切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 11594阅读
    • 27回复

    [求助]matlab画准直透镜曲线? [复制链接]

    上一主题 下一主题
    离线2102
    发帖
    111
    光币
    141
    光券
    0
    只看该作者 10楼 发表于: 2013-04-16
    謝謝大大的分享
    离线gsh1128
    发帖
    586
    光币
    169
    光券
    0
    只看该作者 11楼 发表于: 2013-06-24
    算出来也就自然画出来了啊
    离线ciomplj
    发帖
    319
    光币
    1
    光券
    0
    只看该作者 12楼 发表于: 2014-06-22
    谢谢哈~
    离线hjg888
    发帖
    39
    光币
    22
    光券
    0
    只看该作者 13楼 发表于: 2014-09-25
    看一下
    离线zouzili
    发帖
    100
    光币
    5
    光券
    0
    只看该作者 14楼 发表于: 2014-12-29
    下来看看
    离线whyhao99
    发帖
    718
    光币
    64
    光券
    0
    只看该作者 15楼 发表于: 2015-07-15
    学习一下
    离线wenge
    发帖
    21
    光币
    9
    光券
    0
    只看该作者 16楼 发表于: 2016-01-11
    看看吧
    离线liunian
    发帖
    7
    光币
    3
    光券
    0
    只看该作者 17楼 发表于: 2016-07-13
    看看e:matlab画准直透镜曲线?
    离线liunian
    发帖
    7
    光币
    3
    光券
    0
    只看该作者 18楼 发表于: 2016-07-13
    程序如下: `Aw^H!  
    % By Ruibin 08-9-25 -:|?h{q?u  
    % InstructionThis program help design LED collimating lens , feedback aspheric parameters and several chief dimensions. s5CXwM6cx  
    L^}_~PO N5  
    clear all;clc AK'[c+2[  
    j(m.$:  
    % The Frist Step: Define independent parameters (gP)%  
    r=3.25;               %选择开孔半径 ;j[>9g  
    R=4.25;               %定义曲面底部半径 ,\_1w  
    d=1;                  %设置透镜前方平板高度 ii T"5`KY  
    n=1.4935;             %定义材料折射率 ,{M^-3C  
    dividing_angle=24;    %定义CoreTIR的分界角 W42 iu"@  
    min_angle=1;          %设置计算精度 zHA!%>%'  
    N=4;                  %设定拟合非球面系数阶数 \-h%O jf4  
    8(pp2rlR  
    % The Second StepCaculate induced variable d,+Hd2o^X  
    angles_Core=(dividing_angle:-min_angle:0);angles_TIR=(90:-min_angle:dividing_angle); vdAr|4^qB  
    num_Core=length(angles_Core);num_TIR=length(angles_TIR); ''yB5#^w(  
    for i=1:(num_Core) "I3@m%qv  
    a_Core(i)=(angles_Core(i)*pi/180); > V-A;S:  
    k1(i)=cot(a_Core(i)); ;_c;0)  
    k2(i)=(-k1(i)+(n^2*k1(i)^2+n^2)^(1/2))/(n^2*k1(i)^2-k1(i)^2+n^2); b$N 2z  
    end X{5vXT\/y  
    k1(num_Core)=999;k2(num_Core)=0; Bt@^+vH ~  
    for i=1:num_TIR wPQH(~k:  
    a_TIR(i)=(angles_TIR(i)*pi/180); .+PI}[g  
    k3(i)=tan((pi/2+asin(cos(a_TIR(i))/n))/2); 6 Q%jA7  
    k4(i)=tan(asin(cos(a_TIR(i))/n)); e7 ^mmm  
    end Q-_N2W ?  
    X0_TIR=R;X0_Core=r;Y0_TIR=0;Y0_Core=r*cot(a_Core(1)); QoI3>Oj=  
    [w0QZyUn  
    % The Third Step:Solve functions '))0Lh l  
    for i=1:num_Core                    %Solve the curve of Core Q_"]+i]s@  
    syms x; a =J^  
    f1=k1(i)*x; |:nn>E}ZA/  
    f2=k2(i)*(x-X0_Core)+Y0_Core; smlpD3?va  
    f=f1-f2; "|EM;o  
    x=double(solve(f));y=k1(i)*x; :ci5r;^  
    X0_Core=x;Y0_Core=y; x-$&g*<  
    Px_Core(i)=X0_Core;Py_Core(i)=Y0_Core; KI)M JG:t  
    end %RTBV9LIXr  
    for i=1:num_TIR                      %Solve the curve of TIR T -.%  
    syms x; YmL06<Mh  
    f1=k3(i)*(x-X0_TIR)+Y0_TIR; Oxm>c[R  
    f2=k4(i)*(x-r)+r*cot(a_TIR(i)); 9]k @Q_  
    f=f1-f2; w mn+  
    x=double(solve(f));y=k3(i)*(x-X0_TIR)+Y0_TIR; CSJdvxb  
    X0_TIR=x;Y0_TIR=y; fT;s-v[`k  
    Px_TIR(i)=X0_TIR;Py_TIR(i)=Y0_TIR; um jt]Gu[  
    end 2GP=&K/A  
    gqZ'$7So  
    % The furth Step:Fitting the curve qraSRK5  
    P_Core=polyfit(Px_Core,Py_Core,4); nr95YSH  
    P_TIR=polyfit(Px_TIR,Py_TIR,4); 9Vg?{v!yn  
    ,vr? 2k  
    % The fifth Step:Feedback chief dimensions of the lens and Create it \HqNAE2T  
    %Feedback dimensions of the whole lens WA5&# kg\  
    result='透镜尺寸如下:' h{CL{>d  
    Diameter_of_lens=2*Px_TIR(num_TIR) HHA<IZ#;,  
    Thickness_of_lens=Py_TIR(num_TIR)+d o)h_H;  
    Diameter_of_Core=2*r h?AS{`.1  
    Thickness_of_front_pannel=d hpHr\g  
    Bottom_thickness=R-r ?qP7Y nl  
    Lowest_Core=P_Core(5) Yrb{ByO&  
    %aHB"vi6  
    %Feedback dimensions of Lens part TIR $:8x(&+/@  
    result='TIR系数如下:' \z>fb%YW  
    Thickness=Py_TIR(num_TIR)-P_TIR(5)+d (uXL^oja  
    Aperture=Px_TIR(num_TIR) YJ^] u}  
    Obstruction=r gR&Q3jlIV  
    Position=P_TIR(5) _t iujP  
    format short e; L9r8BK;  
    Aspheric=[P_TIR(4) P_TIR(3) P_TIR(2) P_TIR(1)] G/k2Pe{SL  
    format short; lG9bLiFY  
    P 0SQr?W  
    %DDE Connection |nc@"OJ  
    TP_COMMAND = ddeinit('TracePro','Scheme'); ERUz3mjA/  
    %Create TIR c?tBi9'Y]  
    cmd =['(define TIR (insert:lens-element "PLASTIC" "pmma" (list 0 0 7.0306e-002 1.2580e-001 -2.5732e-003 -2.5281e-006) 18.6774 (list 0 0)(list "cir" 13.6051 0 0 0)(list "cir" 3.25 0 0 0)))']; Ok|*!!T  
    ddeexec(TP_COMMAND,cmd); (]Z_UTT  
    cmd =['(entity:move TIR 0 0 -2.3712)']; ~FZ&.<s  
    ddeexec(TP_COMMAND,cmd); lAS#874dE  
    cmd =['(property:apply-name TIR "TIR")']; \RNNg  
    ddeexec(TP_COMMAND,cmd); A}BVep@D  
    _Us#\+]_:  
    %Feedback dimensions of Lens part TIR rxe >}ZO  
    result='Core系数如下:' O [\i E5+$  
    Thickness=Py_TIR(num_TIR)-P_Core(5)+d aAZZ8V  
    Aperture=r x/NfZ5e0X  
    Obstruction='None' sr r :!5  
    Position=P_Core(5) Cw iKi^m  
    format short e; _64A( U  
    Aspheric=[P_Core(4) P_Core(3) P_Core(2) P_Core(1)] -Y1e8H ='  
    format short; |EIng0a  
    %Create Core Sj-n;F|=X  
    cmd =['(define Core (insert:lens-element "PLASTIC" "pmma" (list 0 0 -2.6211e-002  1.9124e-001 -1.7949e-002  2.8016e-004) 10.3569 (list 0 0)(list "cir" 3.2500 0 0 0)))']; j:^#rFD4?  
    ddeexec(TP_COMMAND,cmd); s28`OKC}  
    cmd =['(entity:move Core 0 0 5.9493)']; pf2[ , v/  
    ddeexec(TP_COMMAND,cmd); 3]OE}[R  
    cmd =['(property:apply-name Core "Core")']; Bgn&:T8<  
    ddeexec(TP_COMMAND,cmd); &x=.$76  
    v6[!o<@"a  
    %Create Lens .sxcCrQE  
    cmd =['(define Unite (bool:unite TIR Core))']; uX"H4l O~  
    ddeexec(TP_COMMAND,cmd); g9m-TkNk  
    cmd =['(define block (insert:block 100 100 100))']; 1[mXd  
    ddeexec(TP_COMMAND,cmd); XQrF4l  
    cmd =['(entity:move block 0 0 -50)']; QMA%$  
    ddeexec(TP_COMMAND,cmd); S$f9m  
    cmd =['(define Lens (bool:subtract Unite block))']; #Z}Rf k(~  
    ddeexec(TP_COMMAND,cmd); w ~.f  
    cmd =['(property:apply-name Lens "Lens")']; <>n0arAn  
    ddeexec(TP_COMMAND,cmd); 9 3U_tQ&1?  
    <vnHz?71c  
    %Close the DDE connection GSY(  
    ddeterm(TP_COMMAND); Kh"?%ZIa  
    离线leav01
    发帖
    36
    光币
    1
    光券
    0
    只看该作者 19楼 发表于: 2016-11-22
    学习学习