| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 o(3OCh H
function sjr=nfdre(~) f|s,%AU"i
OH
88d:
%系统焦距及各镜间距输入，间距取负正负 @_WZZ
DC$> 5FDv
f=input('f:'); $Nj'_G\}
d1=input('d1:'); 5g9K| -
d2=input('d2:'); &oK&vgcj
d3=input('d3:'); Ac
+fL
sN 1I+X
A=f^2/(d3*d2)-f/d1; Ipow
Jw^
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); .^rs VNG
C=d3/d2-f/d1; r6 pz(rCs}
N{!@M_C^%R
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 @_;vE(!5
a2=d3/(a1*f);%α2 OF! n}.O(
b2=a1*(1-a2)*f/d2;%β2 kH62#[J)yM
b1=(1-a1)*f/(d1*b2);%β1 >l O]/3j1
?V)M!
yfA h=
%曲率半径 U
owbk:
;|Rrtf 9
R1=2*f/(b1*b2) "j}fcrlG9
R2=2*a1*f/(b2*(1+b1)) Reg%ah|$/=
R3=2*a1*a2*f/(1+b2) wF['oUwHH
l 9NET
A1=b2^3*(a1-1)*(1+b1)^3; } _?FmuU
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; "Za 'K+4
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; Mr S~u
59a7%w
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); {,o =K4CD
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); t^<ki?*
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); {UOR_Vt!*
|-vn,zpe
CB=[C1 B1;C2 B2]; e5m-7{h@
AB=[A1 B1;A2 B2]; 6vZ.CUK9
AC=[A1 C1;A2 C2]; *JY 2vq
koOp:7 r
%非球面系数 VrZ6 m
k2=-(det(CB)/det(AB)); ?h|w7/9
k3=-(det(AC)/det(AB)); =:7OS>x
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 soB5sFt&]
k2=k2 |),3 `*N
k3=k3 %0^taA
# F|w_P
end D7(kkr:r
W{*w<a_ `
%有中间像，焦距输入为正数 pe7R1{2Q_s
tGh!5EZ6`
function sjr=yfdre(~) |a[Id
q.g0Oz@ z
f=input('f:'); [(4s\c
d1=input('d1:'); N\WEp?%~
d2=input('d2:'); v6_f F5N/
d3=input('d3:'); k_%"#
x $
oId{;
A=f^2/(d3*d2)-f/d1; ( }NK W
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); Z4'8x h)-
C=d3/d2-f/d1; $bT<8:g
N T<> LWo
a1=(-B-sqrt(B^2-4*A*C))/(2*A); lZ` CFZR0
a2=d3/(a1*f); VOK0)O>&
b2=a1*(1-a2)*f/d2; {E+ o+2L
b1=(1-a1)*f/(d1*b2); gx)!0n;
vfZ.js/
%曲率半径 .gK>O2hI
op]HF4
R1=2*f/(b1*b2) @z! |HLD+
R2=2*a1*f/(b2*(1+b1)) Y
&"rf
R3=2*a1*a2*f/(1+b2) ic_q< Y}
^dF?MQA<@
A1=b2^3*(a1-1)*(1+b1)^3; Pa-p9]gq
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; [Q5>4WY
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; v0}R]h~>\H
2!+saf^-,
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ClvqI"Rd
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ;m[-yqX
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); CtO `t5
!C$bO hc
CB=[C1 B1;C2 B2]; >w~ Hq9
AB=[A1 B1;A2 B2]; wNX2*
AC=[A1 C1;A2 C2]; U)n+j}vi
GYq.!d@O
%二次系数 I#m0 n%-[
g]hTz)8fF
k2=-(det(CB)/det(AB)); ]N\J~Gm
k3=-(det(AC)/det(AB)); &r)i6{w81
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 OcBK n=8
k2=k2 5w#
Ceg9
k3=k3 <E TR6r
;ORT#7CU
end
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