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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? =*Ru 2  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ p"ElO,\  
如下: Z&[_8Y5j  
!RIH: CHIEF RAY HEIGHT ON IMA hQPNxpe  
W&HF*Aw  
!CRA: CHIEF RAY ANGLE IN IMA SPACE vpL3XYs`  
%IhUQ6  
!和取最?視角度 zd-qQ.j0  
3,[#%}1(S  
MAXFIELD = MAXF() 7,:$, bL  
.M zAkZ=  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 &m8Z3+Ea  
f' 28s*n  
!獲曲面數 SdM@7%UK  
Ir\f _>7  
n = NSUR() &|&tPD/dJ  
y)]L>o~  
!主光線錐激 K]s*rPT/,  
qr|v|Ejd~  
7ElU5I<S  
w_hN2eYo&e  
RAYTRACE  0, 1, 0, 0, PWAV() "CcdwWM  
IyJHKDFk  
##_Jz5P  
m2h@*  
MAX_RIH = RAYY(n) &8R !`uh1  
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TOC2[m c'  
^p}|""\j  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   /.>8e%)  
lw j,8  
G>>TB{}  
,UE>@;]  
PRINT   "MAX FIELD: " , maxfield, 6X`i*T$.  
r>Rm=eKJ  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , :y%CP8  
" s3eO  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH j,@@[{tu  
kD.KZV  
9Impp5`/B  
YOE!+MiO  
PRINT "FIELD ",   6L}}3b h  
S#{gCc  
PRINT "CHIEF RAY ANGLE," `j)S7KN  
Fx6]x$3  
PRINT  "CHIEF RAY HEIGFHT ON IMA." ~8l(,N0  
(]gd$BgD  
%ok??_}$}q  
x_VD9  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for eF=cMC  
uzgQ_  
s. ]<r5v7  
8DLj?M>N  
For j, 0, 20, 1 kACgP!~/1  
vA"MTncv  
FHY = j/20 _'Rzu'$`  
[3|&!:4g6  
RAYTRACE  0, FHY, 0, 0, PWAV() (RBzpAiH  
x4=Sm0Ro|V  
CRA = ACOS(RAYN(n-1))*180/3.1416 b;k3B7<  
4Fs5@@>X  
OLDX = CRA 2*)2c[/0F  
Svqj@@_f  
OLDY = RAYY(n) F)n^pT  
::`#qa4!  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY u(W+hdTap=  
cM 5V%w  
bpgvLZb>s  
uw>O|&!  
p'f8?jt  
Vl\8*!OL%  
NEXT l.nd Wv  
;vuqI5k  
!繪出該點數據 *l{GD1ZDk  
dYxX%"J  
='G-wX&k  
}N,$4h9Dj  
GRAPHICS CR8szMa  
6 @A'N(I=O  
B9(@ .  
=8V 9E  
RAYTRACE 0, 1, 0, 0, PWAV() l' mdj!{&  
 ,7h0y  
MAX_RIH = RAYY(n) }5]2tH${  
h ]6: `5-  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 D8 BmC  
u8Ak2:   
X_WIDE = XMAX() /1.6 Kg6[  
i9koh3R\  
Y_WIDE = YMAX() /1.6 N}gPf i  
 PrqyJ  
SEGMENT = 40 hZ`<ID  
H ]z83:Z  
FOR j, 0, SEGMENT-1,1 O;lGh1.  
qd<-{  
yQ!I`T>a  
s3sPj2e{  
FHY = j/SEGMENT ko{7^]gR  
A@<a')#>)  
RAYTRACE 0, FHY, 0, 0, PWAV() Bw/8-:eb  
giYlLJA*}  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 zI,z<-  
!rsGCw!Pg  
RIH = RAYY(n) _)kTlX:,  
c> 0R_  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) z5p5=KOb  
hN^,'O  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) "IN[(  
~JQ6V?fucD  
vzFo"  
p?2^JJpUb  
hQ ?zc_ 3  
4w5);x.  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() oJ?,X^~_  
\IaUsx"#o{  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 b4&l=^:e=  
9? y&/D5O  
RIH = RAYY(n)       !nU|3S[b  
ShesJj  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) [\3W_jR  
fSVb.MZa7  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) H/U.Bg 4  
gA}?X  
7 !dj&?  
A<_{7F9  
LINE OLDX,OLDY,NEWX,NEWY [vqf hpz  
=P%?{7  
A$ = "0" uJ`:@Z^J  
:s*t\09V7  
gtext OLDX,OLDY,0, A$ 3i1TBhs6  
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NEXT #/> a`Ur_  
~)pso7^:  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " Ya4yW9*  
y$+=>p|d.^  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" ,T*\9' Q  
$R%tD.d3  
I? ="Er[g}  
f0879(,i  
GRAPHICS OFF xX|f{)<  
Eh^gR`I  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! g:Q:cSg<  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 =h xyR;  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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