首页 -> 登录 -> 注册 -> 回复主题 -> 发表主题
光行天下 -> ZEMAX,OpticStudio -> 求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [点此返回论坛查看本帖完整版本] [打印本页]

uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? UTXSeNP  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ $56,$K`H  
如下: 7jdb)l\p=  
!RIH: CHIEF RAY HEIGHT ON IMA j~*L~7  
2RSt)3!},  
!CRA: CHIEF RAY ANGLE IN IMA SPACE zc[Si bT  
/Q~i~B 2j-  
!和取最?視角度 _%QhOY5tv"  
JQ"U4GVp  
MAXFIELD = MAXF() i':C)7  
&RfC"lc  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 `]%|f  
-Z's@'*  
!獲曲面數 thhwN A  
Fi0GknQ+  
n = NSUR() S\;V4@<Kn  
t<#h$}=:Vt  
!主光線錐激 -,U3fts  
N0r16# -g  
j:VbrR  
Y=Kc'x[,Zj  
RAYTRACE  0, 1, 0, 0, PWAV() ga`3 (  
/HaHH.e  
MjU6/pO}L  
1u:< 25  
MAX_RIH = RAYY(n) ]?(-[  
sfNE68I2  
.nVa[B |.  
(=om,g}  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   h 5^Z2:#  
U[ 0=L`0e  
P(f0R8BE  
\RG8{G,  
PRINT   "MAX FIELD: " , maxfield, ojan Bg   
jWrj?DV,2N  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , LA}S yt\F  
6}FP  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH ++^l]8  
}F#okU  
6 |PrX L&  
xjKR R?  
PRINT "FIELD ",   o%IA}e7PAa  
NeE t  
PRINT "CHIEF RAY ANGLE," N(Fp0  
JPoN&BTCj  
PRINT  "CHIEF RAY HEIGFHT ON IMA." <4HDZ{"M  
f}9zgWU  
zN^n]N_?  
d^{RQ   
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for aWR}R>E  
t%E!o0+8Z  
;)D];u|_  
0.8  2kl  
For j, 0, 20, 1 NTYg[VTr  
R}*_~7r5  
FHY = j/20 t.xxSU5~%  
xdp`<POn%  
RAYTRACE  0, FHY, 0, 0, PWAV() XovRg,  
iKX-myCz  
CRA = ACOS(RAYN(n-1))*180/3.1416 .\)U@L~  
9_Be0xgJ3^  
OLDX = CRA 6WXRP;!Q  
&L'Dqew,*  
OLDY = RAYY(n) U:^PC x`  
 W\d{a(*  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY onz?_SAW  
#h` V>;  
r]:(Vk]|F  
*Q ?tl\E  
;$.J3!  
X=5xh  
NEXT 9]f!'d!5  
/5(Yy}  
!繪出該點數據 I|gB@|_~  
PQ5QA61  
J&W)(Cf  
|H;F7Y_  
GRAPHICS  zv0l,-o  
_>(^tCo  
/Z'L^ L%R  
6jE |  
RAYTRACE 0, 1, 0, 0, PWAV() ,(qRc(Ho  
?XrQ53  
MAX_RIH = RAYY(n) dCi?SIN  
Dfg2`l  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 KL1/^1  
Mo?~_|}  
X_WIDE = XMAX() /1.6 TC!Yb_H}gN  
RYQ<Zr$!  
Y_WIDE = YMAX() /1.6 7K,-01-:  
:61Tun  
SEGMENT = 40 ($au:'kU  
$WyD^|~SF  
FOR j, 0, SEGMENT-1,1 U}yW<#$+  
{XR6>]  
+)!YrKuu  
S?1AFI9{   
FHY = j/SEGMENT 0^I|u t4  
~ $Tkn_w#  
RAYTRACE 0, FHY, 0, 0, PWAV() IUE~_7  
mn, =i  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 XG{{ 2f  
i UCXAWP  
RIH = RAYY(n) g7}Gip}.>  
[ey:e6,T9  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) 1"zDin!A  
^U `[(kz=  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) sGy eb5c  
G`SUxhCk  
i6dHrx]:,  
!\nBh  
D>/0v8  
H$=e -L`@  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() )Xk0VDNp$/  
qaiNz S@q  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 Rp.Sj{<2  
mg^I=kpk  
RIH = RAYY(n)       UtPLI al  
HJLu'KY }  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) +o\:d1y  
<;vbsksZeH  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) /1"(cQ%?  
En~5"yW5>]  
10)jsA  
+c(zo4nZ  
LINE OLDX,OLDY,NEWX,NEWY YLqGRE`W  
l)G^cSHF.3  
A$ = "0" AqWUwK9T  
+]*zlE\N`  
gtext OLDX,OLDY,0, A$ .<jr0,i  
OVm\  
NEXT $;1#To  
'qZW,],5  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " VPO N-{=`  
hBS.a6u1'd  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" f[@77m*  
DgUT5t1  
r[2ILe  
:}5j##N  
GRAPHICS OFF 't1 ax^-g  
8K.R=  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! Wi*.TWz3  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 (zgW%{V@  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
查看本帖完整版本: [-- 求教CHIEF RAY ANGLE在Zmax中如何可以看出来? --] [-- top --]

Copyright © 2005-2026 光行天下 蜀ICP备06003254号-1 网站统计