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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html ^=V b'g3P~  
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其中使用Ghost focus generator后的结果为: H_<hZ UB  
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Ghost Trace Data F9 q9BH  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx NM:\T1  
Title: A SIMPLE COOKE TRIPLET. I-?Dil3  
Units are Millimeters. [W{WfJ-HwG  
Wavelength: 0.550000 μm rLzN #Zoi  
Type: Double Bounces ( 17=|s  
The '****' denotes a possible internal focus d0MF\yxh  
RMS is the RMS spot radius on axis at the primary wavelength. #Kd^t =k  
RMS values of 0.00 indicate that an accurate RMS re;^,  
could not be computed, usually due to ray errors. F1aI4H<(T  
This analysis may be inaccurate if the system is g8^YDrH  
non-rotationally symmetric or uses non-standard surfaces. GN%|'eU  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) {D9m>B3"{  
Surf     Marginal          F/#          RMS bQFMg41*w7  
   1  5.0000E+000     5.737068  3.5355E+000 .*z Wm  
   2  4.7160E+000     4.595701  3.3570E+000 h<8.0  
   1  4.3614E+000     0.990012  3.1277E+000 d}`Z| ex  
   2  2.7155E+000     0.607262  1.9876E+000 .3 JLa8y  
   3 -2.2309E+000     0.916280  2.6065E+000 jx7b$x]  
   4 -2.7766E+000     0.514753  0.0000E+000 2y0J~P!I  
   5 -7.3909E+000     0.888038  0.0000E+000 eAPNF?0yh  
   6 -9.0530E+000     0.823473  0.0000E+000 qB0F9[U  
   7 -3.4681E+001     0.823473  0.0000E+000 71GyMtX   
Marginal ray height    :       -34.6809 yaD_c;  
Chief ray height       :       -24.8107 r%^l~PN  
Distance to ghost pupil:       -50.9613 dvl'Sq<  
Distance to ghost focus:       -57.1176 v.Y?<=E+<d  
Effective focal length :         8.2347
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请问这个结果怎么看? nGqD{!i<  
sD!)=t_  
其中:Ghost reflection off surface 2 then 1,什么意思? +nj 2  
最后的光线高度能用来分析什么?? K_" denzT+  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 g]V_)}  
Effective focal length : 8.2347 :~Z -K\  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? Yi5^# G  
lI<Q=gd  
Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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