| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 iph}!3f
function sjr=nfdre(~) A5?q&VS}p
"X,*VQl:
%系统焦距及各镜间距输入，间距取负正负 FW)VyVFmk
& (X 6 7
f=input('f:'); 9|NH5A"H.
d1=input('d1:'); OWT|F0.1$k
d2=input('d2:'); yZQcxg%
d3=input('d3:'); {@ Z=b 5/P
zyP9
n[e Z
A=f^2/(d3*d2)-f/d1; Fxv5kho
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 2Og<e|
C=d3/d2-f/d1; i !;9A6D
<rxtdI"3
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 )=pa *
a2=d3/(a1*f);%α2 Q)Q1a; o
b2=a1*(1-a2)*f/d2;%β2 sf"vi i,1A
b1=(1-a1)*f/(d1*b2);%β1 ; cfPS
K $I`&M(
'Y0h w
%曲率半径 6uIgyO*;k
DM,)nh6'
R1=2*f/(b1*b2) qs!A)H#
R2=2*a1*f/(b2*(1+b1)) JFFluL=-
R3=2*a1*a2*f/(1+b2) " p]!="\
spT$}F2n
A1=b2^3*(a1-1)*(1+b1)^3; V5' (op /
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; WG*),P?
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; #Q'#/\5
xVk5%
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); }0, dG4Oo=
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); i>O8q%BnJ
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 54].p7
P^AI*tH"m
CB=[C1 B1;C2 B2]; RT|1M"?$
AB=[A1 B1;A2 B2]; ;Z); k`j
AC=[A1 C1;A2 C2]; JOH\K0=e
0D Lw
%非球面系数 RM;Uq >l
k2=-(det(CB)/det(AB)); P$Q,t2$ A
k3=-(det(AC)/det(AB)); }N&? 8s=
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Z/czAr@ 4
k2=k2 G*_qqb{B
k3=k3 0S96x}]J B
sI.p(
-K Q
end d$"?8r4:K
ST2:&xH(
%有中间像，焦距输入为正数 H: S<O%f
i+F*vTM2,
function sjr=yfdre(~) JIIc4fyy8s
rp+]f\] h
f=input('f:');
T%B z >K
d1=input('d1:'); D|*yeS4>
d2=input('d2:'); HX) ]@qL
d3=input('d3:'); zhJ0to[%?
70'gVCb
A=f^2/(d3*d2)-f/d1; a@J/[$5
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); wJD'q\ n
C=d3/d2-f/d1; 3b|= V
H32o7]lT
a1=(-B-sqrt(B^2-4*A*C))/(2*A); {Kf5a
m
a2=d3/(a1*f); AOJ[/YpM
b2=a1*(1-a2)*f/d2; e{9~m
b1=(1-a1)*f/(d1*b2); G<*
Iw>ep
. 9N7`
%曲率半径 zk"8mTg
U>OAtiq JX
R1=2*f/(b1*b2) Z~<=I }@
R2=2*a1*f/(b2*(1+b1)) BeN]D
R3=2*a1*a2*f/(1+b2) }LeS3\+UHl
IJt'[&D
A1=b2^3*(a1-1)*(1+b1)^3; &_u.q/ ~
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ^Ua6.RH8
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; l4dG=x}M]
N:+)6a
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); \Z,{ De%
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); S~hu(x#
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); X&kp1Ih <^
K yyVO"
CB=[C1 B1;C2 B2]; x NjQ"'i8
AB=[A1 B1;A2 B2]; 5\=
y9Z- x
AC=[A1 C1;A2 C2]; $8 x b|S[
jJ-C\
v
%二次系数 TQmrL
C JER&"em7
k2=-(det(CB)/det(AB)); #UhH
k3=-(det(AC)/det(AB)); R :(-"GW'
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 l?
U!rFRq`
k2=k2 ".%d{z}vz
k3=k3 nJGs ,~"
El@*Fo
end
|
|