zemax物理光学能量问题-ZEMAX,OpticStudio-光行天下-最大的光电技术社区-光学,光电,光机技术及其软件运用交流社区!

首页 -> 登录 -> 注册 -> 回复主题 -> 发表主题

光行天下 -> ZEMAX,OpticStudio -> zemax物理光学能量问题 [点此返回论坛查看本帖完整版本]

[打印本页]

诸葛随风	2016-07-20 15:26
zemax物理光学能量问题请问一下，我在zemax物理光学传播（physical opticals propagation 里看到了以total power的量，这个量代表的是光束的能量吗 Rg46V-"d,@ 0yMHU[):~ [attachment=71423]

hopebox	2016-07-20 16:07
Under POP propagation you will see Beam Definition, under this tab you can define either the "Total Power" of the beam or the "Peak Irradiance". So the total power returns under the window (as you captured) will be reporting the total power with respect to the energy defined under this "Beam Definition". Y,,Z47% E

诸葛随风

2016-07-21 09:49

hopebox:Under POP propagation you will see Beam Definition, under this tab you can define either the "Total Power" of the beam or the "Peak Irradiance". So the total power returns under the window (as you captured) will be reporting the total power .. (2016-07-20 16:07) ft0d5n!ui4

选择total power 和 peak irradiance会有什么不同呢，还有我想改变镜子大小来看光的通过率，设定选择surface type里的 aperture type 里的通光孔径的大小，再看total power 的大小，这样是不是可以说明不同半径下光的通过率啊。

hopebox

2016-07-21 15:47

诸葛随风:选择total power 和 peak irradiance会有什么不同呢，还有我想改变镜子大小来看光的通过率，设定选择surface type里的 aperture type 里的通光孔径的大小，再看total power 的大小，这样是不是可以说明不同半径下光的通过率啊。 (2016-07-21 09:49) pMAFZfte!x

Whether choosing Total power or peak irradance, the energy/power of beam as a function of radius will just be calculated relatively to how you define it. So it shouldn't matter, and just depends on how the source beam is defined though (since the beam profile is there).

I think the method you proposed shall return the physical quantity you want to study. Hope this helps.

诸葛随风

2016-07-22 13:26

hopebox:Whether choosing Total power or peak irradance, the energy/power of beam as a function of radius will just be calculated relatively to how you define it. So it shouldn't matter, and just depends on how the source beam is defined though (since the beam pro .. (2016-07-21 15:47) .^ba*qb`{

我想了解不同镜子尺寸光的损失，不知道能不能通过看total power损失来研究呢

alien21	2016-07-22 15:10
为什么不直接看透过率呢

诸葛随风	2016-07-24 09:30
alien21:为什么不直接看透过率呢 (2016-07-22 15:10) >YcaFnY VLbbn 透过率？怎么弄啊？

hopebox	2016-07-25 21:13
诸葛随风:透过率？怎么弄啊？ (2016-07-24 09:30) #[Rs&$vQm jcRe), Yes, Alien21 is right, you could check Polarization > Transmission as a way to check it, too. Zlrbd FgMQ=O2 If using POP, make sure you tick the box of "Use Polarization". So the total power shall account all sorts of energy loss.

光润	2016-07-26 17:12
谢谢楼主

爱因斯谭	2016-07-27 10:16
学习一下 WwxV}?Cf+

thorn12345

2017-10-20 10:25

hopebox:Yes, Alien21 is right, you could check Polarization > Transmission as a way to check it, too. ??("0U
If using POP, make sure you tick the box of "Use Polarization". So the total power shall account all sorts of energy loss. (2016-07-25 21:13) J7t) H_S{

非序列照明的情况，问下，zemax里非序列编辑器中的内置于（“inside of”）怎么用？如果光源是在环形中空的球体中心，inside of 算是在物体内还是物体外呢

thorn12345

2017-10-20 10:28

hopebox:Yes, Alien21 is right, you could check Polarization > Transmission as a way to check it, too. u`Kc\BSn
If using POP, make sure you tick the box of "Use Polarization". So the total power shall account all sorts of energy loss. (2016-07-25 21:13) 12Fnv/[n'K

非序列编辑器中，能同时设置两个不同的发光光源吗？可以的话怎么设置呢？
还有就是如果可以设置的话，探测器 Detector 能同时分析透过某处这两个不同波长的光能量吗

thorn12345	2017-10-20 11:38
求解答

hopebox	2017-11-16 16:45
thorn12345:求解答 (2017-10-20 11:38) K)h<#F c)q=il7ef Yes, you could set up more than one sources and the detector will pick up all the energy that falls on it.

查看本帖完整版本: [-- zemax物理光学能量问题 --] [-- top --]