| songshaoman |
2020-05-25 15:25 |
在框架结构确定的情况下，基于matlab的消四种像差的三反系统初始结构的求解
%无中间像，焦距输入为负数 QTrlQH &p
function sjr=nfdre(~) ,&z j Oc_v
[EW$7 se ~
%系统焦距及各镜间距输入，间距取负正负 Tvksf!ba
1b
%T_a
f=input('f:'); &?5{z\;1"
d1=input('d1:'); }
K hq
d2=input('d2:'); S,)|~#5x
d3=input('d3:'); Ok~W@sYST
jmk*z(}#:
A=f^2/(d3*d2)-f/d1; fa*H cz
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); 9 z8<[>
C=d3/d2-f/d1; a|6x!p2X
$ <>EwW
a1=(-B+sqrt(B^2-4*A*C))/(2*A);%α1 DS,FVh".|
a2=d3/(a1*f);%α2
6Qzu-
b2=a1*(1-a2)*f/d2;%β2 +DbWMm
b1=(1-a1)*f/(d1*b2);%β1 5M\=+5wB
h^ecn-PC
_w5~/PbWt
%曲率半径 EV ?47\ ~
VM V]TPks>
R1=2*f/(b1*b2) BJ.8OU*9]S
R2=2*a1*f/(b2*(1+b1)) ]zwqG A
R3=2*a1*a2*f/(1+b2) u6S0t?Udap
$b i_i|?
A1=b2^3*(a1-1)*(1+b1)^3; 2dd:5L,
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; _{Q ?VQvZ
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; ,w b|?>Y
v(Zi;?c
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); yzM+28}L<I
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); ?od}~G4s#
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); DP6{HR$L
g0:4zeL
CB=[C1 B1;C2 B2]; !qw=I(
AB=[A1 B1;A2 B2]; ch,Zk )y:_
AC=[A1 C1;A2 C2]; : ! iPn%
?lwQne8/
%非球面系数 EDidg "0p
k2=-(det(CB)/det(AB)); kFIB lP V
k3=-(det(AC)/det(AB)); QY\wQj wuW
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 j'40>Ct=i
k2=k2 C"Y]W-Mgg
k3=k3 %}ApO{
]20 "la5
end /E4 }d =5L
]-5jgz"
%有中间像，焦距输入为正数 Ualq>J5-m-
T;[c<gc/
function sjr=yfdre(~) e9_O /i N
lKhh= Pc2
f=input('f:'); ~j&:)a'^
d1=input('d1:'); \Af|$9boHz
d2=input('d2:'); ,fG_'3wb
d3=input('d3:'); cV_IG}LJ
=E~5&W7
A=f^2/(d3*d2)-f/d1; ?5YmE(v7
B=f/d1-f/d2+f/d1+f/d3-d3*f/(d3*d2); U1 HD ~
C=d3/d2-f/d1; :k )<1ua
F3 l^^ Mc
a1=(-B-sqrt(B^2-4*A*C))/(2*A); j]l}K*8(
a2=d3/(a1*f); PUZXmnB
b2=a1*(1-a2)*f/d2; \;:@=9`
b1=(1-a1)*f/(d1*b2); Is6']bYh
aq,)6P`
%曲率半径 u r.T YKF
]vkHU6d
R1=2*f/(b1*b2) )4_6\VaM
R2=2*a1*f/(b2*(1+b1)) A {Htpm ~
R3=2*a1*a2*f/(1+b2) '/Cz{<,
1gy}E=noP
A1=b2^3*(a1-1)*(1+b1)^3; AW&s-b%P
B1=-(a2*(a1-1)+b1*(1-a2))*(1+b2)^3; y3[)zv
C1=(a1-1)*b2^3*(1+b1)*(1-b1)^2-(a2*(a1-1)+b1*(1-a2))*(1+b2)*(1-b2)^2-2*b1*b2; 9PGR#!!F$
- QI`npsnV
A2=b2*(a1-1)^2*(1+b1)^3/(4*a1*b1^2); V1 #aDfiW
B2=-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)^3/(4*a1*a2*b1^2*b2^2); 6ym)F!t8l
C2=b2*(a1-1)^2*(1+b1)*(1-b1)^2/(4*a1*b1^2)-(a2*(a1-1)+b1*(1-a2))^2*(1+b2)*(1-b2)^2/(4*a1*a2*b1^2*b2^2)-b2*(a1-1)*(1-b1)*(1+b1)/(a1*b1)-(a2*(a1-1)+b1*(1-a2))*(1-b2)*(1+b2)/(a1*a2*b1*b2)-b1*b2+b2*(1+b1)/a1-(1+b2)/(a1*a2); d<'Yt|zt
*n_4R r
CB=[C1 B1;C2 B2]; f uN XY-;
AB=[A1 B1;A2 B2]; rHBjR_L.2
AC=[A1 C1;A2 C2]; 27 TZ+?
Bpo68%dx89
%二次系数 TIh zMW\/K
z slEUTj)
k2=-(det(CB)/det(AB)); wBHDof
xX
k3=-(det(AC)/det(AB)); ZpctsC z]
k1=(k2*a1*b2^3*(1+b1)^3-k3*a1*a2*(1+b2)^3+a1*b2^3*(1+b1)*(1-b1)^2-a1*a2*(1+b2)*(1-b2)^2)/(b1^3*b2^3)-1 *#^1rKGWK
k2=k2 OHnjI> /
k3=k3 ]bE?n.NwZ
7c]Ai
end
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