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sansummer 2011-06-27 11:39

如何分析Ghost focus generator的结果

例如zemax knowledge base的文章,连接如下:http://www.zemax.com/kb/articles/249/1/How-do-I-Account-for-Energy-Losses-When-Performing-a-Sequential-Ghost-Analysis/Page1.html ~0Z.,p_  
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其中使用Ghost focus generator后的结果为: dwqR,|  
l.xKv$uOGR  
Ghost Trace Data 2&zklXuo:  
File : C:\Program Files\ZEMAX - Beta\Samples\Sequential\Objectives\Cooke 40 degree field.zmx 1<;VD0XX  
Title: A SIMPLE COOKE TRIPLET. D@)L?AB1f  
Units are Millimeters. L./{^)  
Wavelength: 0.550000 μm ^Rb*mI  
Type: Double Bounces Om(Ir&0  
The '****' denotes a possible internal focus oTg 'N  
RMS is the RMS spot radius on axis at the primary wavelength. z#B(1uI  
RMS values of 0.00 indicate that an accurate RMS Vt(s4  
could not be computed, usually due to ray errors. PYiO l  
This analysis may be inaccurate if the system is E1s~ +  
non-rotationally symmetric or uses non-standard surfaces. snYyxi  
Ghost reflection off surface 2 then 1. (GH002001.ZMX) PJPKn0,W  
Surf     Marginal          F/#          RMS @a i2A|  
   1  5.0000E+000     5.737068  3.5355E+000 *)L~1;7j>  
   2  4.7160E+000     4.595701  3.3570E+000 U%n>(!d  
   1  4.3614E+000     0.990012  3.1277E+000 iGN6'm`  
   2  2.7155E+000     0.607262  1.9876E+000 phR:=Ox|1  
   3 -2.2309E+000     0.916280  2.6065E+000 I2WWhsNC  
   4 -2.7766E+000     0.514753  0.0000E+000 mNOx e  
   5 -7.3909E+000     0.888038  0.0000E+000 uann'ho?q  
   6 -9.0530E+000     0.823473  0.0000E+000 z @?WhD  
   7 -3.4681E+001     0.823473  0.0000E+000 j&[u$P*K  
Marginal ray height    :       -34.6809 Nw '$r  
Chief ray height       :       -24.8107 ar _@"+tZ  
Distance to ghost pupil:       -50.9613 %-[*G;c'w  
Distance to ghost focus:       -57.1176 B'I_i$g4w  
Effective focal length :         8.2347
3oV2Ek<d  
请问这个结果怎么看? LIll@2[  
Sd/7#  
其中:Ghost reflection off surface 2 then 1,什么意思? v]#[bqB.b  
最后的光线高度能用来分析什么??  F*_+k  
Distance to ghost pupil: -50.9613 Distance to ghost focus: -57.1176 qJE_4/<^!  
Effective focal length : 8.2347 ux~=}{tz  
这有代表什么,求高手啊
sansummer 2011-06-27 13:58
我现在好像明白一点了,可是这个结果该怎么分析呢?比如这个鬼像发生后的有效焦距8.2347,到底会对成像有多撒影响呢? 1a mEQ  
,H_d#Koa.  
Distance to ghost pupil: -50.9613 Distance to ghost focus到底说明了什么哦
superyu2009 2011-11-22 19:48
用CODE V分析更好
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