| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 AVVL]9b_2
function sjr=nfdre(~) DE|r~TQ
Qml e0ae
%系统焦距及各镜间距输入，间距取负正负 ^29w @*
i# $9>X
f=input('f:'); :#0uy1h
d1=input('d1:'); FL% GW:
d2=input('d2:'); ;v'7l>w3\w
d3=input('d3:'); Y^m 2ealC
?P@fV 'Jo
A=f^2/(d3*d2)-f/d1; N(>a-a
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); XIh2Y\33ys
C=d3/d2-f/d1; U^vQr%ha
`fh^[Q|4n0
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 J2Y-D'*s
a2=d3/(a1*f);%α2 @%&;V(
b2=a1*(1-a2)*f/d2;%β2 KY
H*5
b1=(1-a1)*f/(d1*b2);%β1 I"Y d6M%
;
}uo5rB5D
#P *%FgROl
%曲率半径 *@ o@>
Mm`jk%:%]
R1=2*f/(b1*b2) /:v+:-lU
R2=2*a1*f/(b2*(1+b1)) GY<ErS)2
R3=2*a1*a2*f/(1+b2) < J-bDcp
`bu3S }m7
A1=b2^3*(a1-1)*(1+b1)^3; _6" vPN
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; =BQM(mal
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; rB;` &)-
@3KVYv,q
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); 'ah|cMRn
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 0fA42*s;
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 5,`U3n a,
wVkms
CB=[C1 B1;C2 B2]; %41dVnWB^4
AB=[A1 B1;A2 B2]; 5w"f.d'
AC=[A1 C1;A2 C2]; "6_#APoP
I2kqA5>)j
%非球面系数 m 7 6**X
k2=-(det(CB)/det(AB)); j b1OcI%
k3=-(det(AC)/det(AB)); bc L>S$B
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 &;L4Cj$ q
k2=k2 loN!&YceW
k3=k3 ='u'/g$'&
9+@"DuYc6
end c_clpMx=
QwXM<qG*
%有中间像，焦距输入为正数 xb\(>7M6Y
o_&.R
function sjr=yfdre(~) 7 iu?Q
u /!U/|
f=input('f:'); h h}%Z=
d1=input('d1:'); hj64ES#x
d2=input('d2:'); VaC#9Tp2X
d3=input('d3:'); Zi M#g1;
uA=6 HpDB
A=f^2/(d3*d2)-f/d1; nV 38Mj2U
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Pd!;z=I
C=d3/d2-f/d1; UXD?gK1
1<A+.W
a1=(-B-sqrt(B^2-4*A*C))/(2*A); t+}@J}b
a2=d3/(a1*f); (y|{^@
b2=a1*(1-a2)*f/d2; cd{3JGg B
b1=(1-a1)*f/(d1*b2); 5~k-c Ua
9(lIz{
%曲率半径 vW]Frb
X5 lB],t"=
R1=2*f/(b1*b2) ,e+.Q#r*Y
R2=2*a1*f/(b2*(1+b1)) b0X*+q
R3=2*a1*a2*f/(1+b2) :Q2\3
/- z_"G
A1=b2^3*(a1-1)*(1+b1)^3; 8OH<ppi
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; T[a1S ?_*T
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; ?15k~1nA
$>v^%E;Y4
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); //@_`.
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); U y ^Hh4|
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2);
/ :"%m:-P
XOa<R
CB=[C1 B1;C2 B2]; Y?%MPaN:
AB=[A1 B1;A2 B2]; /'
L20aN2
AC=[A1 C1;A2 C2]; %_u*5,w
_tL+39 u
%二次系数 E#Ynn6
& =|W95
k2=-(det(CB)/det(AB)); ar+m j=m
k3=-(det(AC)/det(AB)); a$#, 'UB
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 95(c{
l/
k2=k2 deaxb8' 7
k3=k3 B;4hI?
]]o7e j
end
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