| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 PQ" Dl =,
function sjr=nfdre(~) t [ f]
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%系统焦距及各镜间距输入，间距取负正负 nM#\4Q[}Jh
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f=input('f:'); V! p;ME
d1=input('d1:'); f|!zjX`
d2=input('d2:'); #\qES7We 6
d3=input('d3:'); ,b{4 GU$3
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A=f^2/(d3*d2)-f/d1; c)?y3LX
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); V.qB3 V$
C=d3/d2-f/d1; $|KbjpQ
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a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 3~ylBJJ
a2=d3/(a1*f);%α2 hz!.|U@,{<
b2=a1*(1-a2)*f/d2;%β2 Y yf8B
b1=(1-a1)*f/(d1*b2);%β1 G 9;WO *
= >9`qcNW_
idHBz*3~ps
%曲率半径 On ao'sjY
yd $y\pN=<
R1=2*f/(b1*b2) pnWDsC ~)
R2=2*a1*f/(b2*(1+b1)) pV_2JXM~@
R3=2*a1*a2*f/(1+b2) d}1R<Q;F
;-59#S&?tB
A1=b2^3*(a1-1)*(1+b1)^3; bLg1D d7Q
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; x(A .^Yz
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; k#
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A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); EG,RlmcPp
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ]`%cTdpLj
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 9kcAMk1K
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CB=[C1 B1;C2 B2]; :EZTJu
AB=[A1 B1;A2 B2]; rc"yEI-``"
AC=[A1 C1;A2 C2]; 5bk5EE`
:%R3(
&
%非球面系数 |# k1a:
k2=-(det(CB)/det(AB)); |,o!O39}>
k3=-(det(AC)/det(AB)); Y:O%xtGi
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 V }&
k2=k2 3vx?x39*Y
k3=k3 }JS?42CTaV
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end n<MH\.!tM
C Z|R-ky6p
%有中间像，焦距输入为正数 p\Jz<dkN1
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function sjr=yfdre(~) S>nM&75 8
LbnR=B!
f=input('f:'); IL\#!|>
d1=input('d1:'); WSL_Dc
d2=input('d2:'); E}UlQq
d3=input('d3:'); {{j?3O //
?_IRO|
A=f^2/(d3*d2)-f/d1; 1N2s[ \q$
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 7^=O ^ !sa
C=d3/d2-f/d1; 6#v"+V
YoJN.] ,gf
a1=(-B-sqrt(B^2-4*A*C))/(2*A); &q>=6sQvf
a2=d3/(a1*f); BDpeAF8z
b2=a1*(1-a2)*f/d2; V1M oW;&
b1=(1-a1)*f/(d1*b2); |d K_^~;o
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hvO
%曲率半径 n>{ >3?
+v/_R{ M
R1=2*f/(b1*b2) ]oj
2
R2=2*a1*f/(b2*(1+b1)) {2A/ @$?
R3=2*a1*a2*f/(1+b2) 7i`8 c =.
d x?4)lb
A1=b2^3*(a1-1)*(1+b1)^3; \f .ceh;!
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ZdfIe~Oni
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; #7GbG\
~ ]3y66 7
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); p \1-.
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); .>_p7= a
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); r!'\$(m E
x pT85D
CB=[C1 B1;C2 B2]; $3k5hDA0e
AB=[A1 B1;A2 B2]; mJp)nF8r~
AC=[A1 C1;A2 C2]; &^9 2z:?
4gzr xV
%二次系数 Y;G+jC8
Vv#|% ^0
k2=-(det(CB)/det(AB)); ND77(I$3s
k3=-(det(AC)/det(AB)); \:, dWL u
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1
G<U MZg
k2=k2 A46Xei:Ow
k3=k3 jw]~g+x#$
>d%;+2
end
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