| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 V;VHv=9`o
function sjr=nfdre(~) ^] Y> [[
@}u*|P*
%系统焦距及各镜间距输入，间距取负正负 D(op)]8
x
M/+L:_<
f=input('f:'); /|m2WxK)
d1=input('d1:'); {_"<1C
d2=input('d2:'); sjHE/qmq-Z
d3=input('d3:'); q CC.^8
wYXQlxd y
A=f^2/(d3*d2)-f/d1; 5J.bD)yrP
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); IVnHf_PzF
C=d3/d2-f/d1;
IZ-1c1
BQHVQs
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 M mj;-u
a2=d3/(a1*f);%α2 Xh"n]TK
b2=a1*(1-a2)*f/d2;%β2
!RS}NS
b1=(1-a1)*f/(d1*b2);%β1 8}x:`vDK
J$DE"| -
|-67 \p]
%曲率半径 #pow ub
9Q^r
O26+
R1=2*f/(b1*b2) B2vh-%6 3
R2=2*a1*f/(b2*(1+b1)) Z9ZPr?C=
R3=2*a1*a2*f/(1+b2) \ A#41
a 7 V-C
A1=b2^3*(a1-1)*(1+b1)^3; :K,i\
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; ; u
({\K
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 8U"v6S~A%Q
H [\o RId
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); :gi bfk]C
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); q-2Bt,Y
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); ? pmHFlx
(_]~wi-,
CB=[C1 B1;C2 B2]; N0Lw }@p
AB=[A1 B1;A2 B2]; {*" |#6-
AC=[A1 C1;A2 C2]; ibk6|pp
13=AW
%非球面系数 *I.f1lz%*
k2=-(det(CB)/det(AB)); %3 -y[f
k3=-(det(AC)/det(AB)); .f2bNnB~pP
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 qS$Ox?Bw#u
k2=k2 )F>#*P
k3=k3 > uB# &Q
z'n:@E
end I-*S&SiXjI
%p=M;
%有中间像，焦距输入为正数 '[:D$q;
D2 eckLT
function sjr=yfdre(~) xGg )Y#
_S1>j7RQo
f=input('f:'); 5coyr`7mP
d1=input('d1:'); Y eo]]i{
d2=input('d2:'); %s|Ely)
d3=input('d3:'); \'D0'\:vz
*Kg ks 4
A=f^2/(d3*d2)-f/d1; Rtl"Ub@HV
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); b5vC'B-!
C=d3/d2-f/d1; Qn.om=KDs@
sI GMA$EK
a1=(-B-sqrt(B^2-4*A*C))/(2*A); ,m:.-iy?
a2=d3/(a1*f); a~}OZ&PG
b2=a1*(1-a2)*f/d2; `?_Q5lp/s
b1=(1-a1)*f/(d1*b2); h(_57O:
d.d/<
%曲率半径 E
A1?)|}n
NP3 y+s
R1=2*f/(b1*b2) l'. VKh\C
R2=2*a1*f/(b2*(1+b1)) }rw8PZ9
R3=2*a1*a2*f/(1+b2) WlC:l
u0c1:Uv#~e
A1=b2^3*(a1-1)*(1+b1)^3; 3$>1FoSk
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; m@v \(rT.
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; ~KX/
Ai
7*A],:-q
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); u?(d gJ
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ~Otoqu|
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); :>f )g
{q J1ko)$
CB=[C1 B1;C2 B2]; 37.S\ gO]
AB=[A1 B1;A2 B2]; F_{Y o?_
AC=[A1 C1;A2 C2]; oQVgyj.
qWPkT$ u
%二次系数 s8t;.^1}
CxW >~O:
k2=-(det(CB)/det(AB)); j-}O0~Jz
k3=-(det(AC)/det(AB)); 7# Kn8s
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 [<yaXQxl
k2=k2 fxHH;hRfv
k3=k3 `e&Suyf4B
@:vwb\azVD
end
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