切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 1935阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激  4j*  
    EfqX y>W  
    2d centered Fourier transform,居中的傅里叶变换 rjK%t|aV^  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% T;4NRC  
    % Citation for this code and algorithm: &j;wCvE4+  
    % Tatiana Latychevskaia and Hans-Werner Fink Q 3 ea{!r  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", |NlO7aQ>2H  
    % Appl. Optics 54, 2424 - 2434 (2015) <;lkUU(WT2  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Q1Kfi8h}'  
    % The code is written by Tatiana Latychevskaia, 2002 sWhZby7  
    % The version of Matlab for this code is R2010b .7J#_* N V  
    9p]QM)M  
    function [out] = FT2Dc(u0); !M(xG%M-V  
    &s(^@OayE  
    [Nx, Ny] = size(1i,1j); jV i) Efy  
    {$oj.V 4  
    f1 = zeros(Nx,Ny); YqscZ(L:y  
    \$K20)  
    for ii = 1:Nx  8$=n j  
        for jj = 1:Ny H8=N@l  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); xR~h wj  
        end GblA9F7  
    end "69s) ~  
    *;W+>W  
    FT = fft2(f1.*in); Zpt\p7WQ  
    }PlRx6r@  
    out = f1.*FT; . '6gZKXY  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教