| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 "574%\#4z
function sjr=nfdre(~) b")O#v.
jM-7
%系统焦距及各镜间距输入，间距取负正负 DU SQh+C
"Lyb4# M
f=input('f:'); Kum" }ux
d1=input('d1:'); 4B9D
d2=input('d2:'); i[4!% FxB
d3=input('d3:'); 7~r_nP_
HzL~B#
A=f^2/(d3*d2)-f/d1; u+y3 ( 0
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); s",G
w]8
C=d3/d2-f/d1; nq,:UYNJ
T_q M@/ f
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 ?\I@w4
a2=d3/(a1*f);%α2 XqU0AbQ
b2=a1*(1-a2)*f/d2;%β2 DR
@yd,
b1=(1-a1)*f/(d1*b2);%β1 HWIn.ij
gu VuO
1Vkb}A,'
%曲率半径 )gz]F_
>(_2'c*[w
R1=2*f/(b1*b2) qu.AJ*
R2=2*a1*f/(b2*(1+b1)) G5|'uKz2"
R3=2*a1*a2*f/(1+b2) 1h|qxYO
<I*N=;7
A1=b2^3*(a1-1)*(1+b1)^3; Q8A+\LR~)
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; *ZV3]ig2$
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; Lxn -M5RPQ
@#*{*
S8
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); PdEPDyFk h
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); -aLM*nIoe
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); W0;QufV
v-8{ mK`9\
CB=[C1 B1;C2 B2]; S?zP;
iFj
AB=[A1 B1;A2 B2]; !acuOBv,
AC=[A1 C1;A2 C2]; ~Y{]yBGoF
[?=DPE%
%非球面系数 G O"E>FyB
k2=-(det(CB)/det(AB)); elR1NhB|p
k3=-(det(AC)/det(AB)); ?&!!(dWFH
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 QkWEVL@uM
k2=k2 -tx%#(?wH
k3=k3
'SXLnoeTa
oGyoU#z#
end N
A _8<B^
2"k|IHs1
%有中间像，焦距输入为正数 RameaFX8
O2"@ 09:
function sjr=yfdre(~) i!fk'Yt%
\),zDO+
f=input('f:'); :?}> Q
d1=input('d1:'); SmRFxq tN
d2=input('d2:'); t|9vb
d3=input('d3:'); v9!] /]U^
ks69Z|D
A=f^2/(d3*d2)-f/d1; Y]
UoV_
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); < WbO&;%
C=d3/d2-f/d1; `Ba?4_>k
0C3Y =F
a1=(-B-sqrt(B^2-4*A*C))/(2*A); >p#_ L^oZ%
a2=d3/(a1*f); "r8N-
h/P
b2=a1*(1-a2)*f/d2; asE.!g?
b1=(1-a1)*f/(d1*b2); f
=A#:d
&_s^ C?x
%曲率半径 AFeFH.G6Jr
.g7\+aiTUd
R1=2*f/(b1*b2) nEP3B '+
R2=2*a1*f/(b2*(1+b1)) :o87<)
_F
R3=2*a1*a2*f/(1+b2) tkff\W[JU
k py) kS
A1=b2^3*(a1-1)*(1+b1)^3; <[T{q
|*
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Ef@)y&hn
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; &LG|YvMY6
t\P SB
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 1(_[awBx
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); DwK$c^2q{.
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); {9) HB:
Q'hs,t1<
CB=[C1 B1;C2 B2]; sO!m,pK(
AB=[A1 B1;A2 B2]; * bhb=~
AC=[A1 C1;A2 C2]; (dy: d^
7VdxQ T
%二次系数 bYX.4(R
}[PC
YnS
k2=-(det(CB)/det(AB)); A ;6ew4
k3=-(det(AC)/det(AB)); C1qlB8(Wh>
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 @k# xr
k2=k2 gKmF#Z"\
k3=k3 U-$nwji
\/nSRAk
end
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