songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下,基于matlab的消四种像差的三反系统初始结构的求解
%无中间像,焦距输入为负数 .$@+ /@4 function sjr=nfdre(~) v7n@CWnN 2RQ-L %系统焦距及各镜间距输入,间距取负正负 PMUW<UI P ^ 4 @ f=input('f:'); Z?xRSi2~7 d1=input('d1:'); 0` .5gxm d2=input('d2:'); $,yAOaa d3=input('d3:'); AmC?qoEWQ7 sn"z'=ch A=f^2/(d3*d2)-f/d1; f7y.##W G B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); K`2(Q C=d3/d2-f/d1; FgL892[ =r*Ykd;W|E a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 <z\ `Ma a2=d3/(a1*f);%α2 Nte$cTjX b2=a1*(1-a2)*f/d2;%β2 :AS`1\ C b1=(1-a1)*f/(d1*b2);%β1 n}I?.r@e aCI3Tx&2qT {`Gd %曲率半径 =J4|"z: 0EF~Ouef R1=2*f/(b1*b2) >
K?OsvX R2=2*a1*f/(b2*(1+b1)) 8xg^="OJ R3=2*a1*a2*f/(1+b2) vFB^h1k~.M 9!
/kyyU A1=b2^3*(a1-1)*(1+b1)^3; M(zZ8# B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 9h?'zyX
B C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; #-@uLc eIfQ
TV A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ;0Pv49q B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); !nCq8~# C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); -sfv"? U(9_&sL CB=[C1 B1;C2 B2]; P6R_W AB=[A1 B1;A2 B2]; ,|B-Nq AC=[A1 C1;A2 C2]; S
YDE`- c~?Zmdn: %非球面系数 q;") k2=-(det(CB)/det(AB)); (Xcy/QT k3=-(det(AC)/det(AB)); &'x~<rx k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 kJp~'\b k2=k2 l6&\~Z( k3=k3 c%J6!\ ?UZt30|1 end \1Xk[% !~Uj 'w %有中间像,焦距输入为正数 M{Z
;7n' _BmObXOp. function sjr=yfdre(~) lU%}_!tp3/ pX
^^0 f=input('f:'); 6e B; d1=input('d1:'); `om+p?j d2=input('d2:'); C=/B\G/.9 d3=input('d3:'); XS [L-NHG P}Kgh7)3 A=f^2/(d3*d2)-f/d1; Zn'tNt/ B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); sfj+-se(K. C=d3/d2-f/d1; odsFgh :Ko6.| a1=(-B-sqrt(B^2-4*A*C))/(2*A); "(^XZAU#W a2=d3/(a1*f); "|L"C+tE b2=a1*(1-a2)*f/d2; A913*O:\ b1=(1-a1)*f/(d1*b2); ^,acU\}VqP &(rWl`eTY` %曲率半径 ^ RA'E@" b.&WW R1=2*f/(b1*b2) l9I r@.m R2=2*a1*f/(b2*(1+b1)) 6!ve6ZB[p R3=2*a1*a2*f/(1+b2) pn
gto /Hyz]46 A1=b2^3*(a1-1)*(1+b1)^3; Sw\*$g] B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; {`QHg O C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; K>@yk9)vi \ ;npdFy A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); //U1mDFT B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); aa`(2%(: C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); " B#|C' hfaU-IPcFX CB=[C1 B1;C2 B2]; hj [77EEz AB=[A1 B1;A2 B2]; 6lSz/V; AC=[A1 C1;A2 C2]; wZiUzS;v ;Y$>WKsV %二次系数 xc:E>- O?JJE8~'] k2=-(det(CB)/det(AB)); ,50 k3=-(det(AC)/det(AB)); $*fJKR_N k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 _rT\?//B k2=k2 ~&i4 | |