答案: }>I|\Z0I
_5(lp} s
average luminance L= Luminous instensity / Emitter_Area =16000cd/ (1.5~2x0.19x0.6)cm^2 =70000cd/cm^2~94000cd/cm^2. dd#=_xe
x2*l5t
即平均亮度约在70000cd/cm^2~94000cd/cm^2范围,所以specsheet 写90000cd/cm^2是有道理的。 oa(R,{_*q
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谨供参考。 )mw#MTv<[
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