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wuxujiong:某个位置的slope角计算 @ang == (sagf(5,1,0,(sd s5)+0.002)-sagf(5,1,0,(sd s5)))/0.002 (2019-12-24 08:55) _Pl5?5eZj
k0184990:這段公式是取 0.002 為一長度? 計算區間量的斜率嗎? (2020-11-03 11:29) :b(Nrj&TQ[
scuti:srm fl r1 s8 ,srm是面角度法线的cos值, g66SCr} (2020-11-06 17:00) P] qL&_