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    [求助]请教:Tracepro中照度图选项中选择归一化和不选择归一化选项有什么区别? [复制链接]

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    离线ruskie
     
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    只看楼主 倒序阅读 楼主  发表于: 2008-05-10
    Tracepro照度图选项中有一项“Normalize to emitted flux”,选择和不选择的情况出来的照度图有什么区别?哪位能详细解答一下。 5dYIL`  
     
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    离线suezl9
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    只看该作者 1楼 发表于: 2008-05-12
    说明书:规范从所有发光源发出的所有出射通量给图的数据,这个选项允许你使通量和光照规范为总共的通量,如果这个框被选中后,TracePro在光照度图中使用出色通量来除以总通量。这对于在光学系统计算的系统透射率和照明系统中计算发光效率,会非常有用。 >@]E1Qfe  
    也就是说,比如你的总光源有10lm,得出的照度图在没有选择norm~选项的时候是显示正常的照度,在勾选了之后显示的照度值是原来的/总流明,可以认为是没流明所产生的照度值
    离线ruskie
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    只看该作者 2楼 发表于: 2008-05-13
    谢谢版主的耐心解答,^_^
    离线qiudonglai
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    只看该作者 3楼 发表于: 2008-08-19
    suezl9 94K ;=5h  
    哈哈
    离线norrin
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    只看该作者 4楼 发表于: 2008-08-21
    有中文说明书么?可以共享一下么?
    离线lightgirl
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    只看该作者 5楼 发表于: 2008-08-22
    Normalize X)nOY*  
    Normalize the map data to the total emitted flux from all sources. ;7 IVg[f  
    This option allows you to have the flux and irradiance normalized to the total .X:{s,@  
    emitted flux. When this box is checked, TracePro divides the values in the v,>q]! |a  
    irradiance map and the total flux by the emitted flux. This is especially useful for IM +Dm  
    calculating system transmittance for an optical system, or lighting efficiency for a HkrNh>^=  
    lighting calculation. poXkH@[O  
    Example 1: System Transmittance {]Lc]4J  
    Suppose you need to calculate the system transmittance of an optical system. 6j` waK  
    You would probably use the grid raytrace option, and the emitted flux is equal to A= ,q&  
    the sum of the flux in all the emitted rays. When you display an irradiance map, ;$|+H"g|  
    the system transmittance is equal to the total flux, displayed at the bottom of the ytAhhwN~  
    irradiance map window, divided by the emitted flux. To get the system ~zRW*pd  
    transmittance, check the Normalize to emitted flux box and press the Apply qqkZbsN  
    button. The map will be redisplayed, and the Normalized Flux value will be equal d628@~ Ekn  
    to the system transmittance. R[_7ab]A  
    Example 2: Lighting Efficiency Gg-<3z  
    Suppose you need to calculate the lighting efficiency of a luminaire in illuminating Nwu#,f=X  
    a plane. You would probably choose the Surface Source raytrace option, and the +vYm:  
    emitted flux is equal to the flux you specified when you defined the sources. When ?]P&3UU>0z  
    you display an irradiance map, the total flux incident on the observation plane is hs/nM"V  
    displayed at the bottom of the window. The lighting efficiency is equal to the total px-*uh<  
    flux divided by the emitted flux. To get the lighting efficiency directly, check the E6@+w.VVO  
    Normalize to emitted flux box and press the Apply button. The map will be "`&?<82  
    redisplayed, and the Normalized Flux value will be equal to the lighting efficiency PE4{;|a }  
    of the luminaire.
    离线kaoyanming
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    只看该作者 6楼 发表于: 2015-06-02
    可以看成均匀性吗?