| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 .$@+ / @4
function sjr=nfdre(~) v7 n@CWnN
2RQ- L
%系统焦距及各镜间距输入，间距取负正负 PMUW< UI
P ^ 4 @
f=input('f:'); Z? xRSi2~7
d1=input('d1:'); 0` .5gxm
d2=input('d2:'); $,y AOaa
d3=input('d3:'); AmC?qoEWQ7
sn"z'=ch
A=f^2/(d3*d2)-f/d1; f7y.##W G
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); K`2 (Q
C=d3/d2-f/d1; FgL892[
=r*Ykd;W|E
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 <z\ `Ma
a2=d3/(a1*f);%α2 Nte$cTjX
b2=a1*(1-a2)*f/d2;%β2 :AS`1\ C
b1=(1-a1)*f/(d1*b2);%β1 n}I?.r@e
aCI3Tx&2qT
{`G d
%曲率半径 =J4|"z:
0EF~Ouef
R1=2*f/(b1*b2) >
K?OsvX
R2=2*a1*f/(b2*(1+b1)) 8x g^="OJ
R3=2*a1*a2*f/(1+b2) vFB^h1k~.M
9!
/kyyU
A1=b2^3*(a1-1)*(1+b1)^3; M(zZ8#
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 9 h?'zyX
B
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; #-@u Lc
eIfQ
TV
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); ;0Pv49q
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); !nCq8~#
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); -sfv"?
U(9_&sL
CB=[C1 B1;C2 B2]; P6 R_W
AB=[A1 B1;A2 B2]; ,|B-Nq
AC=[A1 C1;A2 C2]; S
YDE`-
c~?Zmdn:
%非球面系数 q;")
k2=-(det(CB)/det(AB)); (Xcy/QT
k3=-(det(AC)/det(AB)); &'x~<rx
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 kJp~'\b
k2=k2 l6&\~Z(
k3=k3 c%J6!\
?UZt3 0|1
end \1Xk[%
!~Uj 'w
%有中间像，焦距输入为正数 M{Z
;7n'
_BmObXOp.
function sjr=yfdre(~) lU%}_!tp3/
pX
^^ 0
f=input('f:'); 6e B;
d1=input('d1:'); `om+p ?j
d2=input('d2:'); C=/B\G/.9
d3=input('d3:'); X S [L-NHG
P}Kgh7)3
A=f^2/(d3*d2)-f/d1; Z n'tNt/
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); sfj+-se(K.
C=d3/d2-f/d1; ods Fgh
:Ko6.|
a1=(-B-sqrt(B^2-4*A*C))/(2*A); "(^XZAU#W
a2=d3/(a1*f); "|L" C+tE
b2=a1*(1-a2)*f/d2; A913*O: \
b1=(1-a1)*f/(d1*b2); ^,acU\}VqP
&(rWl`eTY`
%曲率半径 ^ RA'E@ "
b.&W W
R1=2*f/(b1*b2) l9I r@.m
R2=2*a1*f/(b2*(1+b1)) 6!ve6ZB[p
R3=2*a1*a2*f/(1+b2) pn
gto
/Hyz]46
A1=b2^3*(a1-1)*(1+b1)^3; Sw\ *$g]
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; {`QHg O
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; K>@yk9)vi
\ ;npdFy
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); //U1mDFT
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); aa`(2%(:
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); " B#|C'
hfaU-IPcFX
CB=[C1 B1;C2 B2]; hj [77EEz
AB=[A1 B1;A2 B2]; 6lSz/V;
AC=[A1 C1;A2 C2]; wZiUzS ;v
;Y$>WKsV
%二次系数 xc:E>-
O?JJE8~']
k2=-(det(CB)/det(AB)); , 50
k3=-(det(AC)/det(AB)); $*fJKR_N
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 _rT\?//B
k2=k2 ~&i4 FuK
k3=k3 ;*<tU
n^t
T{k
P9
4
end
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