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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? +XsY*$O  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ q o'1Pknz  
如下: [bAv|;  
!RIH: CHIEF RAY HEIGHT ON IMA qYE-z( i  
(t <Um Vd  
!CRA: CHIEF RAY ANGLE IN IMA SPACE K jLj  
"ey~w=B$M  
!和取最?視角度 IgVxWh#  
?wmr~j  
MAXFIELD = MAXF() Cu}Rq!9i  
I)6)~[:'  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 9%4rO\q  
2D "mq~ V  
!獲曲面數 .; :[sv)  
R\iU)QP  
n = NSUR() >8ePx,+!  
J=() A+  
!主光線錐激 hNQ,U{`;^  
oYu5]ry  
b.$Gc!g  
MVV<&jho{^  
RAYTRACE  0, 1, 0, 0, PWAV() Fd2zvi  
x ha!.&DO  
67d0JQTu  
mWtwp-  
MAX_RIH = RAYY(n) MLUq"f~N  
t.NG ]ejZ  
BONM:(1  
gX);/;9mm+  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   tvI~?\Ylj  
@n<WM@|l  
4%B${zP(.}  
Ix"uk6 h  
PRINT   "MAX FIELD: " , maxfield, c" yf>0  
ZYg="q0x&  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , ^G15]Pyw  
P\SE_*&  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH `6UW?1_Z5  
/+%1Kq.hP  
fY\QI =  
(ZDRjBth[  
PRINT "FIELD ",   }nu hLt1  
C5F}*]E[y  
PRINT "CHIEF RAY ANGLE," V+_L9  
jh9^5"vQ  
PRINT  "CHIEF RAY HEIGFHT ON IMA." `XQM)A  
C%l~qf1n  
'R= r9_%  
6X)8vQH  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for B2VUH..am  
jRzR`>5  
&`{%0r[UD#  
jPhOk>m  
For j, 0, 20, 1 TR| G4l?  
sy4$!,W:  
FHY = j/20 om|M=/^  
Es1Yx\/:  
RAYTRACE  0, FHY, 0, 0, PWAV() PoQ@9 A  
Bm1yBKjO  
CRA = ACOS(RAYN(n-1))*180/3.1416 dX` _Y  
rJ K~kKG  
OLDX = CRA #N wlKZ-  
U_Id6J]8  
OLDY = RAYY(n) p\~ lPXK  
^<7)w2ns  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY OP{ d(~+  
H;%a1  
xqX~nV#TB  
%.[t(F  
$D1Pk  
1P@&xcvS\  
NEXT =D<46T=(RB  
Ay/ "2pDZ  
!繪出該點數據 OiZPL"Q(K  
{])F%Q_#cD  
JmtU>2z\  
^3F[^#"  
GRAPHICS &CG3_s<2  
esWgYAc3{  
FX4](oM  
l0 r Zril  
RAYTRACE 0, 1, 0, 0, PWAV() M n3cIGL  
[-=PK\ B  
MAX_RIH = RAYY(n) lmgMR|v  
_\1wLcFj  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 dq[j.Nmq  
z{7&=$  
X_WIDE = XMAX() /1.6 ;a*i*{\Rm  
J+kxb"#d  
Y_WIDE = YMAX() /1.6 [89#8|+  
QB7E:g&7  
SEGMENT = 40 ?yU|;my  
/|bir6Y:  
FOR j, 0, SEGMENT-1,1 >x eKO 2o  
L Lm{:T7  
)UO:J7K  
:OUNZDL  
FHY = j/SEGMENT t=d~\_Oa  
fr4#< 6,  
RAYTRACE 0, FHY, 0, 0, PWAV() EL;IrtU  
]Jq1b210  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 mTwz&N\  
-"UK NB!  
RIH = RAYY(n) g>CF|Wj  
2kp.Ljt@  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) 9N:Bu'j&/  
&gw. &/t  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) k9vr6We'  
=) $a>N  
&&\ h%-Jc  
!vHnMY~AG  
?kI-o0@O.  
6@t4pML  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() Zm >Q-7r9  
pLE|#58I  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 s7A{<>:  
ce0TQ  
RIH = RAYY(n)       MS)#S&  
h/ ?8F^C#v  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) 47ppyh6@  
rbHrG<+7zO  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) vRpMZ)e  
I3uaEv7OZc  
%M2.h;9]*\  
mnzamp  
LINE OLDX,OLDY,NEWX,NEWY Cg |_ ) _w  
lbZ,?wm  
A$ = "0"  Jx9S@L`  
Og4 X3QG  
gtext OLDX,OLDY,0, A$ 8P.t  
~}q"M[{  
NEXT dQVV0)z  
cKEf- &~  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " Qr Dzf e[  
s^TF+d?B  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" *]nha1!S  
|\TOSaZ  
({zt=}r,  
s3HwBA  
GRAPHICS OFF iA3d[%tBb  
{a.{x+!5I-  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! `<i|K*u  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 7(rTGd0  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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