| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 Yr|4Fl~U
function sjr=nfdre(~) d"Y{UE
t`QENXA}
%系统焦距及各镜间距输入，间距取负正负 cc3 4e
i@'dH3-kO
f=input('f:'); K,UMqAmk
d1=input('d1:'); { xB3S_,8
d2=input('d2:'); : E?V.
d3=input('d3:'); g\A Y|;T
BJ0?kX@
A=f^2/(d3*d2)-f/d1; B7%U_F|m
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); XX~,>Q}H=
C=d3/d2-f/d1; IGN1gs
-F>jIgeC2v
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 E\$W_Lmr
a2=d3/(a1*f);%α2 c[e}w+ uB
b2=a1*(1-a2)*f/d2;%β2 w*Ihk)
b1=(1-a1)*f/(d1*b2);%β1 .|=\z9_7S8
xezcAwW
et+0FF
,
%曲率半径 Y^]rMK/;
h7@6T+#WoT
R1=2*f/(b1*b2) ]%(2hY~i
R2=2*a1*f/(b2*(1+b1)) E)3N xmM#
R3=2*a1*a2*f/(1+b2) i?;Kq~,
d!{r v
A1=b2^3*(a1-1)*(1+b1)^3; L=h'Qgk%
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ET >](l9
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; BORA(,
G / 5%.Bf@
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); YoE3<[KD(
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); M: V_/@W.
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); t >sE x:
Ct|A:/z(
CB=[C1 B1;C2 B2]; $]8Q(/mbK
AB=[A1 B1;A2 B2]; ?hM64jI|
AC=[A1 C1;A2 C2]; s(8W_4&'
:i7;w%B
%非球面系数 XZwK6F)L
k2=-(det(CB)/det(AB)); }&3 ~|kP~O
k3=-(det(AC)/det(AB)); yppo6 HGD
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 c:g'.'/*
k2=k2 u-C)v*# L
k3=k3 xwty<?dRW1
4`R(?
end -{+}@?
M@ZI\
%有中间像，焦距输入为正数 X 8`Sf>
Lh<).<S
function sjr=yfdre(~) u wBi W
yOKI*.}
f=input('f:'); ~v"L!=~G;a
d1=input('d1:'); C8 \^#5
d2=input('d2:'); bJ;'`sw1
d3=input('d3:'); {zFMmPid
MJrR[h]
A=f^2/(d3*d2)-f/d1; Tac$L S\Q
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); <^uBoKB/f
C=d3/d2-f/d1; k$7Jj-+~
f
V( J|
a1=(-B-sqrt(B^2-4*A*C))/(2*A); t()c=8qF|u
a2=d3/(a1*f); 4'Zp-k?5`
b2=a1*(1-a2)*f/d2; #5j\C+P}|
b1=(1-a1)*f/(d1*b2); 188*XCtjQ9
Xs ?o{]Fe
%曲率半径 u~-8d;+?y
E+J qWR5
R1=2*f/(b1*b2) 9&ids!W~yx
R2=2*a1*f/(b2*(1+b1)) 1!gbTeVlY
R3=2*a1*a2*f/(1+b2) <"|, "hA
IaXeRq?<
A1=b2^3*(a1-1)*(1+b1)^3; })?GzblI&
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 8&aq/4:q0
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; {.\TtE
eGH aY4|
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); O8.5}>gDn.
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); *D3/@S$B
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); bY0|N[ g
ZQ0F$J)2~
CB=[C1 B1;C2 B2]; @|%2f@h
AB=[A1 B1;A2 B2]; D5HZ2cz|a
AC=[A1 C1;A2 C2]; 8ITd Sg
(J!+(H 8
%二次系数 uR r o?m<
Ue~CwFOc
k2=-(det(CB)/det(AB)); ?oHpFlj
k3=-(det(AC)/det(AB)); <3C*Z"aQ>|
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 hNmJ!Uo
k2=k2 Y\?"WGL)p
k3=k3 v<(
<;Zmjeb+#
end
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