| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 5eF tcK
function sjr=nfdre(~) =HIKn6C<
\Wppl,"6c
%系统焦距及各镜间距输入，间距取负正负 G)b:UJa"
hv>Xr=RE
f=input('f:'); g[@0H=
d1=input('d1:'); UA6
C/
d2=input('d2:'); A0;{$/
d3=input('d3:'); &dj/Dq@
+jq@!P"}d
A=f^2/(d3*d2)-f/d1; Xa ;wx3]t
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 'Pn:10;
C=d3/d2-f/d1; 0;=]MEk?
YKayaI\*
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 (;9fkqm%m
a2=d3/(a1*f);%α2 $I#~<bW,
b2=a1*(1-a2)*f/d2;%β2 32anmVnf
b1=(1-a1)*f/(d1*b2);%β1 4 $ N,|bt
=F/ R*5:T
F2Ny=H &G
%曲率半径 '|v<^EH
s -x1<+E(
R1=2*f/(b1*b2) glM42s
R2=2*a1*f/(b2*(1+b1)) r]QeP{
R3=2*a1*a2*f/(1+b2) +
>:}
i88`W&tI{
A1=b2^3*(a1-1)*(1+b1)^3; YbWz!.WPe
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ~mah.8G
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; %'=TYvB 2
F2 <Q~g Q;
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 5RO6YxQ
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); .9g :- hv
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); .Q@]+&`|}i
&pz`gna
CB=[C1 B1;C2 B2]; 7OXRR)]V
AB=[A1 B1;A2 B2]; \ E5kpm
AC=[A1 C1;A2 C2]; {LqYb:/C5U
4 PU@W o
%非球面系数 i^IL o,Q
k2=-(det(CB)/det(AB)); oHS Di
k3=-(det(AC)/det(AB)); P&Xy6@%[Z
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 !rqs!-cCQ
k2=k2 R&P^rrC@B5
k3=k3 9M|#X1r{%{
3y:),;|5
end ]eFNR1<OP
*(i %\
%有中间像，焦距输入为正数 KqaEHL
qf [J-"o
function sjr=yfdre(~) 4{6,Sx
q
%t q9%
f=input('f:'); {ynI]Wj`L
d1=input('d1:'); $m f6!p4
d2=input('d2:'); Dp^=% F{t
d3=input('d3:'); Y1qbu~!
O0pXHXSAL
A=f^2/(d3*d2)-f/d1; Z%3)w.
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ,~l4-x.,
C=d3/d2-f/d1; 2AxKB+c1`
NW21{}=4
a1=(-B-sqrt(B^2-4*A*C))/(2*A); C^U>{jf !
a2=d3/(a1*f); (0? FZ. 9%
b2=a1*(1-a2)*f/d2; dOg c%(kz
b1=(1-a1)*f/(d1*b2); wb]Z4/j#
qCm%};yt
%曲率半径 '=K~M
%5Elj<eHZ
R1=2*f/(b1*b2) $Nj'_G\}
R2=2*a1*f/(b2*(1+b1)) =1O;,8`
R3=2*a1*a2*f/(1+b2) +tYs kx/
Di$++T 8"
A1=b2^3*(a1-1)*(1+b1)^3; ('=Q[ua7-(
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; QNj6ETB-d
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; ukD:4s v
y,<\d/YY@
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); \C1`F [d_
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 8D^ iQ BA
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); b|@f!lA
v}^uN+a5
CB=[C1 B1;C2 B2]; UM+g8J{$*;
AB=[A1 B1;A2 B2]; 10_@'N
AC=[A1 C1;A2 C2];
/zir$
`n e9&+
%二次系数 %IUTi6P
l
GN|xd+O_
k2=-(det(CB)/det(AB)); }.<] A
k3=-(det(AC)/det(AB)); h>|IA@;|f
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ;,B $lgF
k2=k2 vFgnb WxG
k3=k3 dJ{'b '#
U
owbk:
end
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