| qlmi |
2006-08-10 13:34 |
关于Effective focal length的问题
ZEMAX中priscription data会给出系统的许多有用的数据，其中包括effective focal length的数据和主平面位置的数据。但是我发现直接给出的effective focal length数据和根据其定义结合主平面的数据算出来的结果不一致，这时怎么回事？ wn)J XR
一下是我的Prescription Data数据： O(+phRwJ
GENERAL LENS DATA: Ur*6Gi6
_E@ :O +K
Surfaces : 3 IpP~Uz
Stop : 1 SR DXfkoI
System Aperture : Object Space NA = 0.12 !9xp cQ>
Glass Catalogs : Schott bQ~j=\[r
Ray Aiming : Paraxial Reference, Cache On 9 7ql5
X Pupil shift : 0 (PfqRk1Y
Y Pupil shift : 0 <!pY$
Z Pupil shift : 0 @xB*KyUW
Apodization : Gaussian, factor = 1.00000E+000 /="~gq@
************************************************************* QR1{ w'c
Effective Focal Length : 1.639158 (in air at system temperature and pressure) ar:+;.n
Effective Focal Length : 1.639158 (in image space) n> ^[T[.S
************************************************************* 1UKg=A -q
Back Focal Length : -1.061568 /% N r?V
Total Track : 4.318 $z+8<?YD
Image Space F/# : 3.417255 +|tC'gCnV
Paraxial Working F/# : 2.950535 Un sogd
Working F/# : 2.961912 A'2w>8
Image Space NA : 0.1670788 .nyfYa+
Object Space NA : 0.12 e^O(e
Stop Radius : 0.2398355 ,Jd
',>3
Paraxial Image Height : 0 C:Hoq(
Paraxial Magnification : 0 c q$i
Entrance Pupil Diameter : 0.4796709 e*L.U~ZR
Entrance Pupil Position : 0 >Jp:O
7
Exit Pupil Diameter : 2.511155 );FJx~b
Exit Pupil Position : 7.420935 ",! 1m7[wF
Field Type : Angle in degrees e @IA20
Maximum Field : 0 e [8LmuIZ
Primary Wave : 1.31 / z}~zO
Lens Units : Millimeters |O"lNUW
Angular Magnification : 0 {#{DH?=^)u
lg(bDK m
Fields : 1 Uf, 4
Field Type: Angle in degrees U4cY_p?
# X-Value Y-Value Weight 2 aL )
1 0.000000 0.000000 1.000000 )HvnoUO0
s&NX@
Vignetting Factors nB!&Zq
# VDX VDY VCX VCY VAN aJcf`<p
1 0.000000 0.000000 0.000000 0.000000 0.000000 HQB(*
+=:#wz K@
Wavelengths : 1 ;6!Pwb;hY
Units: Microns v{A
KEX*
# Value Weight H=\3Jj (4
1 1.310000 1.000000 Ud!4"<C_
?]x |Zy
CARDINAL POINTS: FHC \?Cg
f/V
2f].
Object space positions are measured with respect to surface 1. _vZ"4L+Iw+
Image space positions are measured with respect to the image surface. VH[hsj
The index in both the object space and image space is considered. v.]Q$q^
0$ -xw
Object Space Image Space 46 PoM
W = 1.310000 (Primary) NM06Q zE
************************************************************ ?`4+c x}n
Focal Length : -1.639015 1.639015 mL4] l(U
************************************************************ qs QNjt
Focal Planes : 0.313078 -1.159568 n+PzA[
Principal Planes : 1.952094 -2.798584 APO>y
Anti-Principal Planes : -1.325937 0.479447 {\(L%\sV@
Nodal Planes : 1.952094 -2.798584 %%4t~XC#
Anti-Nodal Planes : -1.325937 0.479447 |gU(s
BN 4_:
我用*号，标出了需要注意的地方，请高手指教！
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