切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 2020阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激 /%rbXrR4w  
    +:~&"U^ z&  
    2d centered Fourier transform,居中的傅里叶变换 {`KgyC W:  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% y^hpmTB3"  
    % Citation for this code and algorithm: hX 9.%-@sR  
    % Tatiana Latychevskaia and Hans-Werner Fink s+tS4E?  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", -^$CGRE6A  
    % Appl. Optics 54, 2424 - 2434 (2015) }!& w<wR  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% _W]2~9  
    % The code is written by Tatiana Latychevskaia, 2002 u sR19_E-  
    % The version of Matlab for this code is R2010b |VlAt#E  
    pt(GpbtWK  
    function [out] = FT2Dc(u0); YurK@Tq7  
    %7O`]ik:  
    [Nx, Ny] = size(1i,1j); fmA&1u/xMs  
    H[<"DP  
    f1 = zeros(Nx,Ny); {j,bV6X  
    nPfVZGt  
    for ii = 1:Nx  -deY,%  
        for jj = 1:Ny PFG):i-?  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); 5cxA,T  
        end NV*aHci  
    end xh @H@Q\  
    >('L2]4\v  
    FT = fft2(f1.*in);  t\{q,4  
    EFf<| v  
    out = f1.*FT; eOD;@4lR  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教