切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 1897阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激 PB #EU 9  
    aqgm  
    2d centered Fourier transform,居中的傅里叶变换 {>3w"(f7o  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% pS8`OBenA  
    % Citation for this code and algorithm: }vZTiuzC  
    % Tatiana Latychevskaia and Hans-Werner Fink P!!:p2fo  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", v?o("I[ C  
    % Appl. Optics 54, 2424 - 2434 (2015) M8VsU*aU  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% ! QKec  
    % The code is written by Tatiana Latychevskaia, 2002 !N/?b^y  
    % The version of Matlab for this code is R2010b F<O<=Ww  
    `a8&7 J(  
    function [out] = FT2Dc(u0); {DX1/49  
    G{.A5{  
    [Nx, Ny] = size(1i,1j); A QPzId*z  
    '<h@h*R  
    f1 = zeros(Nx,Ny); GPAz#0p  
    p]6/1&t="  
    for ii = 1:Nx F~3 &@TWi  
        for jj = 1:Ny kZQ$Iv+^(  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); rUmnv%qTS  
        end ,%KMi-w]q,  
    end R7Ns5s3X  
    9abn6S(XpJ  
    FT = fft2(f1.*in); _<jccQ  
    XRn+6fn|  
    out = f1.*FT; 6MbMAh5>  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教