| qlmi |
2006-08-10 13:34 |
关于Effective focal length的问题
ZEMAX中priscription data会给出系统的许多有用的数据,其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致,这时怎么回事? [5!{>L` 一下是我的Prescription Data数据: Z6- GENERAL LENS DATA: J0f!+]~G3 gw">xt5 Surfaces : 3 f6\4,() Stop : 1 7$Wbf4 System Aperture : Object Space NA = 0.12 2B)1
tP Glass Catalogs : Schott a*&&6Fo Ray Aiming : Paraxial Reference, Cache On _V8;dv8 X Pupil shift : 0 ~$//4kES Y Pupil shift : 0 )Pc>+}D Z Pupil shift : 0 x&JD~,Y Apodization : Gaussian, factor = 1.00000E+000 ;gAL_/_ ************************************************************* )p#L "r^) Effective Focal Length : 1.639158 (in air at system temperature and pressure) -s)h
?D Effective Focal Length : 1.639158 (in image space) owyQFk ************************************************************* j4`+RS+q Back Focal Length : -1.061568 zmu+un"\j Total Track : 4.318 8N |K Image Space F/# : 3.417255
$tc1te Paraxial Working F/# : 2.950535 egr"og{ Working F/# : 2.961912 b5.]}>]t Image Space NA : 0.1670788 m;1/+qs0 Object Space NA : 0.12 )_>'D4l? Stop Radius : 0.2398355 q<^MC/] Paraxial Image Height : 0 rf`xY4I\ Paraxial Magnification : 0 dK8dC1@,X; Entrance Pupil Diameter : 0.4796709 0DnOO0Nc Entrance Pupil Position : 0 =HV${+K=~ Exit Pupil Diameter : 2.511155 u"wWekB Exit Pupil Position : 7.420935 WCk. K Field Type : Angle in degrees .r-Zz3 Maximum Field : 0 UKTfLh Primary Wave : 1.31 MXDCOe~07 Lens Units : Millimeters P1^|r} Angular Magnification : 0 YRv96|c, AOwmPHEL Fields : 1 0S&J=2D! Field Type: Angle in degrees 2AMb-&po&f # X-Value Y-Value Weight Jf#-OlEQ 1 0.000000 0.000000 1.000000
}J-e:FUF# Bva2f:)K| Vignetting Factors q
\fyp\z # VDX VDY VCX VCY VAN .A_R6~:: 1 0.000000 0.000000 0.000000 0.000000 0.000000 *XYp~b =&Tuh} Wavelengths : 1 \MdieO* Units: Microns 9%"\s2T # Value Weight '{.8tT?tJ 1 1.310000 1.000000 C(z'oi:f tJ8:S@E3, CARDINAL POINTS: =1VZcLNt \D]9:BNJ Object space positions are measured with respect to surface 1. hM>.xr Image space positions are measured with respect to the image surface. lOe|]pQ., The index in both the object space and image space is considered. lF40n4} suFk<^3 Object Space Image Space oQ*LP{M W = 1.310000 (Primary) ?|
6sTu! ************************************************************ .yD
6$!6 Focal Length : -1.639015 1.639015 [7LdTY"Tl ************************************************************ $A/?evJi8R Focal Planes : 0.313078 -1.159568 P3Vh|<'7 Principal Planes : 1.952094 -2.798584 4vvQ7e7 Anti-Principal Planes : -1.325937 0.479447 >,_0Mem2Rr Nodal Planes : 1.952094 -2.798584 >LH}A6dUC Anti-Nodal Planes : -1.325937 0.479447 k\dPF@~Hvl gh
:5 我用*号,标出了需要注意的地方,请高手指教!
|
|