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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html S{N=9934_  
co-1r/ -O  
其中使用Ghost focus generator后的结果为: < Df2  
Hp[i8PJ  
Ghost Trace Data ,JfP$HJ  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx yYdh+x  
Title: A SIMPLE COOKE TRIPLET. #X2wy$GTG  
Units are Millimeters. 8\p"V.o>  
Wavelength: 0.550000 μm rA}mp]  
Type: Double Bounces JA4}B wn  
The '****' denotes a possible internal focus dF*M"|[  
RMS is the RMS spot radius on axis at the primary wavelength. 9U Hh#  
RMS values of 0.00 indicate that an accurate RMS eo^C[# .  
could not be computed, usually due to ray errors. C9*[/|T  
This analysis may be inaccurate if the system is i!iG7X)qT  
non-rotationally symmetric or uses non-standard surfaces. j{6O:d6([$  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) M5 ^qc  
Surf     Marginal          F/#          RMS cUn>gT  
   1  5.0000E+000     5.737068  3.5355E+000 +'_ peT.8  
   2  4.7160E+000     4.595701  3.3570E+000 *E+VcU  
   1  4.3614E+000     0.990012  3.1277E+000 8+H 0  
   2  2.7155E+000     0.607262  1.9876E+000 1C0' Gf)3  
   3 -2.2309E+000     0.916280  2.6065E+000 wQa,o l_p  
   4 -2.7766E+000     0.514753  0.0000E+000 rU|?3x  
   5 -7.3909E+000     0.888038  0.0000E+000 L nyow}  
   6 -9.0530E+000     0.823473  0.0000E+000 O^@F?CG :1  
   7 -3.4681E+001     0.823473  0.0000E+000 NDJP`FI  
Marginal ray height    :       -34.6809 ^ 4*#QtO  
Chief ray height       :       -24.8107 |XV`A)=f  
Distance to ghost pupil:       -50.9613 t<"%m)J  
Distance to ghost focus:       -57.1176 I@TH^8(  
Effective focal length :         8.2347
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请问这个结果怎么看? )a9C3-8Y'  
s\p 1EL(  
其中:Ghost reflection off surface 2 then 1,什么意思? HVK0NI  
最后的光线高度能用来分析什么?? `26.+>Z7  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 v# e*RI2}  
Effective focal length : 8.2347 @FF80U4'  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? [z!pm-Ir  
`ZT/lB`  
Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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