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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? 42fprt  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ dM Y 0K  
如下: <eY %sFq,  
!RIH: CHIEF RAY HEIGHT ON IMA cTM$ZNin  
BI};"y  
!CRA: CHIEF RAY ANGLE IN IMA SPACE eUt=n)*`  
+UzXN$73  
!和取最?視角度 }sv!=^}BY3  
OU!nN>ln  
MAXFIELD = MAXF() ~n WsP}`n  
|| [89G  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 GuT6K}~|D  
LfEvc2 v=g  
!獲曲面數 czI{qi5N  
3:l DL2  
n = NSUR()  EZ<80G  
Jen%}\  
!主光線錐激 :X_CFW  
QC{u|  
wepwX y"  
Bz+.Qa+  
RAYTRACE  0, 1, 0, 0, PWAV() 4qt+uNe!  
|QVr `tE<  
QBoFpxh=  
<FUon  
MAX_RIH = RAYY(n) iU5P$7.p  
o~#f1$|Xn  
zG#wu   
I5qM.@%zB  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   bhD ~ 4Rz  
ca(U!T68  
(s s3A9tG  
;1 |x  
PRINT   "MAX FIELD: " , maxfield, O|I+],  
Lz@$3(2  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , HY;9?KJ'  
9_ZBV{   
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH >7'+ye6z  
SWs3SYJ\  
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p&^J=_O  
PRINT "FIELD ",   l$a?A[M$  
D9BQID$R  
PRINT "CHIEF RAY ANGLE," y<uAp  
fN)x#?  
PRINT  "CHIEF RAY HEIGFHT ON IMA." v^SsoX>WMH  
*%\mZ,s"  
2no$+4+z  
"_< 9PM1t  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for sWHyL(C@  
S`m,S4-eD  
7+nm31,<O  
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For j, 0, 20, 1 NF+<#*1  
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FHY = j/20 "uKFOV?j&  
@g-G =Ba  
RAYTRACE  0, FHY, 0, 0, PWAV() =dzWmL<~8  
>2b`\Q*<  
CRA = ACOS(RAYN(n-1))*180/3.1416 gKo%(6{n~  
c.%.\al8oW  
OLDX = CRA icgJ;Q 5  
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OLDY = RAYY(n) ;3"@g]e  
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PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY 5\ hd4  
y$b]7O  
T95t"g?p  
lpgd#vr  
8(f:U@BS  
kWhr1wR1  
NEXT O_;Dk W  
9QwKakci  
!繪出該點數據 XNehPZYS  
-Z0+oU(?YE  
n~.*1. P  
$t}<85YCQ  
GRAPHICS f>polxB%N  
;65D  
?o*I9[Z)  
PuL<^aJ  
RAYTRACE 0, 1, 0, 0, PWAV() e6E?t[hEeS  
z6*<V5<7  
MAX_RIH = RAYY(n) ZnW@YC#9  
2;2}wM[  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 u92^(|  
zMi; A6  
X_WIDE = XMAX() /1.6 (MLwQiop  
-/P\"c  
Y_WIDE = YMAX() /1.6 S( ^.?z  
+4))/` DA  
SEGMENT = 40 ~" i0x  
r(h`XMsU  
FOR j, 0, SEGMENT-1,1 !RW `3  
pkgjTXR2b  
?jx1R^  
NZ0O,} m  
FHY = j/SEGMENT qS| \JG  
c;2#,m^  
RAYTRACE 0, FHY, 0, 0, PWAV() Wb}c=hZv  
O%8EZyu  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 z4X}O {  
8s{?v &p  
RIH = RAYY(n) l{j~Q^U})  
r|u MovnV  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) Dd/wUP  
457\&  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) 0Hxmm@X2  
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q 11IkDa  
$D'- k]E[H  
9h4({EE2t  
#Lv2Zoi>G  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() m,UGWR  
!K f#@0E..  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 4%nE*H%  
j)C,%Ol  
RIH = RAYY(n)       ,'xYlH3s  
y*pUlts<  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) {!t7[Ctb  
x^4xq#Bb7  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) Q/>{f0  
li~d?>  
]vWKR."4  
2'EUy@0  
LINE OLDX,OLDY,NEWX,NEWY nD5 gP  
$6OkIP.  
A$ = "0" aT>'.*\]  
&0 >Loja`^  
gtext OLDX,OLDY,0, A$ 3RLFp\i"s  
QnZcBXI8  
NEXT MjlP+; !  
#]nx!*JNZ  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " \7Jg7*  
OQW#a[=WQ  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" ?7<JQh)"e  
a}%#*J)!  
KD`IX-r{s  
;;L[e]Z  
GRAPHICS OFF *s9C!w YMZ  
d&ex5CU5  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! o.0ci+z@  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 ZovW0Q)m  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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