this is not easy though...... $+P9@Q$ eA9U|&o I guess you need to give a try as sigma indicates the projected width of 1/e squared value of the peak irrdiance in direction cosine space...... for a normally incidence it should be around ~ cosine 85. Good luck !
Hi MANG2004, d{+H|$L` K;;Q*NN- I am curious about your calculation, too. Plus, the definition of σ refers to 1/e^2 width not the FWHM. Even your calculation/defintion is correct. I have a doubt that it will work when the specualr incident ray angle is not normal......... Ge$cV} UI|L;5 For thsoe who knows it better, please have some input. I am rather curious, too!! Thanks!!
Hi, hopebox, 6"Q/Y[y 3=~"<f
l Thanks for your reply. Really like those words “guess”, “doubt”… L^rtypkJ quk~z};R>\ For your curiosity, have good luck! 6~GaFmW= .E!7}O6 MANG2004 84tuN