| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 k#eH
Q!
function sjr=nfdre(~) _&(\>{p m
o#"U8 N%r
%系统焦距及各镜间距输入，间距取负正负 3,ihVVr&P
/ //
f=input('f:'); R07] {
d1=input('d1:'); (p 19"p
d2=input('d2:'); pUc N-WA
d3=input('d3:'); Lud[.>i
U L{+mp
A=f^2/(d3*d2)-f/d1;
6tx5{Xl-o
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); lu_kir~
C=d3/d2-f/d1; OC?a[^hB^)
+9^V9]{Vo
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 .uh>S!X, ]
a2=d3/(a1*f);%α2 fL^$G;_?3
b2=a1*(1-a2)*f/d2;%β2 iXo Edt)
b1=(1-a1)*f/(d1*b2);%β1 /)%$ xi
O/XG}G.x|
(vR9vOpJ
%曲率半径 AvmI<U
dd+hX$,
R1=2*f/(b1*b2) lf JvN
R2=2*a1*f/(b2*(1+b1)) aru;yR
R3=2*a1*a2*f/(1+b2) &i(\g7%U
?\Bm>p% +
A1=b2^3*(a1-1)*(1+b1)^3; #QUQC2P(~
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; u=6LPwiI
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; D` Cy]j
7 @W}>gnf
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); B*OEG* t
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); {4F= ].!
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); Ad}Nc"O
gLDO|ADni
CB=[C1 B1;C2 B2]; q`Rc \aWB%
AB=[A1 B1;A2 B2]; 5c Uz^ >
AC=[A1 C1;A2 C2]; '?Jz8iu-
|e QwI&
%非球面系数 `i `F$ ;
k2=-(det(CB)/det(AB));
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k3=-(det(AC)/det(AB)); 'bQjJRq!
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 !g .?+~@
k2=k2 B>; `$-
k3=k3 5!s7`w]8*0
g1H$wU3eu
end ;f!}vo<;
,q K'!
%有中间像，焦距输入为正数 p!o?2Lbiw
)MWbZA I
function sjr=yfdre(~) @oNYMQ@)d
_x` oab0@
f=input('f:'); tqFE>ojlI
d1=input('d1:'); _' mK=`>u
d2=input('d2:'); b Y2:g )
d3=input('d3:'); 4=nh'
U38
9
df GV!Z
A=f^2/(d3*d2)-f/d1; oHPh2b0
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); D[
v2#2
C=d3/d2-f/d1; PL |ea~/
iw{rns
a1=(-B-sqrt(B^2-4*A*C))/(2*A); yog(
a2=d3/(a1*f); 6n?0MMtR
b2=a1*(1-a2)*f/d2; ["H2H rI2
b1=(1-a1)*f/(d1*b2); 3P *[ !KI
c }7gHu d
%曲率半径 wBlo2WY
+C36OcmT~
R1=2*f/(b1*b2) 0 K(&Ep VE
R2=2*a1*f/(b2*(1+b1)) adtgNw g
R3=2*a1*a2*f/(1+b2) [gIvB<Uv
XY, !vLjL
A1=b2^3*(a1-1)*(1+b1)^3; 7P bwCRg
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; (:>Sh0.
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; Rd;^ fBx
gl~9|$ivj>
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); E h+m|A
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); @:/H)F^x
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); ++!'6! l
y Iu_DFq%
CB=[C1 B1;C2 B2]; em9nuXG
AB=[A1 B1;A2 B2]; FL[,?RU ?2
AC=[A1 C1;A2 C2]; -`CE ;
nC}Y+_wo0
%二次系数 ?$6(@>`f&t
%$ &_!
k2=-(det(CB)/det(AB)); ROJ=ZYof
k3=-(det(AC)/det(AB)); /^9=2~b
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 >ra)4huZ
k2=k2 HP,{/ $i:
k3=k3 wz{&0-md*'
{#,?K
end
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