首页 -> 登录 -> 注册 -> 回复主题 -> 发表主题
光行天下 -> ZEMAX,OpticStudio -> 求教CHIEF RAY ANGLE在Zmax中如何可以看出来? [点此返回论坛查看本帖完整版本] [打印本页]

uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? 1b8}TG2  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ %`]fZr A]#  
如下: Wfh+D[^  
!RIH: CHIEF RAY HEIGHT ON IMA Uk4G9}I  
oC(.u?  
!CRA: CHIEF RAY ANGLE IN IMA SPACE GX%r-  
kS)|oU K  
!和取最?視角度 }Hb_8P  
j15t8du&O  
MAXFIELD = MAXF() x24&mWgU  
4JGU`L:~  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 y@dTdR2Wc  
*m`F-J6U  
!獲曲面數 =${ImMwj  
Z xR  
n = NSUR() O @{<?[  
T@Th?  
!主光線錐激 g HKA:j`c  
me@EKspX  
MDfC%2Q  
$GIup5  
RAYTRACE  0, 1, 0, 0, PWAV() #;<dtw  
X/23 /_~L`  
\7 }{\hY-  
%DhLU~VX  
MAX_RIH = RAYY(n) |JTDwmR  
BzI(  
T0K*!j}O  
It5n;,n  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   ilFS9A3P  
{EVHkQ+o  
;ZR^9%+y9  
0mI4hy  
PRINT   "MAX FIELD: " , maxfield, q ?m<9`  
cDh\$7'b  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , tD No; f  
%QX"oRMn0  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH opqf)C  
[ P%'p-Hg_  
:A`jRe.  
}Z% j=c"d  
PRINT "FIELD ",   ;`FR1KIg  
+<f!#4T  
PRINT "CHIEF RAY ANGLE," <"!'>ZUt  
\D}$foHg  
PRINT  "CHIEF RAY HEIGFHT ON IMA." Is }?:ET  
qX*Xo[Xp  
'z">4{5  
"oT]_WHqo  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for PsI{y&.  
KZwzQ"Hl  
'jBtBFzP-  
}r:8w*4 7  
For j, 0, 20, 1 ph@2[rUp  
D0 rqte  
FHY = j/20 +fG~m:E  
(eO_]<wmky  
RAYTRACE  0, FHY, 0, 0, PWAV() V-z F'KI[  
r }Nq"s<  
CRA = ACOS(RAYN(n-1))*180/3.1416 P !~B07y  
UQCond+K  
OLDX = CRA 1DM$FG_Z-  
[,q^\T  
OLDY = RAYY(n) q??N,  
<& =3g/Y  
PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY Q?-uJ1J  
P%Wl`NA P  
hV"2L4/E  
juBzpQYj  
K${CHKFf  
Vvk \ $'  
NEXT rcG-V f@  
~Ec@hz]js  
!繪出該點數據 Z n]e2  
a|@1RH>7H  
UJGmaE  
(r$QQO) /  
GRAPHICS o@:u:n+.  
uCGn9]  
g<N3 L [  
`pYL/[5  
RAYTRACE 0, 1, 0, 0, PWAV() ^HNccr  
?1lx8+  
MAX_RIH = RAYY(n) )\,hc$<=m  
r2>y !Q?  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416  Fs1ms)  
}}~ t! /x  
X_WIDE = XMAX() /1.6 R=s^bYdoy  
R,[+9U|4V  
Y_WIDE = YMAX() /1.6 wfc+E9E  
_JXb|FIp  
SEGMENT = 40 S:xG:[N@  
&?B\(?*  
FOR j, 0, SEGMENT-1,1 dG'5: ,n/  
aW#_"Y}v'  
@)m+b;  
b. oA}XP  
FHY = j/SEGMENT Cr%6c3aQ  
5}_DyoV  
RAYTRACE 0, FHY, 0, 0, PWAV() ^tFgkzXm  
qf6}\0   
CRA = ACOS(RAYN(n-1)) * 180/3.1416 ?u /i8  
6d|%8.q1  
RIH = RAYY(n) ]; G$~[  
K>fY9`Whm  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) CF+:9PG  
t"Djh^=y  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) .6#Y- iJqc  
pM'AhzS  
/-jk_8@a  
zhFk84  
Cn(0ID+3f  
W L5!H.q  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() *FEY"W+bY  
4>xv7  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 [sH[bmLR  
k!6wVJ|_Y  
RIH = RAYY(n)       )0NE_AZ?  
gAgP("  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) "Hw%@  
$N1UEvC%Q  
NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) Zf%6U[{ T  
7lz"^  
y*Wl(w3  
}];_ug* "  
LINE OLDX,OLDY,NEWX,NEWY ^~%z Plv  
3xnu SOdh  
A$ = "0" Pkw ` o #  
@7aSq-(_l*  
gtext OLDX,OLDY,0, A$ +#!! 'XP  
>HXmpu.O  
NEXT L'Fy\K\  
/N&)r wc  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " <C9_5C e~  
W!BIz&SY:-  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" m*S[oy&  
]h$,=Qf hD  
e-#!3j!'  
icPg<>TQ  
GRAPHICS OFF :9`T.V<?  
/hMD Me  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! 0FV?By  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 gqRwN p  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
查看本帖完整版本: [-- 求教CHIEF RAY ANGLE在Zmax中如何可以看出来? --] [-- top --]

Copyright © 2005-2026 光行天下 蜀ICP备06003254号-1 网站统计