; ;,F}!R  
    X0_TIR=x;Y0_TIR=y; q,m6$\g4  
    Px_TIR(i)=X0_TIR;Py_TIR(i)=Y0_TIR; {Ji[d.cY  
    end Kj}}O2  
    8ayB<b>+]"  
    % The furth Step:Fitting the curve T}zOM%]]  
    P_Core=polyfit(Px_Core,Py_Core,4); ~Ipl'cE  
    P_TIR=polyfit(Px_TIR,Py_TIR,4); z:acrQwJ?1  
    \BS^="AcpP  
    % The fifth Step:Feedback chief dimensions of the lens and Create it L >xN7N3&m  
    %Feedback dimensions of the whole lens d_OHQpfK  
    result='透镜尺寸如下:' Qn6&M  
    Diameter_of_lens=2*Px_TIR(num_TIR) x2 tx{Z  
    Thickness_of_lens=Py_TIR(num_TIR)+d WJhI6lu  
    Diameter_of_Core=2*r 4sG^ bZ,  
    Thickness_of_front_pannel=d gB&'MA!  
    Bottom_thickness=R-r O1-Ne.$  
    Lowest_Core=P_Core(5) 4|*_mC  
    =>ignoeI  
    %Feedback dimensions of Lens part TIR yA6"8fr  
    result='TIR系数如下:' \N!k)6\  
    Thickness=Py_TIR(num_TIR)-P_TIR(5)+d =0O`VSb  
    Aperture=Px_TIR(num_TIR) OI1&Z4Lx  
    Obstruction=r )<!y_;$A  
    Position=P_TIR(5) 2pZ|+!xc+  
    format short e; r`mfLA]d  
    Aspheric=[P_TIR(4) P_TIR(3) P_TIR(2) P_TIR(1)] b}axw+  
    format short; 3F<My+J  
    W4X=.vr  
    %DDE Connection rq+E"Uj?  
    TP_COMMAND = ddeinit('TracePro','Scheme'); gzi~ BJ  
    %Create TIR 02bv0  
    cmd =['(define TIR (insert:lens-element "PLASTIC" "pmma" (list 0 0 7.0306e-002 1.2580e-001 -2.5732e-003 -2.5281e-006) 18.6774 (list 0 0)(list "cir" 13.6051 0 0 0)(list "cir" 3.25 0 0 0)))']; l'mgjv~  
    ddeexec(TP_COMMAND,cmd); v vOG]2z  
    cmd =['(entity:move TIR 0 0 -2.3712)']; k;q|pQ[  
    ddeexec(TP_COMMAND,cmd); F4KXx^~o  
    cmd =['(property:apply-name TIR "TIR")']; N^:)U"9*e  
    ddeexec(TP_COMMAND,cmd); ix6j=5{  
    Q]66v$  
    %Feedback dimensions of Lens part TIR )ASI 41  
    result='Core系数如下:' YJF!_kg.  
    Thickness=Py_TIR(num_TIR)-P_Core(5)+d qm] k (/w  
    Aperture=r IJ[#$I+Z%  
    Obstruction='None' mD=x3d  
    Position=P_Core(5) "1WwSh}Z  
    format short e; ..;}EFw5  
    Aspheric=[P_Core(4) P_Core(3) P_Core(2) P_Core(1)] ^jqQG+`?  
    format short; ':6`M  
    %Create Core <`n T+c  
    cmd =['(define Core (insert:lens-element "PLASTIC" "pmma" (list 0 0 -2.6211e-002  1.9124e-001 -1.7949e-002  2.8016e-004) 10.3569 (list 0 0)(list "cir" 3.2500 0 0 0)))']; r +d%*Dx  
    ddeexec(TP_COMMAND,cmd); <4D.P2ct  
    cmd =['(entity:move Core 0 0 5.9493)']; evz{@;.R  
    ddeexec(TP_COMMAND,cmd); / 9^:*,  
    cmd =['(property:apply-name Core "Core")']; Z!v)zH\  
    ddeexec(TP_COMMAND,cmd); @tR:}J*9s  
    ~~;J[F p  
    %Create Lens ~*ST fyFw  
    cmd =['(define Unite (bool:unite TIR Core))']; r3{Cuz  
    ddeexec(TP_COMMAND,cmd); Q6]SsV?x  
    cmd =['(define block (insert:block 100 100 100))']; #J# x,BLI  
    ddeexec(TP_COMMAND,cmd); MZl6 J  
    cmd =['(entity:move block 0 0 -50)']; ,_F@9Up  
    ddeexec(TP_COMMAND,cmd); -Uh3A\#(  
    cmd =['(define Lens (bool:subtract Unite block))']; ,l1A]Wx  
    ddeexec(TP_COMMAND,cmd); ko2?q  
    cmd =['(property:apply-name Lens "Lens")']; W0R<^5_  
    ddeexec(TP_COMMAND,cmd); D!^&*Ia?2  
    s\@RJ[(<  
    %Close the DDE connection >kU$bh.(  
    ddeterm(TP_COMMAND); :6:;Z qn  
    离线leav01
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    只看该作者 19楼 发表于: 2016-11-22
    学习学习