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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html G[6V=G  
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其中使用Ghost focus generator后的结果为: bWwc2##7jo  
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Ghost Trace Data %`HAg MgP  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx O} QTg  
Title: A SIMPLE COOKE TRIPLET. G(|ki9^@"9  
Units are Millimeters. >mT2g  
Wavelength: 0.550000 μm J`uV $l:  
Type: Double Bounces ar=uDb;  
The '****' denotes a possible internal focus s{KwO+UW  
RMS is the RMS spot radius on axis at the primary wavelength. v%= G~kF}[  
RMS values of 0.00 indicate that an accurate RMS +QuaQ% lA  
could not be computed, usually due to ray errors. @xB"9s  
This analysis may be inaccurate if the system is 2>.B*P  
non-rotationally symmetric or uses non-standard surfaces. c&AA< 6pkv  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) +l2{EiQw  
Surf     Marginal          F/#          RMS UbJ_'>hK6  
   1  5.0000E+000     5.737068  3.5355E+000 Cz Jze  
   2  4.7160E+000     4.595701  3.3570E+000 yu<sd}@  
   1  4.3614E+000     0.990012  3.1277E+000 ,K6s'3O(LW  
   2  2.7155E+000     0.607262  1.9876E+000  _*9eAeJ  
   3 -2.2309E+000     0.916280  2.6065E+000 A/W0O;*q  
   4 -2.7766E+000     0.514753  0.0000E+000 %-i2MK'A  
   5 -7.3909E+000     0.888038  0.0000E+000 wvcG <sj  
   6 -9.0530E+000     0.823473  0.0000E+000 7:R8QS9  
   7 -3.4681E+001     0.823473  0.0000E+000 %[-D&flKC  
Marginal ray height    :       -34.6809 d>)*!l2,C  
Chief ray height       :       -24.8107 z(aei(U=  
Distance to ghost pupil:       -50.9613 H{E223  
Distance to ghost focus:       -57.1176 Qy*`s  
Effective focal length :         8.2347
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请问这个结果怎么看? O]~cv^  
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其中:Ghost reflection off surface 2 then 1,什么意思? #<S+E7uTs  
最后的光线高度能用来分析什么?? :7<spd(%"  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 &o= #P2Qd  
Effective focal length : 8.2347 ]P<u^ `{*  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? )Pakb!0H@t  
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Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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