| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 duCXCX^n
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function sjr=nfdre(~) B4m34)EOE
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%系统焦距及各镜间距输入，间距取负正负 cauKG@:2F
mwz!7Q
f=input('f:'); -&v0JvTJ9j
d1=input('d1:'); $\20Vgu<
d2=input('d2:'); `V glE?M
d3=input('d3:'); = P$7
"
/>PH{ l
A=f^2/(d3*d2)-f/d1; ;1TQ r3w
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); "oR%0pU*
C=d3/d2-f/d1; 8<E U|/O
j zZEP4
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 [,z>msEB.
a2=d3/(a1*f);%α2 !|"LAr9u
b2=a1*(1-a2)*f/d2;%β2 [>Q zT"=
b1=(1-a1)*f/(d1*b2);%β1 8D^ iQ BA
b|@f!lA
v}^uN+a5
%曲率半径 UM+g8J{$*;
bD 1IY1
R1=2*f/(b1*b2) zj1_# =]
R2=2*a1*f/(b2*(1+b1)) +]C|y ,r
R3=2*a1*a2*f/(1+b2) :pP l|"
reoCyP\!!
A1=b2^3*(a1-1)*(1+b1)^3; !Jj Nm*F[
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; P2U [PO
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; -li;w
tCS
3.?oG5 P#
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); Hegj_FQ
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 6a{b% e`
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2);
JU=4 v!0
{r?Ly1 5
CB=[C1 B1;C2 B2]; emS 7q|^
AB=[A1 B1;A2 B2]; >>h0(G|
AC=[A1 C1;A2 C2]; ,L(q/#p
G`u";w_
%非球面系数 z }P1+Pm
k2=-(det(CB)/det(AB)); ~ \7peH%
k3=-(det(AC)/det(AB)); }/%^;@q ;
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Gii1|pLZ1
k2=k2 {'f=*vMI
k3=k3 FWpb5jc)3
qI1J M =
end ;J?zD9
It Q3|-^
%有中间像，焦距输入为正数 p=f8A 71
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function sjr=yfdre(~) *Cx3bg*Gan
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f=input('f:'); )^Md ^\?
d1=input('d1:'); f9 b[0L
d2=input('d2:'); Hl*/s
d3=input('d3:'); zT _[pa)O`
!}&f2!?.W
A=f^2/(d3*d2)-f/d1; um
mkAeWb
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); |z.Z= '`
C=d3/d2-f/d1; uJt*> ;Kp
"]1|%j
a1=(-B-sqrt(B^2-4*A*C))/(2*A); VrZ6 m
a2=d3/(a1*f); ]1i1 _AR'`
b2=a1*(1-a2)*f/d2; vs Cy?
b1=(1-a1)*f/(d1*b2); 3 *[YM7y
<a$'tw-8
%曲率半径 +Zi@+|"BCN
~HyqHx y
R1=2*f/(b1*b2) WH 0$v#8`v
R2=2*a1*f/(b2*(1+b1)) FTZ a N1%`
R3=2*a1*a2*f/(1+b2) Eza B}BLQ9
vKcc | #
A1=b2^3*(a1-1)*(1+b1)^3; oi/bp #(fa
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; H7R6Ljd?&S
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; orr6._xw
5R"(4a P
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); OLgW .j:Ag
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 4l"oq"uc
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); tGh!5EZ6`
'/ H+
CB=[C1 B1;C2 B2]; I?IAZa)
AB=[A1 B1;A2 B2]; `F
TA{ba
AC=[A1 C1;A2 C2]; Y A4;gH +
Umt?COc
%二次系数 t"L- 9kCM
'"<h;|
k2=-(det(CB)/det(AB)); j?cE0
hz
k3=-(det(AC)/det(AB)); v6_f F5N/
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 IA?v[xu
k2=k2 _^" 0"< ,
k3=k3 I2<t?c:Pn<
9 54O=9PQ
end
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