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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html I~p*~mLh'  
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其中使用Ghost focus generator后的结果为: y/_=  
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Ghost Trace Data fo/sA9  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx <~v4BiQ3l^  
Title: A SIMPLE COOKE TRIPLET. u| "YS-dH  
Units are Millimeters. @raJB'  
Wavelength: 0.550000 μm 17;9>*O'  
Type: Double Bounces j1+I_   
The '****' denotes a possible internal focus %'=TYvB 2  
RMS is the RMS spot radius on axis at the primary wavelength. F2<Q~gQ;  
RMS values of 0.00 indicate that an accurate RMS (~F}O  
could not be computed, usually due to ray errors. uP8 cW([  
This analysis may be inaccurate if the system is e(1{W P  
non-rotationally symmetric or uses non-standard surfaces. VTDnh*\5  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) ^:f)XZ  
Surf     Marginal          F/#          RMS /L! =##  
   1  5.0000E+000     5.737068  3.5355E+000 C deV3  
   2  4.7160E+000     4.595701  3.3570E+000 4 PU@W o  
   1  4.3614E+000     0.990012  3.1277E+000 &n83>Q  
   2  2.7155E+000     0.607262  1.9876E+000 oHSDi  
   3 -2.2309E+000     0.916280  2.6065E+000 P&Xy6@%[Z  
   4 -2.7766E+000     0.514753  0.0000E+000 |@R/JGB^  
   5 -7.3909E+000     0.888038  0.0000E+000 R&P^rrC@B5  
   6 -9.0530E+000     0.823473  0.0000E+000 9M|#X1r{%{  
   7 -3.4681E+001     0.823473  0.0000E+000 U%VFr#  
Marginal ray height    :       -34.6809 ]eFNR1<OP  
Chief ray height       :       -24.8107 b!"qbC1  
Distance to ghost pupil:       -50.9613 N5cC!K  
Distance to ghost focus:       -57.1176 aGE} EK}  
Effective focal length :         8.2347
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请问这个结果怎么看? 7VkjnG^!:  
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其中:Ghost reflection off surface 2 then 1,什么意思? -,mV~y  
最后的光线高度能用来分析什么?? mc,HliiJ  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 ~WB-WI\  
Effective focal length : 8.2347 +>a(9r|:  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? Q4N0j' QA  
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Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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