| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 97Qng*i
function sjr=nfdre(~) (K+TqJw
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%系统焦距及各镜间距输入，间距取负正负 R6Cm:4m}I
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f=input('f:'); #?i#q%q
d1=input('d1:'); 8P!dk5 ,,O
d2=input('d2:'); MOG[cp
d3=input('d3:'); morI'6N
D.<CkD B
A=f^2/(d3*d2)-f/d1; 0{Kl5>Z9M
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); dTaR 8i
C=d3/d2-f/d1; 7`tnoTUv
-i'T!Qg1
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 ZjEO$ ts=@
a2=d3/(a1*f);%α2 BQB O]<99
b2=a1*(1-a2)*f/d2;%β2 fT8Id\6js
b1=(1-a1)*f/(d1*b2);%β1 IO xj$ ?%l
c`X'Q)c&K
fwAN9zs
%曲率半径 %i%Xi+{3
J6 [x(T
R1=2*f/(b1*b2) ja7Z v[
R2=2*a1*f/(b2*(1+b1)) 0 \ LkJ*i
R3=2*a1*a2*f/(1+b2) >Fld7;L?<
7 Nwi \#o
A1=b2^3*(a1-1)*(1+b1)^3; >W'SG3Hmc
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; 9v
cUo?/
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; \Zf&&7v
u."fJ2}l0X
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); Z{p6Q 1u
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); B@ zJ\Ir[
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); SC2C%.%l`
N`Bt|#R
CB=[C1 B1;C2 B2]; "}SER C7
AB=[A1 B1;A2 B2]; v[a#>!; s
AC=[A1 C1;A2 C2]; <YeF?$S}
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%非球面系数 N@Mea O
k2=-(det(CB)/det(AB)); pXFNK " jm
k3=-(det(AC)/det(AB));
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k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 FOk @W&
k2=k2 k) v[/#I
k3=k3 )i_FU~ LRq
5h:SH]tn8]
end jm-0]ugY&`
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%有中间像，焦距输入为正数 }uHc7gTBF7
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function sjr=yfdre(~) ZHC sv]l
k@8#By l|
f=input('f:'); 3yKI2en "
d1=input('d1:'); k9Sqp :l,
d2=input('d2:'); (J$ A
d3=input('d3:'); "}OFwes
|~HlNUPR
A=f^2/(d3*d2)-f/d1; xu:m~8%
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); ;n;^f&;sJ
C=d3/d2-f/d1; 68 HX,t
f]'@Vt>
a1=(-B-sqrt(B^2-4*A*C))/(2*A); 9wq%Fnt
a2=d3/(a1*f); /5x `TT
b2=a1*(1-a2)*f/d2; KFZ[gqW8YY
b1=(1-a1)*f/(d1*b2); xapkhIW2\
@zJ I0_Bp
%曲率半径 H~ZSw7!M8
sRZ :9de+
R1=2*f/(b1*b2) 4 iLU "~
R2=2*a1*f/(b2*(1+b1)) M)J *Df0@
R3=2*a1*a2*f/(1+b2) W1@;94Sb~
sd[QtK^
A1=b2^3*(a1-1)*(1+b1)^3; wFJK !9KA8
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; Dz50,*}J
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; gNqV>p
w//w$}v
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); P+b^;+\1s
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); llleo8
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); 4w
z
6%
*SY4lqN
CB=[C1 B1;C2 B2]; 'u3+k.
AB=[A1 B1;A2 B2]; vv0zUvmT
AC=[A1 C1;A2 C2]; W vJ?e
+E [b Lz^
%二次系数 $0*47+f
O5{XT]:
k2=-(det(CB)/det(AB)); s =5H.q%PV
k3=-(det(AC)/det(AB)); iTt=aQjd
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 |f:d72 {Qr
k2=k2 W<LaR,7
k3=k3 _Y|kX2l
S@
@
RI^w Z-;
end
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