切换到宽版
  • 广告投放
  • 稿件投递
  • 繁體中文
    • 1790阅读
    • 1回复

    [求助]相位恢复算法 [复制链接]

    上一主题 下一主题
     
    发帖
    4
    光币
    2
    光券
    0
    只看楼主 倒序阅读 楼主  发表于: 2020-05-29
    有会相位恢复算法的吗?能帮我看看下面的代码错哪儿了吗?不胜感激 Y<1]{4Wt  
    a3i;r M2  
    2d centered Fourier transform,居中的傅里叶变换 . Y@)3  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% LHy-y%?i  
    % Citation for this code and algorithm: 2VSs#z!  
    % Tatiana Latychevskaia and Hans-Werner Fink h7 uv0a~0  
    % "Practical algorithms for simulation and reconstruction of digital in-line holograms", R 2.y=P8N  
    % Appl. Optics 54, 2424 - 2434 (2015) E]Wnl\Be  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% <<Zt.!hS  
    % The code is written by Tatiana Latychevskaia, 2002 -s ]  
    % The version of Matlab for this code is R2010b >LqW;/&S<  
    'VH%cz*  
    function [out] = FT2Dc(u0); c{X>i>l>  
    z x e6M~+  
    [Nx, Ny] = size(1i,1j); V s/Z8t  
    MSef2|"P#  
    f1 = zeros(Nx,Ny); W PDL$y  
    Z{' .fq2A  
    for ii = 1:Nx FPg5!O%  
        for jj = 1:Ny .nGYx  
             f1(ii,jj) = exp(1i*pi*(ii + jj)); c UJUZ@ol  
        end Y$tgz)  
    end {'(1c)q>  
    A4C4xts]N  
    FT = fft2(f1.*in); B Q) 1)8r  
    :#yjg1aej  
    out = f1.*FT; u<}PcI.  
    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
     
    分享到
    发帖
    4
    光币
    2
    光券
    0
    只看该作者 1楼 发表于: 2020-05-29
    求大神指教