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    [求助]matlab画准直透镜曲线? [复制链接]

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    离线2102
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    只看该作者 10楼 发表于: 2013-04-16
    謝謝大大的分享
    离线gsh1128
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    只看该作者 11楼 发表于: 2013-06-24
    算出来也就自然画出来了啊
    离线ciomplj
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    只看该作者 12楼 发表于: 2014-06-22
    谢谢哈~
    离线hjg888
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    只看该作者 13楼 发表于: 2014-09-25
    看一下
    离线zouzili
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    只看该作者 14楼 发表于: 2014-12-29
    下来看看
    离线whyhao99
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    只看该作者 15楼 发表于: 2015-07-15
    学习一下
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    只看该作者 16楼 发表于: 2016-01-11
    看看吧
    离线liunian
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    只看该作者 17楼 发表于: 2016-07-13
    看看e:matlab画准直透镜曲线?
    离线liunian
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    只看该作者 18楼 发表于: 2016-07-13
    程序如下: a0~LZQ?  
    % By Ruibin 08-9-25 y2cYRHN[X}  
    % InstructionThis program help design LED collimating lens , feedback aspheric parameters and several chief dimensions. PY[nnoF"|  
    Ejmpg_kux  
    clear all;clc <v%Q|r  
    @cukoLAn  
    % The Frist Step: Define independent parameters -e(e;e  
    r=3.25;               %选择开孔半径 KSz;D+L \  
    R=4.25;               %定义曲面底部半径 ~7ZWtg;B  
    d=1;                  %设置透镜前方平板高度 Qhy!:\&1  
    n=1.4935;             %定义材料折射率 %py3fzg  
    dividing_angle=24;    %定义CoreTIR的分界角 W^k95%zBM  
    min_angle=1;          %设置计算精度 {\hjKP  
    N=4;                  %设定拟合非球面系数阶数 Q WcQtM  
    3?5JY;}h>"  
    % The Second StepCaculate induced variable DHQS7%)f`  
    angles_Core=(dividing_angle:-min_angle:0);angles_TIR=(90:-min_angle:dividing_angle); F$M^}vsjGx  
    num_Core=length(angles_Core);num_TIR=length(angles_TIR); FF#T"y0Y  
    for i=1:(num_Core) zcGmru|k  
    a_Core(i)=(angles_Core(i)*pi/180); H\RejGR  
    k1(i)=cot(a_Core(i)); -!q^/ux  
    k2(i)=(-k1(i)+(n^2*k1(i)^2+n^2)^(1/2))/(n^2*k1(i)^2-k1(i)^2+n^2); 8 kvF~d ;  
    end *O_>3Hgl  
    k1(num_Core)=999;k2(num_Core)=0; /*P) C'_M  
    for i=1:num_TIR 5:|9pe)  
    a_TIR(i)=(angles_TIR(i)*pi/180); Y O&@  
    k3(i)=tan((pi/2+asin(cos(a_TIR(i))/n))/2); > 9.%hSy  
    k4(i)=tan(asin(cos(a_TIR(i))/n)); KrdEB0qh  
    end F_G .$a Cc  
    X0_TIR=R;X0_Core=r;Y0_TIR=0;Y0_Core=r*cot(a_Core(1)); jIEntk  
    DQ<4`wEM  
    % The Third Step:Solve functions L+N\B@ 0-  
    for i=1:num_Core                    %Solve the curve of Core U$|q]N  
    syms x; uP G\1  
    f1=k1(i)*x; `R;i1/  
    f2=k2(i)*(x-X0_Core)+Y0_Core; t'1g+g  
    f=f1-f2; $Q"D>Qf{G  
    x=double(solve(f));y=k1(i)*x; Me79:+d  
    X0_Core=x;Y0_Core=y; (@->AJF1\  
    Px_Core(i)=X0_Core;Py_Core(i)=Y0_Core; AXF 1{  
    end F Y<Q|Ov  
    for i=1:num_TIR                      %Solve the curve of TIR $GP66Ev  
    syms x; pT{is.RM  
    f1=k3(i)*(x-X0_TIR)+Y0_TIR; 3^[P  
    f2=k4(i)*(x-r)+r*cot(a_TIR(i)); _B>'07D0  
    f=f1-f2; [Do^EJ  
    x=double(solve(f));y=k3(i)*(x-X0_TIR)+Y0_TIR; =p^$>o  
    X0_TIR=x;Y0_TIR=y; {0~\T[qm  
    Px_TIR(i)=X0_TIR;Py_TIR(i)=Y0_TIR; 4%2APvLW  
    end \3OEC`  
    ~UJ.A<>Fh  
    % The furth Step:Fitting the curve tn#cVB3  
    P_Core=polyfit(Px_Core,Py_Core,4); p#).;\M   
    P_TIR=polyfit(Px_TIR,Py_TIR,4); ~| b\1SR  
    793 15A  
    % The fifth Step:Feedback chief dimensions of the lens and Create it %N)B8A9kh  
    %Feedback dimensions of the whole lens Z#.1p'3qm1  
    result='透镜尺寸如下:' 7HkFDI()1  
    Diameter_of_lens=2*Px_TIR(num_TIR) yX4 Vv{g  
    Thickness_of_lens=Py_TIR(num_TIR)+d ! ui   
    Diameter_of_Core=2*r &Ts!#OcB,  
    Thickness_of_front_pannel=d NB1KsvD{  
    Bottom_thickness=R-r +j{(NwsX  
    Lowest_Core=P_Core(5) "I66 @d?  
    \_WR:?l  
    %Feedback dimensions of Lens part TIR EjL]#,QR  
    result='TIR系数如下:' ^R=`<jx   
    Thickness=Py_TIR(num_TIR)-P_TIR(5)+d vhPlH0  
    Aperture=Px_TIR(num_TIR) ,VS(4  
    Obstruction=r >ei~:z]R  
    Position=P_TIR(5) o2X95NiH  
    format short e; OHi.5 (  
    Aspheric=[P_TIR(4) P_TIR(3) P_TIR(2) P_TIR(1)] ?h6|N%U'  
    format short; 9 wZ?")2  
    2HtsSS#0Q  
    %DDE Connection 5CZyA`3V^5  
    TP_COMMAND = ddeinit('TracePro','Scheme'); PJiU2Y33  
    %Create TIR E/g"}yR  
    cmd =['(define TIR (insert:lens-element "PLASTIC" "pmma" (list 0 0 7.0306e-002 1.2580e-001 -2.5732e-003 -2.5281e-006) 18.6774 (list 0 0)(list "cir" 13.6051 0 0 0)(list "cir" 3.25 0 0 0)))']; Asv]2> x  
    ddeexec(TP_COMMAND,cmd);  Z/%FQ  
    cmd =['(entity:move TIR 0 0 -2.3712)']; QuqznYSY{  
    ddeexec(TP_COMMAND,cmd); *#'j0;2F  
    cmd =['(property:apply-name TIR "TIR")']; ''YqxJ fb  
    ddeexec(TP_COMMAND,cmd); H,]8[ qT<  
    Bhxs(NO  
    %Feedback dimensions of Lens part TIR &nP0T-T5y  
    result='Core系数如下:' o>_})WM1[  
    Thickness=Py_TIR(num_TIR)-P_Core(5)+d R|n  
    Aperture=r "aOs#4N  
    Obstruction='None' i+h*<){X  
    Position=P_Core(5) tGgxID  
    format short e; Ec!!9dgRQ  
    Aspheric=[P_Core(4) P_Core(3) P_Core(2) P_Core(1)] l3sF/zkH  
    format short; !{g<RS( c  
    %Create Core ao2^3e  
    cmd =['(define Core (insert:lens-element "PLASTIC" "pmma" (list 0 0 -2.6211e-002  1.9124e-001 -1.7949e-002  2.8016e-004) 10.3569 (list 0 0)(list "cir" 3.2500 0 0 0)))']; O;~e^ <*  
    ddeexec(TP_COMMAND,cmd); 1(-!TJ{  
    cmd =['(entity:move Core 0 0 5.9493)']; ~.aR=m\#  
    ddeexec(TP_COMMAND,cmd); &1$d`>fn  
    cmd =['(property:apply-name Core "Core")']; x=t(#R m  
    ddeexec(TP_COMMAND,cmd); g3z/yj  
    J-hJqR*;K  
    %Create Lens 6@s!J8!  
    cmd =['(define Unite (bool:unite TIR Core))']; q2*A'C  
    ddeexec(TP_COMMAND,cmd); Z+&V  >  
    cmd =['(define block (insert:block 100 100 100))']; N[p o)}hp  
    ddeexec(TP_COMMAND,cmd); D`T;j[SsS#  
    cmd =['(entity:move block 0 0 -50)']; SI=$s>1  
    ddeexec(TP_COMMAND,cmd); !l9{R8m>eJ  
    cmd =['(define Lens (bool:subtract Unite block))']; tw_o?9  
    ddeexec(TP_COMMAND,cmd); SLKpl LO  
    cmd =['(property:apply-name Lens "Lens")']; xvV";o  
    ddeexec(TP_COMMAND,cmd); 5p (zhfuG  
    s0/O/G?  
    %Close the DDE connection QWk3y"5n<  
    ddeterm(TP_COMMAND); v>_@D@pr  
    离线leav01
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    只看该作者 19楼 发表于: 2016-11-22
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