| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 D+tn<\LF
function sjr=nfdre(~) 7 yK
>
vI4St;
%系统焦距及各镜间距输入，间距取负正负 vtmvvv
H 13|bM<
f=input('f:'); !RV}dhI
d1=input('d1:'); A >Js`s
d2=input('d2:'); 7tJPjp4l
d3=input('d3:'); F9N)UW:w
d+$a5 [^9
A=f^2/(d3*d2)-f/d1; k \|Hd"T
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 7cH[}v`pn
C=d3/d2-f/d1; xI$B",?(
.Gw;] s3
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 !ce:S!P
a2=d3/(a1*f);%α2 n>{ >3?
b2=a1*(1-a2)*f/d2;%β2 +v/_R{ M
b1=(1-a1)*f/(d1*b2);%β1 ]oj
2
{2A/ @$?
U\P ;,o
%曲率半径 p3&w/K{L6w
i!9yN: m0
R1=2*f/(b1*b2) L "9,K8
R2=2*a1*f/(b2*(1+b1)) !>+YEZ"
R3=2*a1*a2*f/(1+b2) Ry8@U9B6,t
GHfsq|*j,Z
A1=b2^3*(a1-1)*(1+b1)^3; b+,u_$@B
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 1jpcoJ@s
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; mJp)nF8r~
&^9 2z:?
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 1d,;e:=j
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); \^ i /:
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); wS9EC}s:Q
B[}#m'Lv
CB=[C1 B1;C2 B2]; C[z5&
x2
AB=[A1 B1;A2 B2]; q,A; d^g
AC=[A1 C1;A2 C2]; w|7<y8#qC
n]jZ2{g+
%非球面系数 k%Jv%m}aB
k2=-(det(CB)/det(AB)); *H8(G% a!^
k3=-(det(AC)/det(AB)); ^^1rj h1I
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 _gxI=EYi
k2=k2 sE{A~{a`
k3=k3 bd_&=VLTC
kO>F , M
end S jgjGJw
M:YtW5{
%有中间像，焦距输入为正数 0rP`BK|
W{B)c?G]
function sjr=yfdre(~) &==X.2XW
}&M$
f=input('f:');
74i
d1=input('d1:'); Y%m^V?k
d2=input('d2:'); b= ( ?\
d3=input('d3:'); ~\<aj(m(|
VPBlU
A=f^2/(d3*d2)-f/d1; 9x$Kb7'F
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 8K$q6V %#
C=d3/d2-f/d1; _\uyS',
v0v%+F#>@
a1=(-B-sqrt(B^2-4*A*C))/(2*A); SkU'JM7<95
a2=d3/(a1*f); m_
>+$uL
b2=a1*(1-a2)*f/d2; ]rU$0)VN
b1=(1-a1)*f/(d1*b2);
_8]hn[
='"DUQH|*
%曲率半径 rXgU*3 RG
& iYy
R1=2*f/(b1*b2) VjsQy>5m
R2=2*a1*f/(b2*(1+b1)) ^F J .C|l(
R3=2*a1*a2*f/(1+b2) |:Q`9;
ZxW4 i
A1=b2^3*(a1-1)*(1+b1)^3; `0'Bg2'
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; bLSXQStB
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; A"ApWJ 3
w alQo^<
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 1HPYW7jk@"
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ] / w: 5o#
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); b8o }bm{s
kIR?r0_<G6
CB=[C1 B1;C2 B2]; 1VRe xp
AB=[A1 B1;A2 B2]; c0 }* $e
AC=[A1 C1;A2 C2]; ,-({ m'
<B"M} Y>_P
%二次系数 TX/Ng+v S
gN./ u
k2=-(det(CB)/det(AB)); ^6c=[N$aW
k3=-(det(AC)/det(AB)); V) Oj6nD]
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 GB MCw
k2=k2 `*Ar6
k3=k3 4Og&w]
'Ll,HgU;
end
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