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uiuo 2009-04-11 21:31

求教CHIEF RAY ANGLE在Zmax中如何可以看出来?

求教CHIEF RAY ANGLE在Zmax中如何可以看出来? `52+.*J+%  
leslie1719 2011-12-26 09:48
我這邊有一個zpl可以直看出來~ I8R#EM%C#  
如下: 9Z.Xo kg  
!RIH: CHIEF RAY HEIGHT ON IMA d <{ >&  
Wt|IKCx   
!CRA: CHIEF RAY ANGLE IN IMA SPACE cZB?_[Cp  
l`S2bb6uMR  
!和取最?視角度  n7g}u  
N`3q54_$  
MAXFIELD = MAXF() #|<\q*<  
wKxw|Fpn  
IF (MAXFIELD = = 0.0) THEN maxfield = 1.0 :w|ef;  
-|0nZ  
!獲曲面數 b`a4SfbQS  
-BQoNEh  
n = NSUR() [{iPosQWj  
/V-uo(n< .  
!主光線錐激 yx0wR  
63'Rw'g^|2  
s7(NFX5  
'q3<R%^Q   
RAYTRACE  0, 1, 0, 0, PWAV() JXFPN|  
3jSt&+  
x*H,eY3  
<{ZDD]UGs0  
MAX_RIH = RAYY(n) C K#^`w  
/!7    
b+=@;0p*6B  
N>pTl$\4  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416   v2w|?26Lf  
#:B14E  
!4.VK-a9V%  
vIq>QXb;d  
PRINT   "MAX FIELD: " , maxfield, eELLnU{"  
:.DZ~I  
PRINT   "MAX_CHIEF_RAY_ANGLE : " , MAX_CRA , p{@jM  
[ TX1\*W  
PRINT   "MAX CHIEF RAY HEIGHT ON IMA : ",MAX_RIH u[:-^H  
;$nCQ/ /  
YR'dl_  
6Qc *:(GE  
PRINT "FIELD ",   |WkWZZ^  
.ZOG,h+8  
PRINT "CHIEF RAY ANGLE," aB_~V h  
ZVX1@p  
PRINT  "CHIEF RAY HEIGFHT ON IMA." $^TxLv  
et`1#_o  
wI5(`_l{G  
'hGUsi  
!將最大試廠分為20, 設置試場數據步常  FHY=j/20 , for FhP$R}F  
$.Ia;YBf  
C.|.0^5  
} yb"/jp  
For j, 0, 20, 1 HfOaJ'+e<  
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FHY = j/20 H\%^n<]#  
~|Nj+A  
RAYTRACE  0, FHY, 0, 0, PWAV() &gLXS1O  
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CRA = ACOS(RAYN(n-1))*180/3.1416 w,T-vf  
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OLDX = CRA m$.7) 24  
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OLDY = RAYY(n) /$\N_`bM  
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PRINT FHY*maxfield, " ,  ",OLDX,"   ",OLDY N,bH@Q.Ci  
7VIfRN{5n  
u?4d<%5R!  
qV#,]mX  
YB+My~fw{l  
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NEXT H73 r3BH  
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!繪出該點數據 L9]y~[R:  
yHo#v:>?p  
*snY|hF  
F2>W{-H+  
GRAPHICS 'F%h]4|1  
HGao}@'  
>:bXw#w]  
I]z4}#+cX  
RAYTRACE 0, 1, 0, 0, PWAV() -]Ny-[P  
hRQw]  
MAX_RIH = RAYY(n) QQ/9ZI5  
[Mk:Zz%  
MAX_CRA = ACOS(RAYN(n-1))*180/3.1416 /s~BE ,su  
,`ba?O?*G  
X_WIDE = XMAX() /1.6 Ub{7Xk n  
}vb.>hy  
Y_WIDE = YMAX() /1.6 Obx!>mI^6  
)b~+\xL5J  
SEGMENT = 40 v]'\]U^  
m f\tMik<  
FOR j, 0, SEGMENT-1,1 ~#dfZa&   
SN 4JX  
Cb6K!5[q]  
!S'!oinV  
FHY = j/SEGMENT L0R$T=~%)  
)43z(:<  
RAYTRACE 0, FHY, 0, 0, PWAV() L@S1C=-/  
!<<wI'8  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 Y 8-;eqH  
6"9(ce KX  
RIH = RAYY(n) ,T-xuNYC  
IC6'>2'=T  
OLDX = X_WIDE * (CRA/MAX_CRA+2/20) (~NR."s;  
CHVAs9mrNB  
OLDY = Y_WIDE * (1-RIH/MAX_RIH+2/20) I%jlM0ZUI"  
H~?7 : K  
h05BZrE  
g^{a;=  
Ri3*au/Q  
yb-4[C:i  
RAYTRACE  0, (FHY+1/SEGMENT),  0,  0, PWAV() 5~OKKSUmT  
4,&f#=Y  
CRA = ACOS(RAYN(n-1)) * 180/3.1416 @ %o'  
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RIH = RAYY(n)       w ^ X@PpP  
n0)y|B#  
NEWX = X_WIDE * (CRA/MAX_CRA+2/20) im9Pjb%  
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NEWY = Y_WIDE * (1-RIH/MAX_RIH+2/20) L/)eNZ  
E;YD5^B  
dpT?*qLM  
"g/UpnH  
LINE OLDX,OLDY,NEWX,NEWY &{bNa:@  
!/]z-z2>  
A$ = "0" wauM|/KG  
 zj$Ve  
gtext OLDX,OLDY,0, A$ S3Fj /2Q8  
Lie= DD  
NEXT @cQ |`  
!FQS9SoO9  
gtext NEWX, NEWY, 0 " THE LAST DATA POINT " ~ymSsoD^  
9R:?vk4  
gtitle "THE CHIREF RAY ANGLE VS. REAL IMAGE HEIGHT" lI3d _cU  
sfp.>bMj  
bV:MOj^  
!>fi3#Fi  
GRAPHICS OFF 16"L;r  
r@Xh8 r;  
rcasiodu 2011-12-27 09:57
楼上的回答非常棒!谢谢分享这个宏! &-KQ m20n  
还有一个简单的方法,利用Ray Trace观察主光线的ray angle以及imaging height,参见http://www.opticsky.cn/read-htm-tid-51156.html,此贴介绍的很详细。 SJlL!<i$  
paradism 2012-07-01 12:51
学习了!!!!!!!!!!!!!!!!!!!
wanglu079 2012-07-09 13:04
用宏指令看
qq41894351 2012-07-09 22:26
什么事宏指令
oxfocean 2019-05-14 17:10
这个宏厉害了
1014597 2019-05-15 06:04
这个宏厉害了
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