| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 EZ .3Z`
function sjr=nfdre(~) Dho6N]86r
/m"/#; ^l
%系统焦距及各镜间距输入，间距取负正负 lJ-PW\ P
B F<u3p??
f=input('f:'); |A 'I!Jm
d1=input('d1:'); WM
?a1j
d2=input('d2:'); E|f[ #+:+
d3=input('d3:'); &;d
N: F;
{:u v}4 Z
A=f^2/(d3*d2)-f/d1; |}
b+$J
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); j0 mN4Ny
C=d3/d2-f/d1; 9m$;C '}Z
dJ6fPB|k
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 >[|N%9\
a2=d3/(a1*f);%α2
Ptba C6"\
b2=a1*(1-a2)*f/d2;%β2 l(sVnhL6h
b1=(1-a1)*f/(d1*b2);%β1 ALTOi?
(~^fx\-S
dn-
[Gnde
%曲率半径 ( 4L/I
Y)X7*iTi'j
R1=2*f/(b1*b2) pVy =rS-
R2=2*a1*f/(b2*(1+b1)) &[-(=43@
R3=2*a1*a2*f/(1+b2) +`Z1L\gmA
oM~y8O
A1=b2^3*(a1-1)*(1+b1)^3; =9a2+ v0
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; wL?Up>fr
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; ja_8n["z
MMFw T(l<1
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); YK3>M"58
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ?ZRF]\dP]
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); +r8bGS]ki
b]4dm c*N+
CB=[C1 B1;C2 B2]; !lgL=Ys(
AB=[A1 B1;A2 B2]; JkAM: ,^(
AC=[A1 C1;A2 C2]; K 4!-%d$
U8Y% rFh1
%非球面系数 luf5-XT
k2=-(det(CB)/det(AB)); /]TNEU,K
k3=-(det(AC)/det(AB)); h4p S~/
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 c
3QgX4vq
k2=k2 J;0;oXwJ<
k3=k3 CjQO 5
x"12$ 7 9=
end `Y?VQ~ci>
>q:%?mi
%有中间像，焦距输入为正数 N*-tBz
)r9 9zdUk
function sjr=yfdre(~) JnBUW"
nHm}^.B*+
f=input('f:'); ,5n!a.T
d1=input('d1:'); lhN@ ,q
d2=input('d2:'); ;?2)[a
d3=input('d3:'); 6ZQ |L=Ytp
uDDa >Ka#+
A=f^2/(d3*d2)-f/d1; Y_'ERqQ
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); + F T c/r
C=d3/d2-f/d1; Y P2VSK2Q
lYx _8x2
a1=(-B-sqrt(B^2-4*A*C))/(2*A); 03 @a G
a2=d3/(a1*f); `> : 5[Y
b2=a1*(1-a2)*f/d2; A>@#eyB
b1=(1-a1)*f/(d1*b2); y7,fFUKl
x o"GNFh!
%曲率半径 aDbq h~7
)O1 ]|r7v
R1=2*f/(b1*b2) A5XMA|2_
R2=2*a1*f/(b2*(1+b1)) 7Aqg X0)
R3=2*a1*a2*f/(1+b2) x>#{C,Fi
a('0l2e<u9
A1=b2^3*(a1-1)*(1+b1)^3; r<`:Q]
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; =A"Abmx|
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 4era5=
5p0~A N)
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); KUI{Z I
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); m!V,W*RNr
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); <XdnVe1
,-pE/3|(
CB=[C1 B1;C2 B2]; Mg2+H+C~:
AB=[A1 B1;A2 B2]; |p|Zv H
AC=[A1 C1;A2 C2]; 8 1,N92T5
G ]K1X"W?
%二次系数 nQF& ^1n
9z7_D_yN2
k2=-(det(CB)/det(AB)); i GW|j>N
k3=-(det(AC)/det(AB)); c+:Zm rP/
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 Ebnb-Lze,
k2=k2 k%.v`H!
k3=k3 n2U
&}O
1b5Z^a<u
end
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