| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 k sOc,4A
function sjr=nfdre(~) cIa`pU,6A
TTbJ9O<43
%系统焦距及各镜间距输入，间距取负正负 |T/s>OW
{K}Dpy
f=input('f:'); >j*0fb!:]
d1=input('d1:'); g{uiY|
d2=input('d2:'); L/,g D.h^
d3=input('d3:'); %_CL/H
qFLt/
>
A=f^2/(d3*d2)-f/d1; nh80"Ny5
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); -N5h` Ii7
C=d3/d2-f/d1; )8'v@8;-
o?~27
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 9}Za_ZgG
a2=d3/(a1*f);%α2 .j"heYF)
b2=a1*(1-a2)*f/d2;%β2 >Q ^ mR
b1=(1-a1)*f/(d1*b2);%β1 Z_<NUPE
!0 |&f>y
?I:_FT
%曲率半径 . 6y*Z+Zg
w ZbT*rU
R1=2*f/(b1*b2) g\?07@Zd|
R2=2*a1*f/(b2*(1+b1)) bY*_6SPK4
R3=2*a1*a2*f/(1+b2) yx6^ mis4
;-l^X%r
A1=b2^3*(a1-1)*(1+b1)^3; |2 =w":2#
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 4 >H0a
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; .y_ ~mr&d
TDy)A2Z
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); w40*vBz
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 8 wZ
$Hq
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); H@ty'z ?
RdL5V AD
CB=[C1 B1;C2 B2]; nw_|W)JVQ
AB=[A1 B1;A2 B2]; _ Qek|>
AC=[A1 C1;A2 C2]; N1'Yo:_A
]W%rhppC
%非球面系数 !U(KQ :j
k2=-(det(CB)/det(AB)); v&%W*M0q@
k3=-(det(AC)/det(AB)); s >WqVuXmn
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 b NtO qhi
k2=k2 d{(Rs.GuP
k3=k3 1DL+=-
jGJf[:M&Pm
end ^L
Xr4
R`@7f$;wG
%有中间像，焦距输入为正数 jv1p'qs4
?duw0SZ
function sjr=yfdre(~) aO9\8\^
A e2Y\ sAV
f=input('f:'); [xDIK8d:I
d1=input('d1:'); up J y,|5
d2=input('d2:'); ;i+(Q%LO
d3=input('d3:');
:J )^gc
t*6C?zEAU
A=f^2/(d3*d2)-f/d1; >s,*=a
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); VeQ [A?pER
C=d3/d2-f/d1; {4p7r7n'
36.mf_AM
a1=(-B-sqrt(B^2-4*A*C))/(2*A); $[J\sokpY
a2=d3/(a1*f); 3=UufI
b2=a1*(1-a2)*f/d2; ! }1l8Y
b1=(1-a1)*f/(d1*b2); /8hjs{(;
gq~`!tW'
%曲率半径 ,pkzNe` F
&qa16bz
R1=2*f/(b1*b2) wjOqCF"
R2=2*a1*f/(b2*(1+b1)) 6+PP(>em
R3=2*a1*a2*f/(1+b2) /\1Q
:B 3W
soKR*gJ,
A1=b2^3*(a1-1)*(1+b1)^3; =Q|s[F
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; .Dr7YquW
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 6Hd^qouid
8-K4*(-dL
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); +,D82V7S
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); U[#q"'P|l
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); aIWpgUd`
l?;ReK.r
CB=[C1 B1;C2 B2]; :n
x;~f
AB=[A1 B1;A2 B2]; nXxnyom,
AC=[A1 C1;A2 C2]; U2JxzHXZ
_tO2PI L@Z
%二次系数 n4ti{-^4|d
W}wd?WIps
k2=-(det(CB)/det(AB)); qEkhgJqk
k3=-(det(AC)/det(AB)); ]7h;MR
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 P|aSbsk:I<
k2=k2 0XL[4[LdA
k3=k3 mj y+_
z_z '3d.r7
end
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