991518 |
2009-10-31 20:19 |
优化设计齿轮几何参数编程原理解密
本文系全自动[GAD]齿轮设计软件之内容,限于篇幅,未包含功率部份, 符合ISO.9085 渐开线园柱齿轮标准。 lstnxi%x %B Rll 河海大学常州校区 胡瑞生 2009. 10 . 18 qKuHd~M{ 1 u$x'P <b @=l.J+lh [post]--------------------------------------------------------------- 6wyhL-{: 本程序适用于: 速比 u < 4, 求取最大功率, 而且 k )fLJ9R 一般不发生切削干涉与啮合干涉。 Jqt|'G3 当速比 2 > u > 4 尚需作局部修正 ]5eZLXM -------------------------------------------------------------- '494^1"io 己知: 产品的工作条件: 中心距 [A`] , 速比 [u] I{u+=0^Y 步骤00 1 起步假设 [Z1齿 经验值] hB]<li)"C if ( u <=1.25 )Z1 =41.0 ery{>|k if ( u >1.25 .and. u <=1.50 ) Z1 = 37.0 88atj+N] if ( u >1.50 .and. u <=1.75 ) Z1 = 33.0 -/6Ms%O if ( u >1.75.and. u <=2.00 ) Z1 = 28.0 sH)40QmO{ if ( u >2.00 .and. u <=2.50 ) Z1 = 25.0 8';huq@C{ if ( u >2.50 .and. u <=3.00 ) Z1 = 23.0 BUEV+SZ4 if ( u >3.00 .and. u <=3.50 ) Z1 = 21.0 Hb9r.;r<EW if ( u >3.50 .and. u <=4.00)Z1 = 19.0 Be0v&Q_NK if ( u >4.00 .and. u <=4.50 ) Z1 = 18.0 95 X6V if ( u >4.50 .and. u <=5.00) Z1 = 17.0 iA+zZVwO if ( u >5.00 .and. u <5.50 )Z1 = 16.0 a[V4EX1E if ( u >5.50 .and. u <6.00 )Z1 = 15.0 J`A )WsKkb if ( u >6.00 ) Z1 = 14.0 :}fIu?hCA Z1 = Z1 ot,e?lF Z2 = int ( Z1 * u +0.50 ) 取整数 j|(bdTZY: u = Z2/ Z1 0kld77tn
2 齿 数 比[ u] ≡ u VK$s+" 步骤002起步假设螺旋角 [ β 经验值 ] yvKKE if ( u <=1.25 )β= 24.0 CLY>M`%?+p if ( u >1.25 .and. u <=1.50 ) β= 22.0 3=kw{r[2lM if ( u >1.50 .and. u <=1.75 ) β= 20.0 g6<D 1r if ( u >1.75. and. u <=2.00 ) β= 18.0 n'Z5rXg if ( u >2.00 .and. u <=2.50 ) .β= 16.0 nA XWbavY if ( u >2.50 .and. u <=3.00 ) β= 14.0 P;lDri if ( u >3.00 .and. u <=3.50 ) β= 12.0 T#R*] if ( u >3.50 .and. u <=4.00) β= 11.0 TInp6w+u if ( u >4.00 .and. u <=4.50 ) .β= 10.0 fhQ}Z%$ if ( u >4.50 .and. u <=5.00) β= 10.0 hk+"c^g:j< if ( u >5.00 .and. u <5.50 )β= 9.0 'fY(
Vm if ( u >5.50 .and. u <6.00 )β= 7.0 Pt%EyFG if ( u >6.00 ) β= 6.0 ~px)Jd β= bff r*4@S~; jtt = Atan ( tand (20) /Cos( bff) ) Je;HAhL 压力角 [初值][αt] = jtt ?O#,|\v?] 步骤003 导出 [Axi] 几何性能综合参数概念 C2Af$7c 令 [Axi] ≡ Cos(αt) / [ 2*Cos(β)*Cos(α`) ] E@^mlUf 此系数综合包含螺旋角. 压力角. 啮合角因子, 意义很重要 I)cA:Ip 中心距 [A`] ≡ Mn *Z1 *(1+u) *Axi '9q:gFO 常规采用 [V+] 变位体制齿轮 [V-变位制不利于强度] {,CvWL Axi* Cos(β)≥ 0.5; Axi ≥ 0.5 / Cos(β) R//S(eU68\ β= 5, Axi≥ 0.5019 β=10, Axi≥ 0.5077 Eg|C β=15, Axi≥ 0.5176 β=20, Axi≥ 0.5320 :l?/]K β=22, Axi≥ 0.5392 β=24, Axi≥ 0.5473 dRnO5
7+{ 故 [Axi]max = 0 .5473, [Axi]min = 0.5019 Cr$8\{2OA7 步骤004 计算 模 数 BpZ17"\z [Mn]min ≌ A`/ ( Z1*(1+u)*0 .5473 ) RiM!LX [Mn]max ≌ A`/ ( Z1*(1+u)*0 .5019 ) 3k?|-js 将模 数化为标 准 值 [Mn]≡,Mn Q?TXM1Bp [Mn]≡Mn, call Xg (ch,Mn ) 询问满意否 ? >qjV(_?F- 可人工回答, 如不满意, 可输入新值 y5lhmbl: e 步骤1000 计算啮合角, 先检验以下算式中有否 [Acos]> 1之情况 n!t][d/g+ Mn*Z1*(1+i) /[2*A`] ≡ tan (20)* Cos(α`)/ Sin(αt) RI64QD 令 yyy = 0.5* Mn *Z1*(1.0+ u ) / A` qz/d6-0" Cos(α`) ≡ yyy * Sin(αt ) / tan (20) b&Go'C{p tan (αt) ≡ tan (20) / Cos(β) Y!L<&
sl aaa = yyy * Sin(jtt) / tand (20) E'4dI: [Acos] = aaa 9\D 0mjn=l 步骤011 计算啮合角 {oc7Chv=/H if (aaa >1.0 ) then |F^h>^
x bff = bff -1.0修正 [β`] = bff AIa#t#8${ jtt = Atan( tand (20 ) / Cos(bff) ) LS4|$X4H`! goto 步骤 011 end if
-z$&lP] jpt = ACos ( aaa ) :*{\oqFn~$ 步骤1200检验啮合角. 螺旋角.值之范畴是否合理 ? 8Nz Xe 7 if ( jpt >20 .and .jpt <= 27 ) then b9@VD)J0E go to步骤013 end if go to步骤014 bv8GJ # 步骤013if ( bff >5.0. and. bff<= 24 ) then G@;I^_gN go to步骤1800 end if go to步骤16 o@g/,V $ 步骤014 if ( jpt < 20 ) then hz_F^gF bff = bff - 1.0 修正[β`]= bff $*i"rlJC jtt = Atan ( tand (20) / Cos(bff) ) 5!)_"u3 goto 步骤1000 end if bZsg7[: C 步骤015 If ( jpt >27 ) then -6u#:pVpU bff = bff +1.0修正 [β`] = bff <FFaaGiE> jtt = Atan( tand (20)/Cos(bff) ) =c(3EI'w goto 步骤1000 end if GcYT<pwN6 步骤016 if ( bff < 5.0 ) then y?s8UEC Z1= Z1- 1.0 u = Z2/Z1 C2 ] x go to步骤1000 end if ,HM~Zs 步骤017 if ( bff > 24 ) then 6C|]Fm Z1 = Z1+ 1.0 u = Z2/Z1 *=ymK* go to步骤1000 end if %/x%hs;d 步骤1800 检验中心距系数 Bpw<{U Axo = A` / ( Mn *Z1 *(1.0 + u ) ) "G`8>1tO_ 中心距系数 [初值][Ax]o ≌ Axo +B0G[k7 [Axi] = Cos( jtt ) / ( 2.0 *Cos( bff ) *Cos(jpt ) ) edy6WzxBcm 修正中心距系数值 [Axi] ≡ Axi \v}3j^Yu 步骤020 if (Axi > 0.5019. and. Axi <= 0.576 ) then qxe%RYdA'j go to步骤23 end if T{%'"mm; 步骤021 if ( Axi >0.576 ) then kbkq.fYr Z1= Z1+1.0u = Z2/Z1 B=`"!?we go to步骤1000 endif ^."HD( 步骤022if ( Axi < 0.502 ) then p-t*?p
C Z1= Z1-1.0u = Z2/Z1 -'OO6mU go to步骤1000 end if `i)&nW)R 步骤023Cos(α`) ≡ Cos(αt) / [ 2*Cos(β)*Axi] .5~W3v
< 令qqq = Cos( jtt ) / ( 2 .0 *Cos ( bff) *Axi ) JrdH6Zg jpt = ACos( qqq ) ?~5J!|r# 步骤024if ( jpt >20.0. and. jpt <= 27.0 ) then YQ+Kl[ec go to步骤25 end if go to步骤1200 >O{/%(9 步骤025jtt = Asin ( 2.0 *tand(20) * Cos(jpt) *Axi ) :>t?^r( 核定压力角[αt] ≡ jtt }@V,v[&e bff = Acos( tand (20) / tan(jtt) ) D< | |