切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 1737阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激 ,DKW_F|  
    fNr*\=$  
    2d centered Fourier transform,居中的傅里叶变换 a"O9;&}; &  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%  0Ns Po  
    % Citation for this code and algorithm: bN*zx)f  
    % Tatiana Latychevskaia and Hans-Werner Fink W*c^(W  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", Rv*x'w ==  
    % Appl. Optics 54, 2424 - 2434 (2015) R{4[.  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%  qzD  
    % The code is written by Tatiana Latychevskaia, 2002 PClwGO8'&  
    % The version of Matlab for this code is R2010b 7<Ut/1$MI  
    O6-"q+H)  
    function [out] = FT2Dc(u0); AxJf\B8  
    ~}YgZ/U7T  
    [Nx, Ny] = size(1i,1j); .R+n}>+K  
    bxz6 >>  
    f1 = zeros(Nx,Ny); uN9.U  _  
    az:lG(ZGw  
    for ii = 1:Nx A|L-;P NP  
        for jj = 1:Ny 1eqFMf  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); e]jzFm~  
        end 1p>&j%dk  
    end (j}Wt8  
    K0^+2lx  
    FT = fft2(f1.*in); %gEfG#S  
    ?IG+U TI  
    out = f1.*FT; wd:SBU~f5*  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教