| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 -M 4VC^_
function sjr=nfdre(~) kUr/*an
/"^XrVi-
%系统焦距及各镜间距输入，间距取负正负 8A u W>7_
\XfLTv
f=input('f:'); ^ ),;`YXZ
d1=input('d1:'); h8;H<Y;yQ
d2=input('d2:'); R 0G!5>1i
d3=input('d3:'); }1Q> A 5e
ofs Lx6Po
A=f^2/(d3*d2)-f/d1; xqauSW
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); n;~'W*Ln0
C=d3/d2-f/d1; K~fWZT3]
-U\s.FI.AR
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 OM`Ws5W}f
a2=d3/(a1*f);%α2 5v sn'=yN
b2=a1*(1-a2)*f/d2;%β2 BL-7r=Z
b1=(1-a1)*f/(d1*b2);%β1 #RKd >ig%
Z|A+\#'
+
+Eu.W;&#
%曲率半径 Ri*mu*r\}
vYq"W%
R1=2*f/(b1*b2) Or55_E
R2=2*a1*f/(b2*(1+b1)) [ fs.D /
R3=2*a1*a2*f/(1+b2) Fc|N6I'o
:4LWm<P
A1=b2^3*(a1-1)*(1+b1)^3; N(O* "1b
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ]?NiY:v
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; G-#rWZ&
f>m ! } F:
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); u)%/df qzZ
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); f=Oj01Ut*
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 8?w#=@ s
`trcYmR=k
CB=[C1 B1;C2 B2]; HHOqJb{8S
AB=[A1 B1;A2 B2]; t"5ZYa
AC=[A1 C1;A2 C2]; @ *5+ZAF
( -@I'CFd
%非球面系数 UlPGB2B
k2=-(det(CB)/det(AB)); h dqr~9
k3=-(det(AC)/det(AB)); F'@ 9kdp
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 S8C} C#
k2=k2 urQ<r{$x0
k3=k3 vtc%MG1
7dOpJjv?)
end CX ;
m8
*z dUCX
%有中间像，焦距输入为正数 =p dLh
y!|4]/G]?t
function sjr=yfdre(~) a|k*A&5u2
*T.V5FB0S
f=input('f:'); di<g" 8
d1=input('d1:'); T iJ \J{
d2=input('d2:'); % UG|R:
d3=input('d3:'); []?*}o5&>T
_*xY>?Aq
A=f^2/(d3*d2)-f/d1; n>)h9q S
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ^Of\l:q*
C=d3/d2-f/d1; ?Iag-g9#=m
pezfB{x?
a1=(-B-sqrt(B^2-4*A*C))/(2*A); 7324#Hw S
a2=d3/(a1*f); Vw`%|x"Xz
b2=a1*(1-a2)*f/d2; \vuWypo
b1=(1-a1)*f/(d1*b2); Gc;-zq
%2^V.`0T
%曲率半径 6H0aHCM
Z}3;Ych
R1=2*f/(b1*b2) iaQFVR Ou
R2=2*a1*f/(b2*(1+b1)) N5tFEV'G
R3=2*a1*a2*f/(1+b2) :]LW,Eql
51ILR9 Bc_
A1=b2^3*(a1-1)*(1+b1)^3; JtF)jRB0,
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; g<:TsP'|
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; cVSns\QO
xX8 c> p
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ppeF, Q
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 7}(YCZny5
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); @scSW 5+
6}*4co
CB=[C1 B1;C2 B2]; @}' ?o_/C
AB=[A1 B1;A2 B2]; 8A 'SMJi
AC=[A1 C1;A2 C2]; U? Vik
r' @7aT&_
%二次系数 SXV2Y-
r/QI-Cf&
k2=-(det(CB)/det(AB)); _J,*0~O$
k3=-(det(AC)/det(AB)); ?}C8_I|4~
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 f3<253 1/}
k2=k2 DP!8c
k3=k3 BM87f:d
Z'd]oNF
end
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