切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 1983阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激 l?[{?Luq  
    ]k[ Q]:q  
    2d centered Fourier transform,居中的傅里叶变换 k%EWkM)?  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% :Az8K)  
    % Citation for this code and algorithm: yPf?"W  
    % Tatiana Latychevskaia and Hans-Werner Fink pchQ#GU  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", }G>v]bV0V  
    % Appl. Optics 54, 2424 - 2434 (2015) ;yk9(wea}"  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% jgk{'_ j  
    % The code is written by Tatiana Latychevskaia, 2002 A5CdLwk  
    % The version of Matlab for this code is R2010b Ez zTJ>  
    dIoF~8V  
    function [out] = FT2Dc(u0); K(-G: |  
    %/{IssCR7  
    [Nx, Ny] = size(1i,1j); @Ufa -h5"(  
    VKq0 <+M  
    f1 = zeros(Nx,Ny); 07.nq;/R  
    :wQC_;  
    for ii = 1:Nx .o-0aBG  
        for jj = 1:Ny @rPI$ia1~  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); Ivz+Jj w  
        end GwgFi@itN  
    end _ oQtk^fp  
    [Xxw]C6\>(  
    FT = fft2(f1.*in); #^5a\XJb  
    Cr' ! "F  
    out = f1.*FT; GLo\q:5A  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教