| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 +]*hzWbe
function sjr=nfdre(~) uupfL >h
xU(yc}vw,
%系统焦距及各镜间距输入，间距取负正负 *D:"I!Ho
5n#@,V.O/
f=input('f:'); iqAME%m
d1=input('d1:'); `U6bI`l
d2=input('d2:'); g- O}e4
d3=input('d3:'); J.g4I|{
i4g99Kvl
A=f^2/(d3*d2)-f/d1; ,Srj38p
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); JZom#A.
dt
C=d3/d2-f/d1; f{j.jf l\x
?]Wg{\NC6
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 q*pWx]Y
a2=d3/(a1*f);%α2 `ZLA=oD
b2=a1*(1-a2)*f/d2;%β2 :dM
eNM-
b1=(1-a1)*f/(d1*b2);%β1 ! Bqmw
3A)Ec/;~
JQde I+
%曲率半径 863PVce",}
OO /Pc
R1=2*f/(b1*b2) w}:&+B:
R2=2*a1*f/(b2*(1+b1)) meM61ue_2
R3=2*a1*a2*f/(1+b2) \NTN B9>CO
{klyVb
A1=b2^3*(a1-1)*(1+b1)^3; 9+"\7MHw
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; YjTA+1}
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; =3R5m>6!/
q#|,4 ( Z
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); Xb/^n .>
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); qFwJ%(IQ
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); RLL2'8"A
0X:
:<N@
CB=[C1 B1;C2 B2]; j ?gsc Q3
AB=[A1 B1;A2 B2];
k\wcj^"cb
AC=[A1 C1;A2 C2]; /4_^'RB
*j/[5J0'M
%非球面系数 |d0,54!
k2=-(det(CB)/det(AB)); l We1Q #
k3=-(det(AC)/det(AB)); +~] :oj
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 ~V?3A/]
k2=k2 :f|X$>
b
k3=k3 0{'% j~"
#5a'Z+
end { kF"<W
;~
, <8
%有中间像，焦距输入为正数 Ad'b{C%
n>[" h 2
function sjr=yfdre(~) 1-6[KBQ8
^V5g[XL2
f=input('f:'); @2 eV^eO9
d1=input('d1:'); o;\c$|TNU
d2=input('d2:'); IP
e"9xb
d3=input('d3:'); 9YjO
Xj+oV
A=f^2/(d3*d2)-f/d1; Ohe* m[
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); LnY`f -H
C=d3/d2-f/d1; wEp*j+Mmce
'<v_YxEn
a1=(-B-sqrt(B^2-4*A*C))/(2*A); ;;cP t44s
a2=d3/(a1*f); hD I}V 1)
b2=a1*(1-a2)*f/d2; K WzJ
b1=(1-a1)*f/(d1*b2); "2FI3M =
` x'vF#
%曲率半径 pS
C5$a(
,*} 5xpX
R1=2*f/(b1*b2) _8;)J
R2=2*a1*f/(b2*(1+b1)) $hM>%u
R3=2*a1*a2*f/(1+b2) hr)CxsPoRQ
gJv;{;%
A1=b2^3*(a1-1)*(1+b1)^3; | Vq&IfP
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; h~zG*B5F
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; |'bRVqJ
f} _d`?K
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); v7kR]HU[y
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); tq^d1b(j4
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); oy?>e1Sy*
`4N{x. N
CB=[C1 B1;C2 B2]; C" =^ (HU
AB=[A1 B1;A2 B2]; x22:@Ot6
AC=[A1 C1;A2 C2]; @T6 Z3Zj}
G d 08RW
%二次系数 FID4@--
>tFv&1iR
k2=-(det(CB)/det(AB)); ZKT~\l
k3=-(det(AC)/det(AB)); y?1<7>L5~
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 5W29oz} -S
k2=k2 aTx*6;-PH
k3=k3 qauZ-Qoc9
>.]' N:5
end
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